Organic III: Aromatic Chemistry Flashcards

1
Q

What was kekule’s model?

A
  • benzene was made up of a planar ring of carbon atoms with alternating single and double bonds
    -each C atom bonded to 1 hydrogen
    Also added that benzene was constantly flipping between 2 isomers by switching double/single bonds
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2
Q

Evidence against kekule’s model?

A

X ray diffraction studies have shown all carbon-carbon bonds in benzene are the same length - in between length of single and double bond

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3
Q

What is the delocalised model for benzene?

A

Each carbon atom in the ring forms three σ bonds (with hydrogen and adjacent carbon atoms)
- bonds form due to overlap of their atomic orbitals

  • remaining p orbital on each C atom overlaps sideways with p orbitals of neighbouring C atoms above and below plane—> delocalised ring of π bonds
  • leads to electrons being delocalised causing a π system - 2 ring shaped clouds of electron density ABOVE AND BELOW plane
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4
Q

Evidence of delocalisation?

A

Enthalpy change of hydrogenation data :

Hydrogenation of cyclohexene : each molecule has 1 c=c bond (enthalpy change = -120 kJ/mol)
Hydrogenation of benzene:
- Kekule structure of benzene as cyclohexa-1,3,5-triene has three double C=C bonds so predicted enthalpy change = - 360kJ/mol (3x cyclohexene as 3 double bonds)
But it was actually -208 kJ/mol

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5
Q

Why is benzene resistance to bromination compared to alkenes?

A

It is an Electrophilic Addition reaction
- involve breaking up delocalised system

Also, in benzene, attraction of electrophiles is reduced compared to in alkenes due to - charge being spread out (ELECTRONS ARE DELOCALISED) - less electron density

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6
Q

Combustion of benzene ?

A

2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (g)
- smoky flame due to too little O2 available to burn benzene completely - incomplete combustion
So carbon forms soot - Smoky flame

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7
Q

Halogenation of benzene ? overall conditions and reaction?

A

Conditions : metal halide carrier - iron bromide /aluminium chloride (CATALYST)

Overall :
C6H6 + Br2 → C6H5Br + HBr
Halogen atom substituted in place of H atom - eg of electrophilic substitution

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8
Q

Purpose of metal halide carrier?

A
  • make stronger electrophiles
    Halogen carrier accepts lone pair of electrons from halogen atom on electrophile
    -as lone pair of electrons pulled away, polarisation in Molecule increases + carbocation sometimes forms — STRONGER ELECTROPHILE
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9
Q

Nitration of benzene ? Conditions , overall reaction?

A

Nitro (-NO2) group replaces hydrogen atom on Arene - form NITROBENZENE

CONDITIONS :
- use conc nitric acid (HNO3)
- conc sulfuric acid (H2SO4) catalyst
- temp <55 degrees for mononitration

Benzene + HNO3 —> nitrobenzene + H2O

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10
Q

How does sulfuric acid help make nitronium ion (NO2+) electrophile and how is catalyst reformed?

A

HNO3 + H2SO4 —> H2NO3+ + HSO4-
H2NO3 + —> NO2+ + H20

Reforming catalyst:
HSO4 - + H+ —> H2SO4

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11
Q

Conditions and reaction of Friedel-Crafts Alkylation

A

Conditions : chloroalkane in presence of anhydrous aluminium chloride catalyst
- heat under reflux

Reaction :
C6H6 + chloroalkane (R-Cl) —> C6H5R + HCl
R= alkyl group
Electrophile is R+

FORMS ALKYLBENZENE

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12
Q

Conditions and reaction of Friedel crafts ACYLATION reaction of benzene?

A

C6H6 + RCOCl —> C6H5COR + HCl
R = alkyl group e.g -CH3

FORMS PHENYLKETONE (phenylethanone)
Electrophile is RCO+

Conditions: acyl chloride in presence of anhydrous aluminium chloride catalyst
Heat under reflux - 50 degrees

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13
Q

Forming electrophile and reforming catalyst for Halogenation?

A

Formation of electrophile :
AlCl3 + Cl2 —> Cl+ + AlCl4- (Cl+ is electrophile)
FeBr3 + Br2 —> FeBr4- + Br+ (Br+ is electrophile)

Reforming catalyst:
AlCl4- + H+ —> AlCl3 + HCl (AlCl3 is catalyst)

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14
Q

Forming electrophile and reforming catalyst for alkylation ?

A

Forming electrophile : AlCl3 + CH3CH2Cl —> CH3CH2+ + AlCl4-

Reforming : H+ + AlCl4- —> AlCl3 + HCl

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15
Q

Forming electrophile for acylation and reforming catalyst?

A

Forming electrophile:
AlCl3 + CH3COCl —> CH3CO+ + AlCl4-

Reforming catalyst :
H+ + AlCl4- —> AlCl3 + HCl

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16
Q

Why do phenols react more readily with electrophiles compared to benzene?

A
  • one of the lone pairs of electrons on Oxygen atom in -OH group delocalises into delocalised benzene ring
  • increases electron density of benzene ring —> MORE SUSCEPTIBLE TO ELECTROPHILIC ATTACK

-OH group activates Benzene ring and directs electrophiles to 2,4,6 positions

17
Q

Bromination of phenol ?

A

Electrophilic substitution
Phenol + 3Br2 —> 2,4,6-tribromophenol + 3HBr

  • decolourises orange bromine solution to form WHITE PRECIPITATE (tribromonphenol)
18
Q

Compare Bromination of phenol and benzene ?

A

Phenol doesnt need FeBr3 catalyst - benzene does
Phenol undergoes multiple substitution , benzene only adds 1 Br
Both electrophilic sub

19
Q

If iodine bromide reacts with benzene in a electrophilic substitution which compound would be main product of reaction?

A

Iodobenzene as Br is more electronegative than iodine so the iodine atom will be the electrophile

20
Q

Hydrogenation of benzene , overall reaction and conditions?

A

Benzene + 3H2 —> cyclohexane (C6H12)

Conditions : NICKEL CATALYST at 200C + 30atm

21
Q

Phenol reaction with sodium metal and sodium hydroxide ?

A

Phenol + Na —> sodium phenoxide + 1/2 H2
Phenol + NaOH —> sodium phenoxide + H2O

  • sodium phenoxide is more soluble than phenol so will dissolve on addition of NaOH
22
Q

Why do phenols not react with sodium carbonate but carboxylic acids do?

A

Phenol is not a strong enough acid to react with it

23
Q

Importance of nitration, Friedel crafts reaction of benzene and importance of phenols ?

A

NITRATION: important in synthesising useful compounds - explosive manufacture (TNT)
FRIEDEL CRAFTS: important bc they introduce reactive functional group to benzene ring
PHENOLS: produce plastics,antiseptics,disinfectants, resins for paints