Organic - Halogenoalkanes Flashcards

1
Q

What are halogenalkanes?

A

Not many halogenalkanes occur naturally, but they are the basis of many synthetic compounds. Some examples of these are PVC (used to make drainpipes). Teflon (the non-stick coating on pans), and a number of anaesthetics and solvents. Halogenalkanes have an alkane skeleton with one or more halogen (fluorine, chlorine, bromine, or iodine) atoms in place of hydrogen atoms.

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2
Q

What is the general formula for halogenalkanes?

A

The general formula of a halogenalkane with a single halogen atom is CnH2n+1X where X is the halogen. This is often shortened to R-X.

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3
Q

How do you name halogenalkanes?

A
  • The prefixes fluoro-, chloro-, bromo-, and iodo- tell us which halogen is present.
  • Number are used, if needed, to show on which carbon the halogen is bonded.
  • The prefixed di-, tri-, tetra-, and so on, are used to show how many atoms of each halogen are present.
  • When a compound contains different halogens, they are listed in alphabetical order, NOT in the order of the number of the carbon atoms to which they are bonded.
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4
Q

What is the nature of the halogenalkane bond?

A

Halogenalkanes have a C-X bond. This bond is polar, C(delta)+X(delta)-, because halogens are more electronegative than carbon. This means electron density is drawn towards the halogen forming delta positive and delta negative regions. As you go down group 7, the bonds get less polar.

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5
Q

Describe the solubility properties of halogenalkanes.

A
  • The polar C(delta)+X(delta)- bonds are not polar enough to make the halogenalkanes soluble in water.
  • The main intermolecular forces of attraction are dipole-dipole attractions and van der Waal forces.
  • Halogenalkanes mix with hydrocarbons so they can be used as dry-cleaning fluids and to remove oily stains. (Oil is a mixture of hydrocarbons).
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6
Q

Describe the boiling point properties of halogenalkanes.

A

The boiling point depends on the number of carbon atoms and halogen atoms.

  • Boiling point increases with increased chain length.
  • Boiling point increases going down the halogen group (more electrons so stronger van der Waals forces).
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7
Q

How are the effects of the boiling point properties of haloalkanes caused?

A

Both effects are caused by increased van der Waals forces because the larger the molecules, the greater the number of electrons, and therefore the larger the van der Waals forces.

As in other homologous series, increased branching of the carbon chain will tend to lower the melting point.

Halogenalkanes have higher boiling points than alkanes with similar chain lengths because they have higher relative molecular masses and they are more polar.

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8
Q

What factors determine how readily the C-X bond reacts?

A

When halogenalkanes react, it is almost always the C-X bond that breaks. The two factors that determine how readily the C-X bond reacts are:

  • the C(delta)+X(delta)- bond polarity
  • the C-X bond enthalpy
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9
Q

How does bond polarity affect the reactivity of the haloalkanes?

A

The halogens are more electronegative than carbon, so the bond polarity will be C(delta)+X(delta)-. This means that the carbon bonded to the halogen has a partial positive charge - it is electron deficient. This means that it can be attacked by reagents that are electron rich or have electron-rich areas. These are called nucleophiles. A nucleophile is an electron pair donor.

The polarity of the C-X bond would predict that the C-F bond would be the most reactive. It is the most polar, so the C(delta)+ has the most positive charge and is therefore most easily attacked by a nucleophile.This argument would make the C-I bond least reactive because it is the least polar.

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10
Q

How does bond enthalpy affect the reactivity of the haloalkanes?

A

The C-X bond enthalpies get weaker going down the group. Fluorine is the smallest atom of the halogens and the shared electrons in the C-F bond are strongly attracted to the fluorine nucleus. This makes a strong bond. Going down the group, the shared electrons in the C-X bond gets further and further away from the halogen nucleus, so the bond becomes weaker.

The bond enthalpies would predict that iodo-compounds, with the weakest bonds, are the most reactive, and fluoro-compounds, with the strongest bonds, are the least reactive.

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11
Q

Which factor is most important in terms of affecting reactivity of haloalkanes?

A

Experiments confirm that reactivity increases going down the group. This means that bond enthalpy is a more important factor than bond polarity.

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12
Q

What are nucleophiles?

A

Nucleophiles are reagents that attack and form bonds with positively or partially positively charged carbon atoms. They donate a pair of electrons to form a covalent bond. Halogenalkanes are susceptible to attack by nucleophiles.

A nucleophile molecule is attracted to the positive nuclei (electron deficient areas), so they tend to be negatively charged. Molecules with lone pairs are also nucleophilic.

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13
Q

What are the features of a nucleophile?

A
  • A nucleophile is either a negatively charged ion or has an atom with a delta negative charge.
  • A nucleophile has a lone (unshared) pair of electrons which it can use to form a covalent bond.
  • The lone pair is situated on an electronegative atom.
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14
Q

Why are halogenalkanes susceptible to attack by nucleophiles?

A

Because the halogen atom is more electronegative than carbon atoms and so the carbon of the carbon-halogen bond is delta positive.

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15
Q

What is a nucleophile in organic chemistry?

A

In organic chemistry, a nucleophile is a species that has a lone pair of electrons with which it can form a bond by donating its electrons to an electron deficient carbon atom.

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16
Q

What are some common nucleophiles?

A
\:OH- = the hydroxide ion
\:CN- = the cyanide ion
\:NH3 = ammonia
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17
Q

What is a nucleophilic substitution?

A

In a nucleophilic substitution, the halogen atom is replaced by another atom/group (nucleophile). They all follow essentially the same reaction mechanism.

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18
Q

What is a reaction mechanism?

A

A reaction mechanism describes the route from reactants to products via a series of theoretical steps. These may involve short-lived intermediates.

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19
Q

What is the rate of reaction affected by?

A

The rate of reaction is partly affected by the strength of the carbon-halogen bond. The longer the bond, the weaker the bond, the more easily it breaks and the faster the reaction. Therefore, in terms of rate, C-I > C-Br > C-Cl > C-F. Fluoro-compounds are unreactive due to the strength of the C-F bond.

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20
Q

What do curly arrows indicate?

A

The movement of an electron pair in organic reactions. Curly arrows never move from an area of low electron density. Areas of high/low electron density are likely starting points for reactions.

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21
Q

What happens in a nucleophilic substitution reaction with aqueous sodium (or potassium) hydroxide?

A

The nucleophile is the hydroxide ion. In this reaction, the halogen atom is replaced by the OH group.

This reaction occurs very slowly at room temperature. To speed up the reaction, it is necessary to warm the mixture. The reaction occurs in aqueous conditions.

22
Q

What happens in a nucleophilic substitution reaction with aqueous potassium cyanide?

A

The nucleophile is the cyanide ion. When halogen alkanes are warmed with an aqueous alcoholic solution of potassium cyanide, nitriles are formed.

The product is called a nitrile. It has one extra carbon in the chain than the starting halogenalkane. It is often useful if you want to make product that has one carbon more than the starting material.

23
Q

What happens in a nucleophilic substitution reaction with ammonia?

A

The nucleophile is ammonia. The reaction of the halogen alkanes with an excess concentrated solution of ammonia dissolved in ethanol is carried out under pressure in a sealed container. The reaction produces an amine, RNH2.

24
Q

Why is ammonia a nucleophile?

A

Ammonia is a nucleophile because it has a lone pair of electrons that it can donate (although it has no negative charge) and the nitrogen atom has a beta-negative charge. Because ammonia is a neutral nucleophile, a proton, H+, must be lost to form the neutral product, called an amine. The H+ ion reacts with a second ammonia molecule to form an NH4+ ion.

25
Q

What are the uses of nucleophilic substitution?

A

Nucleophilic substitution reactions are useful because they are a way of introducing new functional groups into organic compounds. Halogenalkanes can be converted into alcohols, amines, and nitriles. These in turn can be converted to other functional groups.

26
Q

What is elimination?

A

Halogenalkanes typically react by nucleophilic substitution. But, under different conditions they react by elimination. A hydrogen halide is eliminated from the molecule (an adjacent carbon atom), leaving a double bond in its place so that an alkene is formed. A mixture of alkenes could be formed depending on which of the adjacent carbon atoms the hydrogen is lost from.

27
Q

Where does the OH- ion acts as a nucleophile and where does it act like a base?

A

The OH- ion, from aqueous sodium or potassium hydroxide, is a nucleophile and its lone pair will attack a halogenalkane at C delta positive to form an alcohol (substitution).

Under different conditions, the OH- ion can act as a base, removing an H+ ion from the halogenalkane. In this case it is an elimination reaction rather than a substitution.

28
Q

What conditions are needed for an elimination reaction?

A

Hot, ethanolic conditions with concentrated solution of base.

The sodium (or potassium) hydroxide is dissolved in ethanol and mixed with the halogenalkane. Changed from sodium to potassium to increase the solubility in ethanol. There is no water present. The mixture is heated.

The product is ethene. Ethene burns and also decolourises bromine solution, showing that it has a C=C bond.

29
Q

Describe the mechanism of elimination.

A
  • The OH- ion uses its lone pair to form a bond with one of the hydrogen atoms on the carbon next to the C-Br bond. These hydrogen atoms are very slightly delta positive.
  • The electron pair from the C-H bond now becomes part of a carbon-carbon double bond.
  • The bromine takes the pair of electrons in the C-Br bond and leaves as a bromide ion (the leaving group).

This reaction is a useful way of making molecules with carbon-carbon double bonds.

30
Q

What determines whether it’s a substitution or an elimination reaction?

A

Since the hydroxide ion will react with halogenalkanes as a nucleophile or as a base, there is competition between substitution and elimination. In general, a mixture of an alcohol and an alkene is produced.

The reaction that predominates depends on two factors - the reaction conditions (aqueous or ethanolic solution) and the type of halogenalkanes (primary, secondary, or tertiary).

31
Q

What are the conditions of the reaction that affect the type of reaction?

A
  • Hydroxide ions at room temperature, dissolved in water (aqueous), favour substitution.
  • Hydroxide ions at high temperature, dissolved in ethanol, favour elimination.
32
Q

What are the types of halogenalkanes that affect the type of reaction?

A

Primary halogenalkanes tend to react by substitution and tertiary ones by elimination. Secondary will do both.

33
Q

What elimination products are possible?

A

In some cases, a mixture of isomeric elimination products is possible.

34
Q

What are chlorofluorocarbons?

A

Chlorofluorocarbons are halogenalkanes containing both chlorine and fluorine atoms but no hydrogen.

35
Q

What are the features of chlorofluorocarbons?

A
  • They are also called CFCs.
  • They are very unreactive under normal conditions.
  • The short chain ones are gases and were used, for example, as aerosol propellants, refrigerants, and blowing agents for foams like expanded polystyrene.
  • Longer chains ones are used as dry cleaning and de-greasing solvents.
36
Q

What is the link between CFC gases and ozone depletion?

A

CFC gases eventually end up in the atmosphere where they decompose to give chlorine atoms. Chlorine atoms decompose ozone, O3, in the stratosphere, which has caused a hole in the earth’s ozone layer. Upper atmosphere research together with laboratory research showed how ozone is broken down. Politicians were influenced by scientists and, under international agreement, CFCs are being phased out and replaced by other, safer, compounds including hydrofluorocarbons, HCFCs. However, a vast reservoir of CFCs remains in the atmosphere and it will be many years before the ozone layer recovers.

37
Q

How does the Mr affect the bond enthalpy?

A

The greater the Mr of the halogen in the polar bond, the lower the bond enthalpy meaning it can be broken more easily. Therefore the rate of reaction for these halogenalkanes is faster.

38
Q

How do CFCs lead to ozone depletion?

A

Ozone in the atmosphere absorbs UV radiation. CFCs also absorb UV radiation (undergo photolysis), breaking down the carbon-halogen bonds to form free radicals that can catalyse ozone depletion.

39
Q

How is ozone depletion being minimised?

A

CFC-free solvents are now being produced to prevent them entering the atmosphere. This helps minimise ozone depletion and global warming.

40
Q

What is an electrophile?

A

An electrophile is a molecule that is attracted to a pair of electrons (electron dense areas). It accepts a pair of electrons to form a covalent bond. Electrons have negative charges, so electrophiles tend to be positively charged.

41
Q

What is the difference between nucleophiles and electrophiles?

A

Nucleophiles are attracted to positive charges. Electrophiles are attracted to negative charges.

42
Q

How can you promote elimination?

A
  • Use an ethanol solvent instead of water

- Heat the reaction under reflux conditions

43
Q

What is the side product of an elimination reaction?

A

Because the hydroxide acts as a base and removes a proton, a side product of the reaction is water.

44
Q

What are the properties of ozone?

A
  • O3 is much less stable than O2
  • O3 is formed from O2 and UV light
  • O3 is present in low concentrations
45
Q

What is the positively charged species called that is formed when ammonia reacts with halogenalkanes?

A

intermediate

46
Q

What conditions favour an elimination reaction?

A

For a given halogenoalkane, to favour elimination rather than substitution, use:

  • higher temperatures
  • a concentrated solution of sodium or potassium hydroxide
  • pure ethanol as the solvent
  • secondary/tertiarry
47
Q

What conditions favour a substitution reaction?

A

To favour substitution rather than elimination, use:

  • lower temperatures
  • more dilute solutions of sodium or potassium hydroxide
  • more water in the solvent mixture
  • secondary/primary
48
Q

What can be made when reacting sodium hydroxide with a halogenoalkane?

A
  1. alkene - high temperature, when using ethanol as a solvent
  2. alcohol - room temperature, when using water as a solvent
  3. both alkene and alcohol - when using a mixture of ethanol and water
49
Q

What are hydrofluorocarbons?

A

Alternatives to CFCs that are safer to use. We use HFCs and hydrocarbons as they don’t have chlorine in them.

50
Q

Why are hydrofluorocarbons safer to use?

A
  • have higher bond enthalpies so are less likely to break when released into the atmosphere
  • don’t contain chlorine so can’t produce chlorine free radicals