OG unit 1.3 Flashcards

1
Q

This may be our downfall, for such a teacher we were given it’s basically gon be solo yolo, but what is the purpose for teachers?

Bruh

A

You raise a good point!

he definitely raised a good point guys

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2
Q

For different isotopes (12C6, 13C6, 14C6), what would be the difference in terms of protons, neutrons and electrons?

A

Protons - stays the same (atomic number)
Neutrons - changes (probably cuz mix of protons & electrons type shi)
Electrons - stays the same (perhaps atomic number too?)

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3
Q

Formula for relative atomic mass?

75% Cl-35 and 25% Cl-37

A

% x atomic number / 100
also add em at the top

(75x35)+(25x37)/100
= 35.5

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4
Q

What’s a mass spectrometer?
(3 things)

A
  • An analytical technique
  • Used to identify different isotopes
  • And find overall relative atomic mass of an element
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5
Q

Explain step 1: Ionisation in mass spectrometry?
(5 things)

A
  1. A sample of an element is vapourised and injected
    - Into mass spectrometer
    - Where high voltage passed over chamber
    - Causes electrons to be removed from atoms (ionised)
    - Leaving 1+ charged ions in chamber
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6
Q

Explain step 2: Acceleration in mass spectrometry?
(2 things)

A
  1. Positively charged ions are accelerated towards
    - Negatively charged detection plate
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7
Q

Explain step 3: Ion drift in mass spectrometry?
(4 things)

A
  1. Ions deflected by magnetic field
    - Into a curved path
    - Radius of their path dependent on
    - Charge & mass of ion
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8
Q

Explain step 4: Detection in mass spectrometry?
(4 things)

A
  1. When positive ions hit negatively charged detection plate,
    - They gain an electron
    - Producing flow of charge
    - Greater current produced = greater abundance
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9
Q

Explain step 5: Analysis in mass spectrometry?
(4 things)

A
  1. Current values used in combination
    - With flight times to produce
    - Spectra print-out
    - With relative abundance of each isotope displayed
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10
Q

In mass spectrum, why do we see a half traced version of the ion?
(5 things)

A
  • During ionisation process, 2+ charged ion may be produced
  • Will be affected more by magnetic field
  • Producing curved path of a smaller radius
  • As a result, mass to charge ratio (m/z) is halved
  • Can be seen on spectra as a trace at half the expected m/z value
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11
Q

In mass spectrum:
What m/z?
What relative abundance?

> _>

A
  1. Mass to charge ratio
  2. Relative atomic mass?

icl i haven’t seen where u had to put a number for a certain bar so i reckon u don’t get fucked up by this one

I changed it lol

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12
Q

For mass spectra graph, how u gain mass for the 2 isotopes

A

Formula for mass of 2 isotopes:

1(relative abundance x m/z)+2(relative abundace x m/z)/ra1 + ra2

May seem a lil hard to remember but gl bro B)

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13
Q

How to gain empirical formula?

48.38% carbon, 8.12% hydrogen, rest is O2 (43.50%)

% = their mass

A

mass/mr = a number (mols?)
then divide that number with it (the smallest number u’ve gained)
double it if the number is not whole

48.38/12 = 4.03 divided by 2.72
8.12/1.01 = 8.02 divided by 2.72
43.5/16 = 2.72 divided by 2.72
(O has a 2, perhaps i should’ve done that 2 to gain real empirical formula)
2.72 is the smallest number

C = 1.5 x 2 = 3
H = 3 x 2 = 6
O = 1 x 2 = 2

C3H6O2

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14
Q

How to gain molecular formula?

CH has molar mass of 78.1g/mol

A

molar mass/mr empirical formula

CH = 12 + 1.01 = 13.01

78.1/13.01 = 6.00 = 6

C6H6

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15
Q

What are the 3 different formulas for moles ?

A

Solid - Mass/molar mass = n
Liquid - concentration x volume = n
Gas - volume/molar volume = n

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16
Q

How to gain mass of one molecule?

H2

A

Mr x number of atoms
then divide it by avogadro’s constant (6.02x10^23)

1.01 x 2 = 2.02 mr
2.02/6.02x10^23 = 3.36x10^-24

17
Q

How to gain number of molecules in a compound?

1.058 mole of H2O

A

n x avogadro’s constant

1.058 x (6.02x10^23) = 6.37x10^23

18
Q

How to gain moles from molar volume + volume?

120cm^3 of hydrogen at RTP (24.5 molar volume)

(the liquid type shi)

A

Volume (v) = number of moles (n) x molar volume (Vm)
(also divide volume into dm^3)
0.12/24.5 = 0.0049 or 4.89 x 10^-3

19
Q

How to understand mole ratio?

H2O + 2H2O

A
  1. Gain moles (so use n = m/M)
  2. The 2 on the second H2O is very important (lol)
    1:2 mole ratio
  3. So then that means mols for second H2O
    is double mols of first H2O

:v

20
Q

What is the ideal gas equation?

and what’s the 3 points to note?

A

pV = nRT

  1. Temp must be kelvin (0 degrees = 273K)
  2. Pressure must be in pascals (1atm = 101325 Pa)
  3. Volume must be m^3 (convert cm by dividing by 10^6)
21
Q

Define each symbol from ‘pV = nRT’

A

P = pressure (Pa)
V = volume (m^3)
n = number of moles (mols)
R = molar gas constant (8.31Jmol^-1 K-1)
T = temperature (K)

22
Q

What’s the simplified gas equation?
and when to use it?

A

P1V1/T1 = P2V2/T2
Only when the moles remain constant

23
Q

What equation if number of moles and volume remain constant?

(simplified gas equation)

A

P1/T1 = P2/T2

24
Q

What equation if number of moles and temperature remain constant?

(simplified gas equation)

A

P1V1 = P2V2

25
Q

What equation if number of moles and pressure remain constant?

(simplified gas equation)

A

V1/T1 = V2/T2

26
Q

How to gain concentration of a certain chemical present in a solution?

Conc. of NAOH solution when 4.0g of NaOH powder dissolved in 250cm^3 of distilled water? (in moldm^-3)

A

Know this:
n = cv
and rearrange for n =
c = n/v
and also know n = m/M

  1. Since it’s moldm^-3,
    - Convert 250cm^3 to dm^3
    = 250/1000 = 0.25dm^-3
  2. Gain mr of NaOH
    - 25 + 16 + 1.01 = 40.01
  3. Gain moles
    - 4/40.01 = 0.0999
  4. Divide Tingy n stuff
    - 0.0999/0.25 = 0.3996moldm^-3

(you are using both solid & liquid formulas)

27
Q

How to find concentration of chemicals with just their solubility?

Solubility of ammonium chloride , NH4Cl is 37.2g/100g water. What is the concentration in moldm^-3?

A

n = m/M
moles = mass/mr

  1. When u convert for dm^3, mass gotta be times by 10
    - 37.2 & 100cm^3
    = 372 & 1dm^3
  2. n = m/M with the NH4Cl
    - 372/(14 + 4.04 + 35.5)
    = 6.95 moldm^-3

Doesn’t make sense but just go with it man :(

28
Q

Wat percentage yield?

A

uhhh idk the info it no say, only for actual and theoretical
How effective a reaction is
But here’s the formula:

Percentage yield = (Actual yield/Theoretical yield) x 100

29
Q

2 reasons for how percentage yield may be below 100%?

A
  1. Not all reactants react
  2. Impurities in reactants
30
Q

The simplified formula for percentage yield?

A

(what you get/what you should get) x 100

31
Q

How would u get the theoretical yield specifically?

3.00g of ethanoic anhydride reacts with water to give ethanoic acid.
(CH3CO)2O + H2O –> 2CH3COOH

Calculate theoretical yield

A
  1. Mole ratio first
    - Gain mr for that specific compound (CH3CO)2O and then do mass/mr
    - It’s 1:2 so 0.03 x 2 = 0.06 mols (Look in book for more details)
  2. mass = mols x mr
    - 0.06 x 60.04 = 3.60g <– that’s the theoretical yield ig

(don’t include the 2 in front)

32
Q

How to really get the percentage yield?

When 18.0g of propan-1-ol (C3H8O) was reacted with excess acidified sodium dichromate, 7.20g of propanol (C3H6O) were obtained. Calculate percentage yield given the equation

3C3H8O + Na2Cr2O7 + 4H2SO4 –> 3C3H6O + Na2SO4 + 7H2O

A
  1. We got the masses for the propanols sooo we gain mr first for both
    - 3C3H8O =
    36 + 8.08 + 16 = 60.08
    - 3C3H6O =
    36 + 6.06 + 16 = 58.06
    (DON’T INCLUDE THE NUMBERS INFRONT OF EM)
  2. Do mass/mr = mols
    - 18/60.08 = 0.29
    - 7.20/58.06 = 0.12
  3. The real percentage yield (actual/theoretical) x 100
    - 0.12/0.29 x 100 = 41.4%
33
Q

What 2 things atom economy check?

A
  1. How much of the reactants are turned into desirable products
  2. And how much is waste product
34
Q

Formula for atom economy?

A

(molecular mass of desired product/sum of molecular masses of all products) x 100

35
Q

How to calculate atom economy for this one?

CH3CH2OH + HBr –> CH3CH2Br + H2O
The desired product is bromoethane

A
  1. Gain mr of CH3CH2Br (that’s bromoethane)
    - 24 + 5.05 + 79.9 = 108.95
  2. Add mr of bromoethane with water
    - mr of H2O = 2.02 + 16 = 18.02
    - 108.95 + 180.02 = 126.97
  3. (Mr of bromoethane/Mr of resultant products altogether) x 100
    - (108.95/126.97) x 100 = 85.8%
36
Q

Look at the last question of atom economy in the book cuz it has both atom economy and percentage yield soooo ye

How do u comment on atom economy and percentage yield??

A

Ohhhhh kayyyyyyy.

Atom economy
- High % = Efficient reaction
- Low % = Not efficient at all, high waste products, not sustainable

Percentage yield
- High % = Effective reaction
- Low % = Not an effective reaction, impurities probably present

37
Q

We just keep continuing. Also questions are good for answering so ye idk do something, am currently sick rn

Sick of you losing

A

¬.¬

> :|

38
Q

How to do percentage errors?
(mass and time are the same,
volume is a lil different D:)

A
  1. Say u want to find the percentage error for mass 1g
  2. For 2 decimal place balance, nearest would be 0.01g
  3. Formula: (0.01/1g) x 100 = 1%
  4. For 3 decimal place: (0.001/1g) x 100 = 0.1%
  5. How how about 2 decimal place for 10g?: (0.01/10g) x 100 = 0.1%
  6. Say for time, 100s, it’s probably 2 decimal places depending on how many 0s in decimal place thingy
  7. soooo: (0.01/100) x 100 = 0.01%
  8. Now for volume
  9. Consider measuring 25cm3 in a 25cm3 measuring cylinder
  10. Apparently it’s the nearest 0.5cm3 and idk why
  11. Therefore: (0.5/25) x 100 = 2.0%
  12. For a burette, nearest 0.05cm3 as well?
  13. Aiming for a titre of 25cm3 as well?
  14. Formula: (2x0.05/25) x 100 = 0.4%
    My question is, why the 2x there?

Concluding tho:
- Look at the minimum number u can get (it’s the decimal places)
- grams always denominator
- And tbh it’s like finding any other percentage in general