O.Chem 3 Flashcards
Alpha Hydrogens
Hydrogens on a carbon adjacent to a carbonyl carbon are ACIDID due to RESONANCE STABILIZATION of the conj. base. When there are two carbonyls separated by a single carbon, hydrogens in the middle carbon are even more acidic.
The more partial positive the carbonyl carbon is, the more acidic the alpha hydrogens will be.
Carbonyl Key Features
1) Partial positive charge on carbonyl carbon
2) Alpha hydrogens: acidic
3) Electron donating/withdrawing groups: ED decrease reactivity of the carbonyl carbon, EW increase its reactivity
4) Steric hinderance: bulky substituents attached to carbonyl carbon decrease reactivity
5) Planar stereochemistry: sp2 hybridized carbonyl carbon is planar, can be attacked from either side.
Aldehydes
- Name with the -al ending.
- Aldehyde carbons are always considered carbon #1 for numbering purposes
- Aldehyde substituent is “-oxo” like ketones
Ketones
- Are named with the -one ending
- If ketone must be named as a substituent it is called an “-oxo” group
Common Aldehydes and Ketones
- Formaldehyde (HCOH)
- Acetaldehyde (CH3COH)
- Benzaldehyde (C6H5COH)
- Acetone (CH3COCH3)
Aldehydes and Ketones Solubility and Boiling Point trends
Aldehydes and ketones act as H-bond recipients, but NOT as H-bond donors.
-They don’t form hydrogen bonds with one another, but since they are polar, their boiling points are much higher.
General Characteristics of Aldehydes and Ketones
- Major function: ELECTROPHILES
- Can act as Lewis acids, accepting electrons when a base abstracts an alpha hydrogen
Substitution vs Addition:
- Aldehydes and ketones undergo NUCLEOPHILIC ADDITION (no substitution because no good LEAVING GROUPS)
- Carboxylic acids, amides, esters, anhydrides undergo NUCLEOPHILIC SUBSTITUTION
Keto-Enol Tautomerization
Process by which an alpha hydrogen adjacent to an aldehyde or ketone becomes bonded to the carbonyl oxygen, while the double bond is switched from the carbonyl oxygen-carbon bond to the bond between the carbonyl carbon and the alpha carbon
Formation of Acetals/Hemiacetals and Ketals/Hemiketals
- Acetals/ketals have TWO -OR substituents
-Hemiacetals/hemiketals have ONE -OR substituent plus one alcohol substituent (-OH group)
Steps:
1. Alcohol acts as nucleophile, attacks carbonyl carbon, pushes up pi bond electrons to the oxygen.
2)Oxygen is protonated (could have been protonated already if acid catalyzed) to form an alcohol and original alcohol is de-protonated to form an ether. This yields a hemiacetal (aldehyde) or hemiketal (ketone)
3) Alcohol is protonated again to form the good leaving group water, and a second equivalent of alcohol attacks the central carbon
4) Deprotonation of the second alcohol results in another ether, yielding a acetal or ketal.
Protecting Ketones/aldehydes from Reaction
Ketones and aldehydes can be prevented from reaction with nucleophiles or base by conversion to an acetal or ketal (unreactive unless in acidic conditions). Any terminal DIOL with at least two carbons will work.
Steps:
1) One end of the diol acts as a nucleophile
2) Other end of the diol acts as the “second equivalent of alcohol”
3) Acidic conditions will return the aceta/ketal to the original aldehyde or ketone
Halogenation of an Aldehyde or Ketone
Substitution of Br, Cl or I for one of the ALPHA H’s on an aldehyde or ketone. Multiple halogenations often occur.
1) Base abstracts an alpha H, leaving carbanion.
2) Carbanion attacks a diatomic halogen (Cl-Cl)
The Haloform Reaction
When Halogenation is performed on a methyl ketone (CH3CO-R) with sufficient halogen present to effect replacement of all 3 alpha H’s.
1) Complete halogenation using methyl ketone and enough halogen to replace all 3 alpha H’s
2) Tri-substituted alpha carbon has a large partial positive charge and is transformed into a decent leaving group. When a strong hydroxide base, such as NaOH, is added, the -OH attacks the carbonyl carbon, kicking the electrons in the C=O up to onto the oxygen.
3) The electrons from the oxygen collapse down, reforming the pi bond, and kicking off the haloform as a leaving group. Results in a carboxylic acid
* * Since in basic conditions, the reaction will produce carboxylate ions exclusively (COO-). Haloform acts as a base
Aldol Condensation
Condensation of one aldehyde or ketone with another aldehyde or ketone
1) Base abstracts an alpha H, creating a carbanion
2) Carbanion will attack any carbonyl carbon in the solution
3) Oxygen is protonated to form an alcohol
* *Always COUNT CARBONS BEFORE AND AFTER
Alpha-beta unsaturated Carbonyls
An aldehyde or ketone with a double bond between the alpha and beta carbons
Two resonance structures so two possible ways to visualize mechanism:
1) With the double bond between the alpha and beta carbons, the nucleophile attacks the BETA carbon, pushing the double over to one carbon and forcing the C=O electrons up onto the oxygen
2) With a carbocation on the beta carbon, the nucleophile simply attacks the beta carbon directly
- Starting with either resonance form, the oxygen will get PROTONATED to form an alcohol.
- The protonated oxygen is really just the ENOL form of a keto-enol tautomer.
The Wittig Reaction
Transforms carbonyls into an alkene
NO MECHANISM, the product will always be an alkene, with the double bond bormed between the CARBONYL CARBON and the CARBON attached to the polyphenyl group
(CH3)2C=O + Ph3P+–CRR’ ====> (CH3)2C=CRR’ + Ph3P=O
Carboxylic Acids
- “oic acid” ending
- Carboxylate formed when proton is abstacted, leaving negative oxygen. “-ate” ending. If salt is formed, name metal then ion (sodium benzoate)
- Common names: formic acid (HCOOH), acetic acid (CH3COOH), benzoic acid (C6H5COOH)
Physical Properties of COOH’s
Very high boiling points due to H-bonding (forms strong dimers)
- W/O long alkyl chains, they are soluble in water
- Surprisingly short-chain carboxylic acids are also soluble in many relatively non-polar solvents, such as chloroform (even though they are clearly polar), SINCE THE DIMER WOULD HAVE NO DIPOLE MOMENT, IT IS SOLUBLE IN NON-POLAR SOLVENTS