Nucleophilic substitution with loss of carbonyl oxygen Flashcards

1
Q

Draw the mechanism for the nucleophilic substitution with loss of carbonyl

A

-

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2
Q

How do you make something a better leaving group?

A

Protonate it

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3
Q

What is Keq for aldehydes?

Is this favourable or unfavourable?

A

0.01

Unfavourable

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4
Q

What is the overall equation for acetal formation and how can this reaction become more favourable?

A

Aldehyde + 2ROH acetal + H2O

Remove water as it formed to drive eq to the RHS

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5
Q

Why is Keq so low for acetal formation?

A

Both entropically and enthalpically unfavourable

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6
Q

How is acetal formation entropically unfavourable?

A

From 3 molecules to 2 molecules

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7
Q

Why do the entropy and enthalpy factors affect Keq?

A

They cause ΔG to be positive which is not favourable

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8
Q

Which conditions are acetals hydrolysed under?

A

Acidic

H+ , H2O

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9
Q

What are acetals stable to?

A

Base hydrolysis

HO-, H2O

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10
Q

Why is it good to convert an aldehyde to an acetal?

A

Acetal acts as a protecting group

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11
Q

What is an imine?

A

Nitrogen equivalent of a carbonyl compound

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12
Q

What does imine formation require?

A

acid catalysis

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13
Q

How does an imine compare to amine and ketone?

A

Unstable

Keq < 1

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14
Q

How can equilibrium be driven to form the imine?

A

Remove water as it is formed

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15
Q

What reaction are imines involved in? How are they involved?

A

Reduction of amides through a double hydride addition

There is an iminium ion intermediate

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16
Q

What reagent is required for the reduction of amides?

A

LiAlH4

17
Q

What is the Wittig reaction?

A

Substitution of C=O for C=C

18
Q

What is a ylide?

A

Molecule with adjacent positive and negative charges

19
Q

What reagent is involved in the Wittig reaction?

A

Ph3P–CH2

20
Q

Which bit of the reagent is swapped out in the Wittig reagent? What for?

A

-CH2 for =O

21
Q

What is a ylid?

A

Molecule with adjacent positive and negative charges

22
Q

What is the driving force for the Wittig reaction?

A

P=O bond strength as it is extremely strong which creates an irreversible reaction

23
Q

How is a phosphonium ylid formed?

A

Using Me - I to form a phosphonium salt and then a strong base