Moving charges and magnetism Flashcards
force due to a magnetic field
F=q(VxB)
v–>velocity of charge
B–>magnetic field
! obtained direction for +ve charge(for eg upward) is opposite to
direction for -ve charge(for eg downward)
Lorentz force
1)the force experienced by a charge in an external electric field and magnetic field
2)F = qE(force due to electric field) + qv × B
force on current carring conductor
F=BIL sin(theta)
where theta –>angle between conductor and magnetic field
(use flemings left hand rule[FBI] to determine the direction)
motion of charged particle in a magnetic field(when it is parallel or anti parallel to the magnetic field)
no change because force due to magnetic field is zero
motion of charged particle in a magnetic field(perpendicular)
find its responding formula
1)circular motion with constant velocity and direction keeps changing
2) r=mv/qb
r–> radius of circular path
m–>mass of particle
b–>magnetic field
3)anglular velocity(omega)=qb/m [by v=r omega]
4)f=qb/2pim [by 1/T where T=2*pi/omega]
motion of charged particle in a magnetic field(the particle is projected with an angle theta)
it follows a helical path(spring)
relationship between epsilon and mu
epsilon * mu = 1/c^2
magnetic field due to a finite current carring conductor
B=(μ/4*pi) * I/d(sin x+sin y)
where
d–> distance between the point and conductor
i–> current
x–>angle between the top and middle of the conductor
y–>angle between the conductor’s middle and bottom
Magnetic field on the axis of a circular current loop
(μIR^2) / 2*[R^2+X^2]^(3/2)
where
R–>radius of sphere
x–>distance from center of the circle to the point
magnetic field due to a infinity long straight conductor
B= μi/2pir
ampere circuital law
the line integral of the magnetic field surrounding closed-loop equals to the number of times the algebraic sum of currents passing through the loop
∮B dl = μ i(enclosed)
force per unit length due to parallel current
F12=μi1i2/2pid
torque on a rectangular current loop in a uniform magnetic field
tau(T)= B * I * A(area of rectangular loop)
torque on a rectangular current loop in a uniform magnetic field at angle theta
tau(T)= iabsin(theta)
where ia=
current in a moving coil galvanometer
I = (C/nBA) × θ
I–>The current in the moving coil galvanometer
C–>The torsional constant of the spring