module 5 physical chem Flashcards
acid
proton donor
base
proton acceptor
conjugate acid base pairs
HA + OH –> H2O + A
HA & A acid base pair 1
OH- & H2O acid base pair 2
basic equations
acid + metal –> salt + hydrogen
acid + oxide –> salt + water
acid + carbonate –> salt + CO2 + water
acid + hydroxide –> salt + water
pH equation
pH = -log[H+]
[H+] is concentration of H+ atoms
[H+] equation
[H+] = 10-pH
10 to the power of -pH
Diluting pH
X10 everytime to drop down pH
1 –> 2 X10
Ka expression
Ka= [H+] [A-]
[HA]
Ka= [H+]2
[HA]
Ka equation
Ka= 10-PKa
PKa equation
-log(Ka)
working out [H+] conc with Ka
[H+] = Ka x [HA]
Kw
ionic product of water
1 x 10-14
working out [H+] in alkali
you are given OH conc (overall conc)
[H+] = 1 X 10-14 / [OH-]
then put into pH equation (-log[H+] )
working out [H+] in alkali
method 1
you are given OH conc (overall conc)
[H+] = 1 X 10-14 / [OH-]
then put into pH equation (-log[H+] )
working out [H+] in alkali
method 2
you are given OH conc
put into equation POH = -log[OH-]
then do 14 - POH = pH