module 5 (chapter 23) - electrode potentials and redox Flashcards

1
Q

electrochemical cells

A

transfer chemical energy into electrical energy
-electrical energy is produced by the movement of electrons and so redox reactions are needed as these transfer electrons

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2
Q

half cells

A
  • contains a chemical species present in a redox half-equation
  • the chemicals of the two cells are kept apart as if allowed to mix electrons flow uncontrollably releasing heat energy not electrical
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3
Q

metal-metal ion half cells.

A

metal rod dipped into a solution of its aqueous metal ion

  • the phase boundary is where the metal is in contact with its ions and this sets up an equilibrium
  • phase boundary is shown by a vertical line in the equation
  • in an isolate half cell, there is no net transfer of electrons either into or out of the cell.
  • when there are two, the direction of flow depends upon the relative tendency of each electrode to release electrons
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4
Q

ion-ion half cells.

A
  • Contains ions of the same element in different oxidation states.
  • An inert electrode made out of platinum is used. These help to transport electrons either into or out of the half-cell
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5
Q

electrode potentials

A
  • The electrode with more reactive metal loses electrons and is oxidised. This is the negative electrode
  • The electrode with the less reactive metal gains electrons and is reduced. This is the positive electrode.
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6
Q

standard electrode potentials

A
  • The e.m.f of a half-cell connected to a standard hydrogen half-cell under standard conditions.
  • A standard Half-cell contains hydrogen gas, a solution containing H+ ions and an Inert platinum electrode
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7
Q

standard conditions

A
  • Concentration of exactly 1moldm-3
  • 298K
  • 100Kpa
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8
Q

general rules for measuring a standard electrode potential

A
  • The more negative the electrode potential value, The greater the tendency to lose electrons and undergo oxidation.
  • The more positive the electrode potential value, The greater the tendency to gain electrons and undergo reduction.
  • Metals tend to have more negative electrode potential values than non-metals.
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9
Q

standard cell potential equation

A

E(positive electrode) – E(negative electrode)

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10
Q

limitations of electrode potentials

A
  • They do not give an indication of rate of reaction of activation energy
  • If the concentration is different to 1moldm-3, it won’t work.
  • The actual conditions may be different to standard.
  • standard electrode potentials apply to aqueous equilibria, many reactions take place that are not aqueous
  • f the potential difference is less than 0.4V, the reaction is unlikely to happen
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11
Q

salt bridge

A
  • allows ions to flow and contains a solution that doesn’t react with the half cell solutions
  • e.g. filter paper socked in KNO3
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12
Q

by convention. how do we write half cell equations?

A

-reduction as the forwards reaction

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13
Q

over time why does the measured cell potential change?

A
  • the concentration of the electrolyte chances

- this means that the conditions are standard

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14
Q

how do primary cells work?

A
  • electrical energy is produced by redox reactions at the electrodes.
  • however, the reactions cannot be reversed. this means they are non-renewable and therefore when chemicals are used up they will go flat
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15
Q

what are primary cells used for?

A
  • Low current, long-storage devices such as wall clocks and smoke detectors
  • Most modern primary cells are alkaline based on Zinc and Magnesium dioxide, and a potassium hydroxide electrolyte solution
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16
Q

advantages of primary cells

A
  • They have high specific energy
  • Light weight so can be carried around on aircrafts
  • Cheap to make and buy
  • Long storage times
17
Q

disadvantages of primary cells

A
  • non-renewable and therefore can only be used once
  • Made from toxic materials (heavy metals)
  • Difficult to dispose of and often sent to landfill.
18
Q

how do secondary cells work?

A
  • electrical energy produced by redox (simultaneous oxidation and reduction)
  • They can be recharged as the cell reaction producing the electrical energy can be reversed
  • The chemicals in the cell are regenerated and can be used again
  • The recharging process is just the opposite of the discharging reaction so is essentially the redox reaction in reverse for recharging.
19
Q

what are secondary cells used for?

A
  • Lead-acid batteries used in cars
  • Nickel-cadmium cells form the batteries used in radios and torches
  • Lithium ion cells are used in laptops, camera and mobile phones. They are also being developed for use in cars.
20
Q

advantages of secondary cells

A
  • They use less toxic materials and therefore toxic waste.
  • Sometimes generates hydrogen gas at the cathode when charging
  • Produce less waste because they can be recharged
  • Motion can be used to recharge batteries
21
Q

disadvantages of secondary cells.

A
  • more expensive
  • Don’t have a huge lifespan
  • Extremely sensitive to high temperatures and therefore are prone to exploding and burning
22
Q

how do hydrogen fuel cells work?

A
  • Anode is where oxidation takes place (electrically negative), cathode is where reduction takes place (electrically positive)
  • Electrodes are porous and made of platinum materials reinforced carbon – acts as catalysts
  • can have either an acid or alkali electrolyte
23
Q

fuel cells

A
  • use the energy from a reaction of a fuel with oxygen to create voltage
  • the fuel and oxygen flow into the fuel cell and the products flow out. the electrolyte remains in the cell
  • they don’t need to be recharged and can operate continuously along as they are supplied.
24
Q

advantages of fuel cells

A
  • Produced in an environmentally manner
  • Water and heat are the only by-product
  • More efficient than combustion engines
  • Less noise
  • Never run flat if you have a constant supply of fuel and therefore are more reliable. Secondary cells eventually become less efficient, primary cells are non-renewable as you have to replace the cell when it runs out.
25
Q

disadvantages of fuel cells

A
  • expensive to manufacture
  • There is a lack of infrastructure to support the distribution of hydrogen. This means it is not yet, widely available.
  • It needs to be pressurised into a liquid as a gas is too dispersed. This is expensive and potentially explosive.
26
Q

how do methanol fuel cells work?

A

-Water and methanol react as the cathode whilst oxygen and H+ ions react at the anode to produce water

27
Q

positives and negatives of methanol fuel cells

A
  • used in consumer goods
  • Limited power so they can’t power vehicles
  • Methanol is very toxic and highly flammable
28
Q

how do you do redox equations?

A
  • work out what has been oxidised and what has been reduced
  • balance the electrons
  • balance any remains atoms and predict further species
29
Q

what can manganate redox titrations be used for?

A
  • the analysis of different reducing agents
  • irons ions Fe2+
  • ethanedioic acid (COOH)2
30
Q

how do you analyse the purity of an iron compound?

A
  • prepare a volume if impure hydrated iron sulphate in a volumetric flask
  • measure a volume of this into a conical flask and add a smaller amount of 1moldm-3 sulphuric acid
  • titrate this using a standard 0.02moldm-3 solution of potassium manganate
  • analyse your results to determine percentage purity
31
Q

how to analyse your results (iron and manganate)?

A
  • calculate the amount of managante that reacted.
  • determine the amount of iron that reacted (equation and molar ratio)
  • scale up to find mole of iron in standard solution
  • find the mass of hydrated iron sulphate in the impure sample
  • place this as a percentage of the impure sample
32
Q

what happens in iodine/thiosulphate titrations?

A
  • thiosulfate ions are oxidised

- iodine is reduced

33
Q

what can iodine/thiosulphate titrations be used for?

A
  • the ClO- content in household bleach
  • the Cu2+ content in copper compounds
  • the Cu content in copper alloys
34
Q

how is the iodine/thiosulphate titration done?

A
  • prepare a solution of the oxidation agent and add to a conical flask
  • add an excess of potassium iodide. the oxidising agent reacts with iodide ions to produce iodine, which turns the solution a yellow-brown colour
  • titrate with thiosulphate
  • the iodine is reduced to black ions and the yellow colour fades
  • when the end point is being reached, add starch. this forms a deep blue colour to assist the identification of the end point
  • once all of the iodine has reacted all of the blue/black disappears.
35
Q

iodine/thiosulphate and copper

A
  • can be used to determine the copper content in copper salts or alloys
  • for soluble copper salts dissolve in water, for insoluble react with acid.
  • Cu2+ ions react with I- to form a solution of iodine and a white ppt of copper iodide
  • the mixture appears brown
  • the iodine is then titrated with a standard solution of sodium thiosulphate