module 3: equilibrium Flashcards

1
Q

rate =

A

concentration/ time

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2
Q

rate of reaction calculated by

A

reactant us up/ product formed overtime

if gas produced increase of in volume, decrease in mass
if reactant acid increase in pH over time

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3
Q

collision theory

A

particles collide with enough energy to break existing bonds
collide in correct orientation
not all collisions are successful
higher rate = more successful collisions per second

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4
Q

increasing concentration

A

increases the rate of reaction
more particles per unit volume
more frequent collisions

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5
Q

rate of reactions from graphs

A

instantaneous -> tangent

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6
Q

catalyst

A

increases rate of reaction without being used up
lowers activation energy by providing an alternate pathway
“proceed via alternate route with lower activation energy”

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7
Q

homogeneous catalyst

A

same state as reactants

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8
Q

heterogeneous catalyst

A

different state from reactants

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9
Q

benefits of using catalyst

A

lower temperature and pressure
reduce energy demand -> less fossil fuels burnt -> less limited resources used up and CO2 produced
increases sustainability and reduces emissions
cost saving

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10
Q

Boltzmann distribution key notes

A

not symmetrical
does not cross x-axis (asymptote)
starts at origin, no particles have zero energy
total area= total number of gas particles

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11
Q

Boltzmann curve Ea

A

larger area= greater proportion of particles with an energy greater than Ea therefore faster rate of reaction

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12
Q

Boltzmann distribution temperature graph aided

A

higher temperature peak lower and shifted right
greater proportion of molecules can overcome activation energy

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13
Q

Boltzmann distribution temperature

A

as temperature increases
average energy of particles increases
peak distribution moves right
flatter
greater proportion of molecules can overcome activation energy
rate of reaction increases

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14
Q

Boltzmann distribution catalysts

A

distribution curve same
activation energy lower
greater proportion of molecules exceed new lower activation energy
on collision, more molecules react to form products
rate of reaction increases

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15
Q

Le Chateliers principle

A

system works to counteract change

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16
Q

dynamic equilibrium

A

closed system
rate of forward reaction= rate of reverse reaction
concentration of reactants and products remain constant

17
Q

increasing temperature

A

endothermic reaction favoured

18
Q

changing concentration

A

equilibrium shifts to oppose change

19
Q

factors affecting rate of reaction

A

concentration
surface area
temperature
pressure
catalyst

20
Q

pressure same no of moles on both sides

A

no change

21
Q

increasing pressure

A

favours side with fewer moles of gas

22
Q

heterogeneous catalysts notes

A

reactants absorbed onto surface
weak bonds formed between reactants and catalysts
bonds between reactant molecules weaken and break
new bonds form between reactant molecules

23
Q

catalyst “poisoning”

A

impurities bind to the surface
e.g. lead and sulfur

24
Q

regeneration

A

blowing hot air over a catalyst
oxidises chemicals on the surface
used to remove carbon after catalytic cracking

25
Q

Kc =1

A

equilibrium position around halfway between reactants and products

26
Q

Kc < 1

A

equilibrium favours reactants

27
Q

Kc >1

A

equilibrium favours products
(high concentration of products to reactants)

28
Q

homogeneous equilibrium

A

reactions in which reacting species are in the same phase

29
Q

heterogeneous equilibrium

A

different phase
solids and liquids do not appear

30
Q

equilibrium constant

A

[A] (concentration of reactants) decreases to a constant
[B] (concentration of products) increases from zero to a constant

no matter the starting composition of reactants and products, the same ration is achieved at equilibrium at constant temperature

31
Q

catalyst equilibrium position

A

no effect-> forward and reverse both increased by same amount
equilibrium reached faster

32
Q

Ea

A

minimum energy for reaction to occur

33
Q

equilibrium law

A

for the reaction aA + bB ⇌ cC + dD

kc = ([C]c [D]d) / ([A]a [B]b)

kc is in terms of concentration

34
Q

equilibrium law simplified

A

Kc= [products]/ [reactants]

35
Q

when equation for reversible reaction given in opposite direction

A

equilibrium constant becomes resiprocal