midterm 1 notes Flashcards
relationship between Q and K
Q greater than K: reactants
Q less than K: products
Q=K: equilibrium
a plot of the concentration of the reactant versus time yields a straight line
0 order
the reaction has a half life that is independent of the initial concentration
1st order
a plot of the inverse of the concentration versus time yields a straight line
2nd order
slope is equal to
-k (1st order)
-Ea/R (2nd order)
review endothermic and exothermic graphs
ok
b is equal to in second order
ln A
units for K
zero order: M/s
first order: 1/s
second order: 1/M (1/s)
after time (for arrehnius q)
original concentration-calculated concentration
when drawing graphs
Ea = goes up until reactants
enthalpy= btwn reactants and products
reverse Ea= makes up the Ea and the enthalpy
determining value for k with system of equations
the one you are determining cant be constant values (i.e. cant be [0.10] and [0.10]
integrated rate law
[A]=-kt+c
when solving for instantaneous rate of change….
=k[E]
Ea2 goes up to
intermediates
endothermic drawing
Ea2 IS BIGGER than EA1
does solid account for the value or conversion btwn Kp and Kc?
no
