Lab 7 Flashcards

1
Q

what does this experiment study

A

equilibrium systems that exist between a sparingly soluble salt and its environment

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2
Q

Ionic solids

A

some of which are the products of acid-bases reactions, have varying solubility in water

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3
Q

what represents the equilibrium of dissolution of compounds such as ionic solids

A

Ksp

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4
Q

When sparingly soluble salts are added to water, agitated, and allowed to equilibrate

A

you get saturated solutions

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5
Q

Equilibrium in saturated solutions differs from ionic equilibrium in aqueous acids and
bases in that they …..

A

are heterogeneous mixtures and therefore involve heterogeneous equilibria

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6
Q

solid material is in contact with a liquid aq phase containing separated ions of the solid

A

Ions move back
and forth from the aqueous phase to the solid phase at the same rate and the system is said to be in a
state of dynamic equilibrium

For example, the sparingly soluble salt calcium iodate, Ca(IO3)2, dissolve in water to a very small
extent according to the reaction:
Ca(IO3)2 = (w/H2O) = Ca2+ + 2IO3
- eq lies to the left
- concentration of ions is small

Ksp= [Ca2+][IO3-]^2

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7
Q
  • solubility product constant expressions are often
A

restated in terms of the molar solubility of the
salt.

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8
Q

molar solubility

A

The molar solubility of a substance is the maximum amount (in moles) of solute that dissolves per
litre of solution.

therefore we can rewrite
Ksp=(s)(2s)^2=(4s)^3

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9
Q

common ion effect

A

according to Le chat adding excess calcium or calcium iodate ions can cause equilibrium to shift left

  • We will study this effect via a redox titration of calcium iodate solution containing an additional source of iodate ion (from KIO3).
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10
Q

to find Ksp

A

we need to know the concentration of both Ca+2 and IO3– in solution at equilibrium. However, since the concentrations of the two ions are stoichiometrically related, we only
need to find one to know the other.

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11
Q

The concentration of iodate, IO3-, is most easily determined through

A

a redox titration with standardized thiosulfate, S2O32-, in the presence of iodide, I-, using starch as an
indicator.

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12
Q

iodate is used because

A

Iodate is a fairly good oxidizing agent and will oxidize I- (supplied by KI) to give iodine, I2, in acidic solution (7.4).

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13
Q

use of starch indicator

A

Starch is used as an indicator in this titration because it reacts with I2 reversibly to form a dark blue –
black complex

  • Since I2 is consumed in the titration the dark colour of the complex will fade.
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14
Q

when is endpoint reached

A

The endpoint is reached when one drop of Na2S2O3 causes the disappearance of the last trace of blue – black
colour

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