Membrane and action potentials Flashcards

1
Q

What type of channels develop resting membrane potential?

A

Leak potassium and Leak Sodium channels

NOT the sodium potassium pump

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2
Q

What ion is the membrane more permeable to at rest

A

Potassium. The Em (-65mV) lies closer to the equilibrium potential of potassium (-80mV)

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3
Q

what is the equilibrium potential point

A

the point at which the chemical and electrical forces moving across the membrane is both equal and opposite

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4
Q

What would happen is only K+ ion channels were open?

A

Chemical force at start leads to K+ efflux
[K+] inside > [K+] outside
K+ efflux results in membrane becoming more negative
this establishes a electrical force inside of cell becomes more negative
this leads to some K+ influx
at a sufficiently negative Em there is no net movement of K+ across the membrane as chemical and electrical forces become equal and opposite
this is the equilibrium potential around -80mV for K+

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5
Q

Theory if Na+ only?

A

The chemical force would result in Na+ influx
Em becomes more positive
electrical force would be established that would push Na+ back out of the cell
when Em reaches a sufficiently positive value chemical and electrical forces become equal and opposite there is no net movement of Na+
ENa is +62mV

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6
Q

Em is not equal to the E potential of an ion. why?

what is the effect on K+ and Na+

A

Em is not the Ek therefore forces on K+ are unequal
at -65mV chemical influence on K+ ([K+] inside is greater than outside therefore efflux) is larger than the electrical force that causes influx so net movement of K+ ions outside the neurone

For Na+ at -65mV both the chemical and electrical influence both cause Na+ influx as large difference in Na+ conc and there inside and the -65mV attracts positive Na+ ion the cell

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7
Q

Why is the resting potential closer to K+ equilibrium potential than Na+ equilibrium potential

A

Membrane contains more K+ leak ion channels than Na+ leak channels. 40X more permable to K+ than Na+ therefore the Em lies closer to K+ EK than Na+ ENa

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8
Q

Explain the establishment of the resting membrane potential

A

Na+ enter the cell due to chemical and electrical influence ie there is an ionic driving force driving

Na+ ion the cell
this makes the inside of the cell more +

This reduces the ionic driving force of K+
K+ move out of the cell down its concentration gradient as conc gradient > ion driving force that causes K+ influx
eventually Na+ influx= K+ efflux
This is the resting potential

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9
Q

Why is there no significant change in concentration during the establishment of a membrane resting potential?

A

The movement of ions across the membrane is so small its effect on conc is negligible however over time it would have an effect on concentration

Na+/K+ maintain the ionic gradient and therefore the ionic driving force of Na+ and the efflux of K+ out of the neurone

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10
Q

What is conductance?
Why is it a good measurement?
What is significant?

A

equivalent to permeability

easier to measure than permeability as it only takes into account the action of ion channels
is denoted as g

g is directly proportional to the no of open ion channels (permeability don’t have such as simple relationship)

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11
Q

What are the stages of an action potential?

A

Depolarisation
Repolarisation
Hyperpolarization
Refractory period

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12
Q

Why is Em -65mV

A

K+ efflux = Na+ influx

Na+ influx due to ionic driving force (electrical and chemical)

K+ efflux as ionic driving force trying ot move K+ in is less than the conc gradient causing k+ movement out of the neruone

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13
Q

What is depolarisation?

Describe how it is achieved.

A

stimulus from synapse or generator potential causes a small amount of depolarisation

this causes some Na+ VG ion channels to open

Na+ influx as well as that from the leak channels

Increases the membrane potential more +
most overcome minimum threshold -55mV

if over the threshold potential more and more Na+ channels open causing rapid depolarisation

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14
Q

Why does the Em approach the ENa during an action potential

A

gNa increases x1000
during the AP gNa is 25X the permeability to K+ during normal resting potential

more and more Na+ enter due to the opening of VG Na+ channels therefore the membrane potential approaches +40mV

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15
Q

What are the two aspects of Repolarisation?

A

inactivation of VG Na+ channels

Opening of VG K+ ion channels at +40mV
gK increases
K+ influx

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16
Q

Hyperpolarization? What occurs

A

Em approaches EK as gK maintained past the original Em

Eventually VGK+ ion channels close decreasing permeability
Allows time for VG Na+ channels to recover

EM returns to normal due to action of LEAK channels

17
Q

Summarise the events leading to depolarisation including the concept of threshold.

A

Initial stimulus causes depolarisation

Some Na+ influx through VG ion channels and through leak channels –> decrease on ionic driving force driving Na+ in the cell due to initial depolarisation and an increase on the ionic driving force moving K+ out

Therefore stimulus must cause enough depolarisation and opening of initial VG ion channels to overcome the reduced ionic driving force for Na+, and the increased ionic driving force on K+

Na+ influx must be greater than K+ efflux and reach the minimum threshold value to cause the graded opening of many VG Na+ channels that result in Depolarisation

ALL OR NOTHING RESPONSE

18
Q

Repolarisation

And Hyperpolarisation

A

As Em approaches ENa Vg Na+ channels are inactivated. gNA decreases

Vg K+ channels open
gK increases
K+ ion efflux out of the cell
Repolarization

Em approaches the resting potential Em is still high and goes past into hyperpolarization os VG K+ are still open

additional K+ efflux leading to Em approaching the EK

VG K+ eventually close Em returned to -65mV via LEAK channels

19
Q

How can the strength of a response be increased?

A

Increasing the firing frequency of action potentials

NB Magnitude cannot be changed

20
Q

What is the absolute refractory period?

A

No further action potentials can be generated by any stimulus:

most Vg Na+ ionic channels are still inactivated

Too many Vg K+ ion channels are open

Na+ influx must be greater than K+ efflux to overcome the threshold which is impossible here

21
Q

What is the relative refractory period?

A

Can get another AP but the stimulus must be larger as:

Na+ are still recovering from inactivation

K+ ion channels are now closing

Now possible for Na+ influx to be greater than K+ efflux however stimulus must be large enough to open VG Na+ ion channels and overcome the higher threshold value due to some Na+ still being inactivated and some K+ still closing

22
Q

Propagation of nerve impulse on an unmyelinated axon

A

Electronic spread allows propagation along the axon

Differences in ion concentration flow inside axoplasm

Positive ions move to area that hasn’t yet been depolarised –> depolarisation and opening of Vg Na+ ion channels leading to AP propagation

Na+ ions can flow backwards however the membrane is still in its refractory period and most of the Na+ are still recovering

Ensure unidirectionality

23
Q

Why is the refractory period so important?

A

Allows the neurone to recover to resting membrane potential before firing another action potential

ensures unidirectionality in the propagation of AP along axons

24
Q

Saltatory conduction (myelinated axons)

A

axolemma insulated by myelin sheet increasing the size of local circuits

Positive charge diffuses a longer distance to the Node of Ranvier where the axolemma is exposed.
Causes depolarisation and opening of Vg ion channels allowing AP propagation

25
Q

What is an advantage of myelinated axons

A

increases the size of local circuits inside the neurone leading to rapid transmission of action potential via saltatory conduction