Mechanics Flashcards

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1
Q

Kinematics

A

Deals w/ description of motion (terminology?)

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2
Q

Distance (x/s)

A
  • How far an object goes (unit: m)
  • Scalar (no direction involved)
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3
Q

Displacement (x/s)

A
  • Change in position of an object in a certain direction OR shortest distance an object covered in a certain direction
  • Final position minus the initial position
  • Unit: m (+ direction)
  • B/c direction involved, vector
  • Can be positive (right, forward, upwards, etc.) or negative (backward, left, downwards, etc.)
  • “Displace” from initial to final position
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4
Q

Speed (v)

A
  • Rate at which distance is covered
  • Distance over time (x/t)
  • Unit: ms^-1
  • Scalar (direction not involved)
  • Slope of a distance-time graph represents speed
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5
Q

Velocity (v)

A
  • Change in position per unit time OR displacement per unit time OR speed in a certain direction
  • Displacement over time (change in position [final minus initial] over time)
  • Unit: ms^-1 (+ direction)
  • Vector (has direction)
  • Slope of a displacement-time graph represents velocity

*Rate = per unit time
*Post-slash = unit
*Speed, velocity interchanged

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6
Q

Distance-time/Displacement-time graphs

A
  • “As the slope goes, so does the motion”
  • Interpretation has a lot to do w/ slope (all about slope and then maybe a little based on the y-axis)

ex.
Slope = velocity
Straight line = constant
Line goes up = positive

Interpretation: The above graph represents an object whose speed is constant and positive and the distance increases proportionally (if line goes through origin).

  • Displacement could be increasing sharply or gradually too (and velocity could be zero [displacement constant])

*“tending towards…” ex. t
*Whatever a graph w/ a horizontal line represents is zero

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7
Q

Area of a displacement-time graph

A
  • We’re not doing calculations rn, but just try to figure out what area represents (triangle for diagonal and rectangle for straight line)
  • Do you recognize the formula (does it represent anything useful)?
  • Use units
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8
Q

Avg speed

A
  • There must’ve been changing speeds (implied)
  • Total distance over total time
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9
Q

Avg velocity

A

Total displacement over total time

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10
Q

Instantaneous speed

A
  • Velocity at a certain point in time
  • Draw tangent, make triangle (connect to axes): line must be blow curve
  • Change in y over change in x
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11
Q

Acceleration (a)

A
  • Rate of change of velocity
  • Change in velocity (final [v] minus initial [u]) over time
  • Unit: ms^-2
  • Vector (has direction [uses velocity])
  • Slope of a velocity-time graph represents acceleration
  • Object is said to be accelerating if velocity increases or decreases or if the object changes direction
  • Negative acceleration = decceleration
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12
Q

NOTE

A
  • For circular motion, direction is not constant, so even though the speed is constant, there’ll be a change in velocity, and acceleration will be present
  • If tangent a straight line, speed at that point is zero
  • Speed and velocity can be interchanged, so speed can be negative
  • More curve = more change in velocity = more acceleration
  • When falls downward, change in position is negative
  • Write all five?
  • Vertical line = connection between whatever was happening before and what happened next
  • No acceleration is x-axis
  • Say “force of gravity” or “gravitational force” (not just “gravity”)
  • Acceleration, force go together (if there’s acceleration, there’s force)
  • Deep in space, force of gravity is 0?
  • Outer space has a small amt of gravity b/c it’s close to earth?
  • Negative sign is conventional (shows it’s going downward)
  • Negligible = ignore (not present)
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13
Q

Area of a velocity-time graph

A

Represents distance (do the calculation)

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14
Q

Area of an acceleration-time graph

A

Represents speed (do the calculation)

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15
Q

Uniformly-accelerated motion (UAM)

A
  • Motion of an object whose acceleration stays constant (ex. freely falling object, object moving in a straight line w/ constant acceleration, projectile [parabola], frictionless incline [there are inclines they can pad so that there will be almost no friction as the object falls and the only force acting on it would be gravity]], etc.)
  • Weightless: only force present is gravity (no air resistance [so mass doesn’t matter])
  • Negative symbol applies to force of gravity when falling (agrees w/ force): downward is negative for vectors
  • For distance-time, a curve
  • For acceleration-time, a straight horizontal line
  • For velocity-time, straight line (diagonal) up/down (acceleration is a vector, so can be constant or negative)
  • Negative acceleration b/c -d/t (-v)

*When you balance w/ normal force, that’s when something’s mass comes in
*Weight is gravity

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16
Q

SUVAT (UAM) Equations

A
  • Used to solve UAM problems (once you see a problem suggesting acceleration was constant, SUVAT comes to mind)
  • See packet (one w/ dividing by two and multiplying by t is used to find avg velocity)

t = time
v = final velocity
u = initial velocity
s = displacement/height
a(g) = acceleration

17
Q

Conditions necessary for UAM

A
  1. Constant acceleration (both the magnitude and the direction are constant).
  2. Velocity increases/decreases at a constant rate
18
Q

Rules for problems involving UAM

A
  1. An object in free fall has an acceleration of -9.8 ms^-2 (gravity always acts downward).
  2. If an object is accelerated from rest or dropped from a height, its initial velocity (u) is zero.
  3. For projectiles, speed (v) at max height is zero (stops momentarily before it starts coming down).
19
Q

Free-falling objects

A
  • An object falling under the sole influence of gravity
  • Doesn’t encounter air resistance
  • Same w/ object falling in a vacuum
  • Acceleration is -9.8 ms^(-2)—acceleration due to gravity/free fall acceleration
    *Acceleration constant, so same graphs as w/ UAM

NOTE [for illustration]:
- Time between two positions is the same
- Displacement increases sharply
- Velocity increases proportionately
- Acceleration is constant throughout

20
Q

Projectile motion

A
  • Involves only the force of gravity acting on the object (in the absence of air resistance [air resistance is negligible])
  • 2D (displacement in two different directions [vertical and horizontal])
    *Prior to now, all motion we’ve dealt w/ has been 1D (straight line)
  • Acceleration is acceleration due to gravity
  • Examples include: throwing a ball, fountains, fireworks, etc.
21
Q

Two components of projectile motion

A

Vertical:
- Not constant (acceleration/force present [accel due to gravity])
- Velocity at max height is 0
- Initial velocity is same as final but opposite

  • Vertical and horizontal components are independent of each other (in a perfect situation, where no air resistance is present)
  • What’s happening horizontally has no effect on what’s happening vertically

Horizontal:
- Velocity is constant (acceleration/net force = 0)

22
Q

Effects of air resistance on projectile

A
  • When air resistance is negligible, bigger (NOTE: for illustration, path is same until 1/4 or maybe 1/3 of the journey)
  • Range will be bigger
    *See equations (SUVAT)

NOTE:
- To calculate time during the journey, only vertical equations are used
- If an angle is involved multiply initial vertical velocity by sin theta and horizontal by cos theta (see illustration)?
- Range = horizontal velocity times cos theta times t
- Distance (range) depends on horizontal speed

23
Q

Terminal velocity

A
  • Air resistance not negligible
  • Velocity of an object when its weight is equal to the air resistance
  • As an object falls (under the influence of air resistance), the force of air resistance increases as the speed of the object increases
  • This situation continues until the air resistance force equals the weight of the object
  • Once this is achieved, the speed of the object becomes constant and the acceleration, in effect, becomes 0
    *Lighter = reaches terminal velocity faster
  • The speed, at this point, is known as terminal velocity
    *See graphs

*NOTE:
- The above also happens in the presence of water resistance
- During skydiving, the release of the parachute leads to the following:
1. increase in air resistance (due to larger surface area)—becomes larger than weight, so decceleration
2. decrease in speed
3. decrease in air resistance due to decrease in speed in order to balance again w/ gravity (air resistance and speed are directly proportional)
4. this balance leads to a second lower terminal velocity, with which the parachutist lands