MBG Flashcards

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1
Q

Wildtype Allele

A

A functional enzyme or other protein is produced

-Referred as a most common phenotype or genotype found in natural population

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2
Q

Loss of function allele

A

-an enzyme or protein is no longer produced

or it is produced at lower levels or nonfunctional

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3
Q

Biochemical definition of a Wildtype

A
  • the wildtype allele is dominant over the loss of function allele
  • half as much protein is synthesized yet this is often sufficient to achieve the wildtype phenotype
  • This is called halposufficiency
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4
Q

Haplosufficiency

A
  • Half as much protein is synthesized yet this is often sufficient to achieve wildtype phenotypes
  • half is enough, 1 copy is backup
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5
Q

not always is it that the dominant allele is normal and the recessive allele is a mutation

A

-Dominant alleles can be a gain of function mutations, in which the mutant allele produces a protein that has increased detrimental function

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6
Q

Dominant allele can be a loss of function alleles

A

-In the heterozygote half as much protein is synthesized and that is not enough for a normal phenotype-halposufficient (tailles cat)

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7
Q

Heterosis

A
  • When two different inbred lines are cross, the hybrids are heterozygous for many genes
  • These heterozygotes display heterosis, or hybrid vigor
  • Inbreed increases the frequency of homozygotes and decreases the frequency of heterozygotes.
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8
Q

Hardy Weinberg principle

A
  • Predicting genotypes through allele frequencies in a population
  • p+q=1 (when there are two alleles present, if there are three like in the ABO blood then it would be x+y+z=1)
  • p^2+2pq+q^2
  • 2pq= 1allele generated from mom or the same allele generated from the dad
  • The Hardy weinberg principle is used to predict genotype based on the allele frequency.
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9
Q

Conditions for the Hardy-Weinberg Principle

it is not valid if it is…..

A
  • Non random mating (we are sexual selective)
  • Unequal survival (due to enviromental forces)
  • Population division (1/4 is not a representation of a whole pop’n) it is not the rep of the whole gene pool
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10
Q

For problems with Hardy Weinberg

A
  • you are always give the allele frequency
  • allele frequency represents either the recessive gene (q) or dominant (p)
  • when you figure out what you have you can find the other variable p or q using this formula p+q=1
  • if it says what is a chance to be a carrier then it is 2pq
  • if there is a chance to be recessive then it is q^2
  • if the child is affected then use the punnet square with the carrier allele that you calculated and the chances of it being passed down (1/2)
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11
Q

Dosage compensation

A
  • It is a way of equalizing gene expression in the face of different gene dosage.
  • Humans are sensitive to gene dosage, we need only 2
  • If there are more than 2 in the autosomal/somatic chromosome then it will cause a miscarriage in the womb
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12
Q

How do the X and Y chromosomes pair even though they are not homologous?

A

-The X and Y chromosome are ONLY homologous at the PSEUDOAUTOSOMAL REGIONS, which are essential for X-Y pairing in a male in meiosis

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13
Q

X innactivation

A
  • in mammals not only females
  • Every cell chooses a random x to inactivate
  • unique of sex chromosomes
  • they are viable bc of the x inactivation
  • autosomal change means you die
  • inactivate the x chromosome bc of the dosage compensation
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14
Q

Lyon Hypothesis and X inactivation

A
  • Mary Lyon proposed the random inactivation of x chromosome
  • if a cell contains more than 2X chromosomes all but one of them are inactive
  • Condensed mass is called a Barr Body
  • XO have no Barr bodied, XXX have two barr bodies
  • They are HEMIZYGOUS for x linked genes
  • 50 percent express one alle and 50 precent of cells express the other allele
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15
Q

HEMIZYGOUS

A

Only one copy is present in a diploid organism

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16
Q

Polyploidy

A

Have more than 2 chromosomes in a set

17
Q

Aneuploidy

A

1 more or 1 less chromosome than you should have (45 or 47)