M8: Using Factors to Solve Quadratic Equations Flashcards

1
Q

What solving method would you use to solve this equation?

4x^2 + 4x + 1

A

To solve easily, use the box method.

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2
Q

(x+6) (x-4)

A

x^2+2x-24

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3
Q

(2x+5) (x-3)

A

2x^2-x-15

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4
Q

(x-6) (x+1)

A

x^2-5x-6

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5
Q

(x^2+3) (x-4)

A

x^3-4x^2+3x-12

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6
Q

(x^2+11) (x+6)

A

x^3+6x^2+11x+66

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7
Q

(x^2+8) (x-5)

A

x^3-5x^2+8x-40

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8
Q

(x+3) (x+7)

A

x^2+10x+21

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9
Q

(4x+2) (x-2)

A

4x^2-6x-4

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10
Q

(3x+2) (2x+5)

A

6x^2+19x+10

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11
Q

(x^2-6) (x-4)

A

x^3-4x^2-6x+24

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12
Q

(x^2+9) (x-3)

A

x^3-3x^2+9x-27

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13
Q

(4x^2-4) (2x+1)

A

8x^3+4x^2-8x-4

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14
Q

(x-3) (x^2+2x+1)

A

x^3+x^2-5x-3

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15
Q

(x+5) (x^3+6x^2+18x)

A

x^4+11x^3+48x^2+90x

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16
Q

(x+4) (x^4+x^2+1)

A

x^2+x^3+x

17
Q

Zero Product Property

A

set equation = to 0

18
Q

Diamond Method

A

Diamond shape where you multiply a and c together and put them at the top point of the diamond then b at the bottom. To find the numbers on the side you must find 2 numbers that multiply to ac and also add to b.

19
Q

What method should you use for the following equation : ax^2+bx+c

A

Diamond Method

20
Q

x^2 + x - 6 = 6

A
Answer is x= -4 x= 3
Steps:
x^2 + x - 12 = 0
(x + 4)(x - 3) = 0
x + 4 = 0  x-3 = 0
x = -4       x = 3
21
Q

x^2 - 3x - 5 = 5

A
Answer is x = -2   x = 5
Steps:
x^2 - 3x - 10 = 0
(x+2)(x-5)=0
x+2 = 0   x - 5 = 0
x= -2         x = 5
22
Q

36x^2 + 84x + 40 = -9

A
Answer is x = -7/6
Steps: 
(Squiggle Line Method)
36x^2 + 84x + 49 = 0 
~~~~                ~~~~
6x                      7
               42x
(6x+7)^2 = 0
6x + 7 = 0
6x = -7
x = -7/6
23
Q

4x^2 + 12x = -8

A
Answer is x = -1 ,  x = -2
Steps:
4x^2 + 12x + 8 = 0
4(x^2 + 3x + 2) = 0
4(x + 1) (x + 2) = 0
x + 1 = 0       x + 2 = 0
x = -1            x = -2
x = -1   ,  x = -2
24
Q

x^2 + 8x + 16 = 33

A
Answer is x = -23  x = -9
Steps:
8/2  = 4^2 = 16
x^2 + 8x + 16 = 49
(x + 4)^2  = 49
x+16 = +/- √49
x+ 16 = +/- 7
-16=        -16
x = -16 +/-7
x=-16-7         x=-16+7
x=-23             x=-9
25
Q

Steps to finding what equation to use

A
  1. Get Equation to 0
  2. Identify A,B,C
  3. Check if A and C are perfect squares
    ( If so we can apply our shortcuts)
  4. If A = 1 check if the reverse box method is possible
  5. If A is other than 1 try the diamond method
  6. Use completing the Square if there are negative numbers.
  7. Use the Quadratic formula when there are more fractions or positive numbers