M1, C4 - Elastic Collisions in 1 Dimension Flashcards

1
Q

What is the letter for the coefficient of restitution

A

e

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2
Q

What is the formula for the coefficient of restitution

A

speed of separation of particles / speed of approach of particles

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3
Q

What vales can e take

A

0 <= e <= 1

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4
Q

What is the value of e for perfectly elastic collisions

A

1

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5
Q

What is the value of e for perfectly inelastic collisions

A

0

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6
Q

What do you do with v1 and v2 to find the speed of separation of two particles if they are moving towards each other

A

v1 + v2

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7
Q

What do you do with v1 and v2 to find the speed of separation of two particles if they are moving away from each other
(given v2 > v1)

A

v2 - v1

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8
Q

What law do you often have to use along with coefficient of restitution to find answers

A

Conservation of linear momentum

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9
Q

Does the direction in momentum matter

A

YES, take velocities moving away from the +ve as -ve

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10
Q

P and Q with masses 3m and 4m move towards each other with speeds 3u and 2u. Coefficient of restitution = e. Floor is smooth and horizontal, show speed of Q after collision = u/7 * (15e + 1)

A

CLM:
(3m * 3u) + (4m * -2u) = (3m * -v) + (4m * w)
u = -3v + 4w
e:
e = (v + w) / (3u + 2u) –> 5eu = v + w
v = 5eu - w
Sub in:
u = -3(5eu - w) + 4w
u = -15eu + 3w + 4w
7w = 15eu + u
w = u/7 * (15e + 1)

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11
Q

You assumed v changed direction and therefore took it as -ve. Given that you were wrong and the direction of a particle remained unchanged, how do you find the possible values for e

A

Find an equation for v1
Make you v1 value negative (flip sign)

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12
Q

What equation for impulse should you use to find impulse if you know the speed before and after a collision for a particle

A

I = mv - mu

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13
Q

What is the equation for the coefficient of restitution for a particle colliding with a smooth wall

A

e = speed of rebound / speed of approach

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14
Q

For particles dropped against the ground, how do you find the speed of approach

A

Use SUVAT to find v
Take S as the distance to the ground

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15
Q

What is the formula for loss of KE

A

KE before collision - KE after collision
0.5 * m * ((u1^2 + u2^2) - (v1^2 + v2^2))

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16
Q

What 4 equation can we use with elastic collision equations

A

Impulse
Conservation of linear momentum
Loss of KE
e = v / u

17
Q

v = u/4 * (-3e + 1) where v is the assumed direction of motion after a collision. Show that if the direction of collision is reversed, e > 1/3

A

v < 0 as v is now -ve
0 > u/4 * (-3e + 1)
0 > -3eu + u
-u > -3eu
-1 > -3e
1/3 < e

18
Q

How can you find the total distance travelled by an infinitely bouncing ball before coming to rest

A

Use the sum to infinity formula
a / 1 - r
Where a is term 1 and r is the common difference
(be careful that the first fall is one lot of the distance but the subsequent bounces are 2 * the peaks)