M1, C4 - Elastic Collisions in 1 Dimension Flashcards
What is the letter for the coefficient of restitution
e
What is the formula for the coefficient of restitution
speed of separation of particles / speed of approach of particles
What vales can e take
0 <= e <= 1
What is the value of e for perfectly elastic collisions
1
What is the value of e for perfectly inelastic collisions
0
What do you do with v1 and v2 to find the speed of separation of two particles if they are moving towards each other
v1 + v2
What do you do with v1 and v2 to find the speed of separation of two particles if they are moving away from each other
(given v2 > v1)
v2 - v1
What law do you often have to use along with coefficient of restitution to find answers
Conservation of linear momentum
Does the direction in momentum matter
YES, take velocities moving away from the +ve as -ve
P and Q with masses 3m and 4m move towards each other with speeds 3u and 2u. Coefficient of restitution = e. Floor is smooth and horizontal, show speed of Q after collision = u/7 * (15e + 1)
CLM:
(3m * 3u) + (4m * -2u) = (3m * -v) + (4m * w)
u = -3v + 4w
e:
e = (v + w) / (3u + 2u) –> 5eu = v + w
v = 5eu - w
Sub in:
u = -3(5eu - w) + 4w
u = -15eu + 3w + 4w
7w = 15eu + u
w = u/7 * (15e + 1)
You assumed v changed direction and therefore took it as -ve. Given that you were wrong and the direction of a particle remained unchanged, how do you find the possible values for e
Find an equation for v1
Make you v1 value negative (flip sign)
What equation for impulse should you use to find impulse if you know the speed before and after a collision for a particle
I = mv - mu
What is the equation for the coefficient of restitution for a particle colliding with a smooth wall
e = speed of rebound / speed of approach
For particles dropped against the ground, how do you find the speed of approach
Use SUVAT to find v
Take S as the distance to the ground
What is the formula for loss of KE
KE before collision - KE after collision
0.5 * m * ((u1^2 + u2^2) - (v1^2 + v2^2))