Lecture 6 (Chris Allen) Flashcards

1
Q

What is the range for UV-visible light

A

200-800nm

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2
Q

What determines the specific wavelength at which a biological molecule absorbs UV light

A

It’s covalent structure

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3
Q

When is the molar extinction coefficient a constant

A

At a particular wavelength for a specific compound

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4
Q

What is the molar extinction coefficient related to

A

The absorbance at a specific wavelength.

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5
Q

Do absorbance and wavelength have a directly or inversely proportional relationship

A

Directly proportional.

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6
Q

What type of molecules are UV chromaphores

A
  • Molecules containing double bonds (aliens such as beta-carotene)
  • Aromatic compounds such as benzene
  • Contain a carboxylate group or ketone (carbonyl group) such as benzoin acid
  • Heterocyclic compounds such as indigo
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7
Q

How does conjugation affect absorption of UV light

A
  • Increases the absorption of UV light and shifts absorption toward the visible region.
  • Therefore, unsaturated bond conjugation (alkenes/aromatics) increase the extinction coefficient for particular molecules and shift the absorption maxima toward the visible (higher wavelengths) region.
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8
Q

How can UV spectroscopy be used to estimate the GC content of DNA

A
  • GC pairs are linked with three hydrogen bonds and AT pairs are linked with two hydrogen bonds.
  • Therefore the temperature at which DNA becomes single stranded will reflect the GC content.
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9
Q

How can UV Vis spectroscopy be used in enzyme assays

A
  • Many enzymes catalyse reactions with intermediates that can readily absorb light of these wavelengths.
  • By comparing the concentration of reactants/products in a spectrophotometer during a reaction, we can determine the rate of the reaction under certain conditions.
  • For example, consider: A + B ➡️ C + D
  • If D is the only chromaphore at a specific wavelength, then the rate of the reaction (and enzyme activity) can be measured by monitoring the concentration of D.
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