Lecture 15: Variations on Dominance Flashcards

1
Q

Explain Mendel’s Second law: 4

A
  1. “Law of dominance: one form of a gene masks the other (one allele is dominant, the other recessive)”

2, This is where our familiar 3:1 ratio comes from.

  1. The heterozygote possesses two alleles that affect a trait, but only one is displayed (the dominant one). Hence a heterozygote has the same phenotype as the homozygotes.
  2. But we all know life is not that simple:
    Some traits, especially non-discrete characteristics (e.g. height) do not fit Mendel’s simple laws of inheritance.
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2
Q

What is incomplete dominance/ partial dominance?

A

a form of Gene interaction in which both alleles of a gene at a locus are partially expressed, often resulting in an intermediate or different phenotype.

The genotypic and phenotypic ratios are the same! This is because each genotype has its own phenotype

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3
Q

AFTER LOTS OF Experimenation WHAT TWO CONCLUSIONS ON DOMINANCE WAS MADE?

A
  1. Dominance affects the phenotypes that genes produce, but NOT how genes are inherited.
  2. Dominance is established by observing the phenotype of heterozygous individuals.
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4
Q

Explaining Co-dominance; example?

A
  1. the heterozygous phenotype is NOT intermediate between that of the two homozygotes. Instead, the heterozygote expresses the phenotypes of BOTH homozygotes simultaneously.

Key example: ABO blood grouping
- Three major alleles i, IA, IB, which determine the presence of sugar molecules on the surface of red blood cells. These sugars act as antigens. Blood group incompatibility arises because adults produce antibodies opposite to their own antigen (e.g. blood group A makes anti-B antibodies).

  • IA and IB produce different sugars (blood groups A and B), whereas i gives none (blood group O).
  • An individual has two alleles that together give the four blood groups (phenotypes) from six different genotypes.
  • IA and IB are co-dominant over i because both A and B antigens are expressed simultaneously
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5
Q

DEFINITIONS: COMPLETE DOMINANCE, INCOMPLETE DOMINANCE, CODOMINANCE

A

COMPLETE DOMINANCE: Phenotype of the heterozygote is the same as the phenotype of one of the homozygotes.

INCOMPLETE DOMINANCE: Phenotype of the heterozygote is intermediate (falls within the range) between the phenotypes of the two homozygotes.

CODOMINANCE: Phenotype of the heterozygote includes the phenotypes of both homozygotes.

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6
Q

Dominance depends on the level of the observed phenotype: SICKLE CELL ANAEMIA = what is it, how it affects, the genetics (7)

A
  1. Sickle cell anaemia results from a mutation in the haemoglobin (Hb) gene (Chr 11)
  2. Most common mutant allele encodes single amino acid substitution in the β-globin gene, causing haemoglobin molecules to aggregate under low oxygen concentrations.
  3. Red blood cells deform and flow poorly in capillaries. Such cells are broken down.
  4. Anaemia results from decreased numbers of functional blood cells to carry oxygen.
  5. WT Hb allele = HbA, mutant Hb allele = HbS
  6. Sickle cell heterozygotes (“sickle cell trait”) express both forms of haemoglobin, A and S
  7. Due to different amino acid sequences, they migrate differently on a protein gel and can be identified

The key genotype is the heterozygote because:
At level of anaemia, HbA allele is dominant…
At level of blood cell shape, HbA is incompletely dominant… At level of haemoglobin, HbA and HbS are co-dominant!

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7
Q

Back to Cuénot’s mice..Why is this relevant to the concept of dominance?

A

Most lethal alleles are recessive: complete loss of an essential gene.

Dominant lethality should be impossible because both homozygotes and hets would die.

Is it possible to have a dominant lethal allele?

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8
Q

What makes an allele recessive or dominant?

Recessive mutant alleles vs Dominant mutant alleles.

A

1 * Remember: a mutant phenotype is defined by the normal or “wild type” (WT) phenotype

2 * Recessive mutant alleles normally result from loss of function or reduced function mutations e.g. premature stop codon leads to incomplete protein

3 * The WT counterpart of a loss-of-function allele is therefore the dominant allele

4 * Dominant mutant alleles often result from a gain of function mutations e.g. a mutation that leads to ectopic expression of the protein (wrong time or place), or a protein that interferes with the function of normal protein

5 * The WT counterpart of a gain-of-function allele is therefore the recessive allele

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9
Q

Explain Loss-of-function recessive alleles

A

When a heterozygote consists of the wild-type allele and the loss-of-function allele, the level of expression of the wild-type allele is often sufficient to produce the wild-type phenotype.

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10
Q

Loss-of-function recessive alleles
* Mendel’s peas: hypothesis, What is the causative mutation for the green phenotype

A
  • Mendel’s peas: yellow (Y) is dominant to green (y): Yy is yellow
  • Pea seeds are green when immature, and normally turn yellow when mature and dry
  • Therefore Yellow is wild type and Green is mutant

HYPOTHESIS: The y allele is a loss-of-function recessive mutation because green seeds
lack something required to turn them yellow.

What is the causative mutation for the green phenotype?

The yy green phenotype results from mutations that affect the expression of a gene
called STAYGREEN (SGR).

SGR encodes an enzyme that breaks down chlorophyll (Chl). Some y alleles result from mutations that lead to amino acid substitutions or insertions in the SGR enzyme, so becoming non-functional.
Chl not degraded -> seeds stay green.

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11
Q

Explain: Gain of function dominant alleles

A

mutations that result in elevated levels of gene activity.

Any heterozygote containing the new allele along with the original wild-type allele will express the new allele

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12
Q

Gain-of-function dominant alleles: (3) Antennapedia (Antp)

A
  • Antennapedia (Antp) encodes a homeobox transcription factor that specifies segment identity (leg development)
  • In dominant Antp mutants, gene is ectopically expressed in head region of embryo – the “gain of function” – and legs form in place of antennae.
  • Mutation in control of Antp expression.
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13
Q

Other reasons for the dominance:
Haploinsufficiency

Dominant negative

A
  • Haploinsufficiency: this is a special case of loss-of-function – one functional gene is not enough.
    NOTE: here, a loss-of- function allele is dominant!
  • Recessive alleles are almost always loss-of-function alleles, but the reverse is not always true (e.g. haploinsufficiency).
  • Dominant negative: a mutant protein disrupts the function of the normal protein
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14
Q

Characteristics of dominance: 3

A
  1. Dominance is allelic interaction: a result of interactions between DNA variants at the same locus.
  2. In turn, allelic dominance comes about through the gene products interacting with each other.
  3. Classification of dominance depends on the level at which the phenotype is examined.
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15
Q

New concepts: Penetrance and Expressivity:
COMPLETELY PENETRANT

INCOMPLETE PENETRANCE

A
  1. Many traits show complete correspondence between genotype and phenotype e.g. ABO blood groups. Given the genotype, we can predict the phenotype with 100% accuracy. The phenotype is said to be ***completely penetrant.
  2. Sometimes, there is not a perfect correspondence between genotype and phenotype – individuals with the same genotype may have different phenotypes: incomplete penetrance.

Example: polydactyly…

Many traits show complete correspondence between genotype and phenotype e.g. ABO blood groups. Given the genotype, we can predict the phenotype with 100% accuracy. The phenotype is said to be ***completely penetrant.

Sometimes, there is not a perfect correspondence between genotype and phenotype – individuals with the same genotype may have different phenotypes: ***incomplete penetrance.

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16
Q

Penetrance and Expressivity

What is expressivity?

What is penetrance?

A
  1. Penetrance is thus the proportion of individuals with a specified genotype that express the expected phenotype
    e.g. if 50 people have the dominant allele for polydactyly, but only 45 are polydactylous, the penetrance is 45/50 = 90%
  2. Expressivity is the degree to which a variable phenotype is expressed i.e. the phenotypic intensity.

In polydactyly, some people might have complete extra digits, some might only have partial digits.

17
Q

Why might alleles show incomplete penetrance and/or variable expressivity? (3)

A
  1. The influence of the environment
    – Individuals with the same genotype may show a range of phenotypes, depending on the environment (e.g. period of drought for plants, fetal nutrition)
  2. The influence of other interacting genes
    – Unknown enhancers/suppressor genes or epistatic genes in the rest of the genome may affect phenotypic expression. Also polygenic traits.
  3. The subtlety of the mutant phenotype
    – A weak phenotype may be difficult to score in a laboratory or medical setting.
18
Q

In rabbits, floppy ears are inherited as a recessive trait with 80% penetrance. In a cross between two heterozygous rabbits, what proportion of the offspring would have floppy ears?

A

Cross is Ff × Ff
Need ff progeny, so f gamete from each parent
1⁄2 × 1⁄2 × 80% = 20%

So 25% would have the genotype, but only 20% express the phenotype!

19
Q

What blood types are possible among the children of a man of type A and a woman of type B?

A

There are nine ways of obtaining six possible genotypes that give rise to four different phenotypes in varying proportions. This result comes about from co- dominance and three alleles interacting with each other.

20
Q

In a maternity ward, four babies become accidentally mixed up. The ABO types of the four babies are known to be O, A, B and AB. The ABO types of the four sets of parents are determined. Indicate which baby belongs to each set of parents:

A

To determine which baby belongs to each set of parents, we can use the principles of ABO blood types and inheritance.

a) ABxO:
- Baby with blood type AB can only belong to parents who have at least one A and one B allele. Therefore, the parents must both have either blood type AB or blood type A and B.
- Baby with blood type O can only belong to parents who both have the O allele. Therefore, the parents must both have blood type O.
- Based on this, we can conclude that the baby with blood type AB belongs to the parents who have blood type AB.

b) AxO:
- Baby with blood type A can belong to parents who have blood type A or blood type O.
- Baby with blood type O can belong to parents who have blood type O.
- Based on this, we cannot definitively determine which baby belongs to this set of parents as both babies A and O could potentially belong to them.

c) AxAB:
- Baby with blood type A can belong to parents who have blood type A or blood type O.
- Baby with blood type AB can only belong to parents who have at least one A and one B allele. Therefore, the parents must both have either blood type AB or blood type A and B.
- Based on this, we can conclude that the baby with blood type AB belongs to the parents who have blood type AB.

d) OxO:
- Baby with blood type O can only belong to parents who both have the O allele. Therefore, the parents must both have blood type O.
- Based on this, we can conclude that the baby with blood type O belongs to the parents who have blood type O.

In summary:
a) ABxO: Baby with blood type AB belongs to the parents with blood type AB.
b) AxO: It is not possible to definitively determine which baby belongs to these parents.
c) AxAB: Baby with blood type AB belongs to the parents with blood type AB.
d) OxO: Baby with blood type O belongs to the parents with blood type O.

21
Q

Two normal-looking fruit flies were crossed, and in the progeny, there were 202 females and 98 males.
a) What is unusual about this result?
b) Provide a genetic explanation for this anomaly.
c) Provide a test of your hypothesis.

A

a) What is unusual about this result?
The unusual aspect of this result is the significantly skewed sex ratio in the progeny. In most cases, fruit fly populations exhibit a roughly equal proportion of males and females.

b) Provide a genetic explanation for this anomaly.
The sex determination system in fruit flies is based on the presence of sex chromosomes. Females have two X chromosomes (XX), while males have one X and one Y chromosome (XY). The gene responsible for determining maleness is located on the Y chromosome. If there is a mutation or deletion in the region of the Y chromosome that carries this gene, it can lead to a higher proportion of female offspring in the progeny.

c) Provide a test of your hypothesis.
To test the hypothesis of a Y chromosome mutation or deletion, further breeding experiments can be conducted. One approach is to perform a backcross, where the male offspring from the initial cross (98 males) are mated with wild-type females. If the skewed sex ratio is due to a Y chromosome mutation, the male offspring should pass on the mutation to their progeny, resulting in a similar skewed sex ratio. Another test could involve examining the chromosomes of the male offspring using techniques like karyotyping or fluorescent in situ hybridization (FISH) to detect any structural abnormalities in the Y chromosome. These tests can provide evidence supporting or refuting the hypothesis of a genetic anomaly affecting sex determination in fruit flies.

22
Q

The type of plumage found in mallard ducks is determined by three alleles at a single locus: MR, which encodes restricted plumage; M, which encodes mallard plumage; and md, which encodes dusky plumage. The restricted phenotype is dominant over mallard and dusky; mallard is dominant over dusky (MR > M > md).
Give the expected phenotypes and proportions of offspring produced by the following crosses:

a) MRM × mdmd
b) MRmd×Mmd
c) MRmd × MRM
d) MRM × Mmd

A

a) MRM×mdmd –1⁄2R,1⁄2M
b) MRmd×Mmd–1⁄2R,1⁄4M,1⁄4d
c) MRmd×MRM–3⁄4R,1⁄4M
d) MRM×Mmd –1⁄2R,1⁄2M