Lecture 14 Flashcards
Implicit functions and differentiation, local linearization
1
Q
what is the derivaitive of tan?
A
sec^(2)(x)
2
Q
why is it impossible to express a circle as a single equation?
A
because each x value produces two y values
3
Q
why does the expression for the derivative at a point must depend on both x and y on a circle?
A
because the equation is in terms of both x and y
4
Q
what are the steps to differentiate implicitly?
A
- write d/dx on both sides of the equation
- find the derivative of both sides of the equation
- collect like terms on each side
- factor out y’
- isolate for y’
5
Q
how do you find the horizontal tangent on an implicit function?
A
- find the derivative
- set the derivative equal to zero
- solve for the x value(s)
6
Q
how do you find the verticle tangent on an implicit function?
A
- find the derivative
- set the denominator of the derivative equal to zero
- solve for the y value
7
Q
how do you estimate the y value given and the x value and an implicit function?
A
- find the derivative of the implicit function
- plug the x value into the derivative to find the slope
- plug the x value into the original function to create a point
- use the slope, point and linearization formula to create the approximation equation
- plug in the x value of interest into the approximation equation to get the answer