L/D 2: Membrane & Action Potentials Flashcards
what does a negative membrane potential signify? which direction is the force on cations? anions?
inside is lower potential than outside
force on cations is inward
force on anions is outward
what does a positive membrane potential signify? which direction is the force on cations? anions?
inside is higher potential than outside
force on cations is outward
force on anions is inward
[K+] in = 100 mEq/L
[K+] out = 10 mEq/L
and K+ is at equilibrium distribution,
what is Vm?
Vm = Ek = -61log(100/10)
= -61 mV
If you know Vm and various in vs out ion concentrations of a cell membrane, how do you determine if the net force on an ion is inward, outward, or equilibrium?
2 possible ways: -calc net driving force for the ion (Vm-Ei) Ei = -(61/z)log(in/out) -calc electrochemical potential of ion ∆μ = 61log(in/out) + zVm
if DF or ∆μ is negative, cats in ans out if DF or ∆μ is positive, cats out ans in if DF or ∆μ is 0, no net movement *DF and ∆μ always have same sign... ...they differ by factor of z
at 20 degrees C, equilibrium potential of an ion =
Ei = -58/z log(in/out)
at 37 degrees C, equilibrium potential of an ion =
Ei = -61/z log(in/out)
in physiological temperature, equilibrium potential of an ion =
Ei = -61/z log(in/out)
at (British) room temperature, equilibrium potential of an ion =
Ei = -58/z log(in/out)
how is the VGNa+ channel a-gate opened?
depolarization (+ charges on inner membrane) force + residues of the a-gate (on the inner side of the gate) apart
is the VGNa+ channel a-gate nearer the internal or external side of the membrane?
internal
when does the VGNa+ channel i-gate bind the channel?
after a delay, the i-gate binds the open a-gate
when does the VGNa+ channel i-gate release the channel?
only after repolarization closes the a-gate
how does the VGNa+ channel i-gate interact with the a-gate?
binds a-gate when open
releases a-gate when closed
how is the peak of an AP affected when external [Na+] is reduced? why?
peak decreases
because Ena = -61/z log(in/out) is decreased,
so DF = Vm-Ena is decreased,
and less driving force drives less Na+ through VGNa+ channels
how is the peak of an AP affected when internal [Na+] is increased?
peak decreases
because Ena = -61/z log(in/out) is decreased,
so DF = Vm-Ena is decreased
and less driving force drives less Na+ through VGNa+ channels