Kp [P2] PAPER 1 Flashcards

1
Q

How to calculate partial pressure?

A

partial pressure = mole fraction x total pressure

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2
Q

how to calculate the mole fraction of a substance?

A

mole fraction of substance = moles of substance / total moles

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3
Q

effect of a catalyst on the value of Kp of a reaction?

A

• no effect
• catalysts increase the rates of the forwards and backwards reactions equally

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4
Q

Kp equation?

A

p = partial pressure of __ in the equilibrium mixture

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5
Q

What affects the value of Kp?

A

temperature

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6
Q

A reaction is endothermic. What happens to the value of Kp for this reaction if the temperature is increased?

A

• value of Kp increases
• equilibrium shifts to the right in the endothermic direction to oppose the increase in temperature, causing the partial pressures of [products] to increase, while the partial pressures of [reactants] decreases

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7
Q

A reaction is exothermic. What happens to the value of Kp for this reaction if the temperature is increased?

A

• value of Kp decreases
• equilibrium shifts to the left in the endothermic direction to oppose the increase in temperature, causing the partial pressures of [reactants] to increase, while the partial pressures of [products] decreases

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8
Q

A reaction is endothermic. What happens to the value of Kp for this reaction if the temperature is decreased?

A

• the value of Kp decreases
• equilibrium shifts to the left in the exothermic direction to oppose the decrease in temperature, causing the partial pressures of [reactants] to increase, while the partial pressures of [products] decreases

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9
Q

A reaction is exothermic. What happens to the value of Kp for this reaction if the temperature is decreased?

A

• value of Kp increases
• equilibrium shifts to the right in the exothermic direction to oppose the decrease in temperature, causing the partial pressures of [products] to increase, while the partial pressures of [reactants] decreases

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10
Q

Calculating the units of Kp?

A

Same as how Kc units are calculated, except using kPa, e.g.

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11
Q

For a reaction, at 1050K, Kp = 762000Pa, and at 500K, Kp = 39400Pa.

Explain how this information can be used to deduce that the forward reaction is endothermic

A

• the value of Kp is higher at a higher temperature
• So, at a higher temperature, equilibrium must shift to the right

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12
Q

given the Kp value of equation 1, what is the Kp of equation 2? Give the value and units.

A
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