group 7 [I1] PAPER 1 Flashcards

1
Q

trend in electronegativity down group 7 and why?

A

• decreases down group
• more shells, so more shielding
• weaker attraction between the nucleus and pair of electrons in the covalent bond

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2
Q

trend in atomic radius down group 7 and why?

A

• increases down group
• more shells
• bigger atom

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3
Q

trend in melting and boiling points down group 7 and why?

A

• increases
• more electrons
• molecule gets bigger
• more van der Waals’ forces between the molecules
• more energy required to overcome these forces

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4
Q

trend in first ionisation energy down group 7 and why?

A

• decreases down group
• more shells, so more shielding
• weaker attraction between nucleus and outer electron

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5
Q

trend in oxidising power down group 7 and why?

A

• decreases down group
• atomic radius increases, so gets larger
• more shielding
• weaker forces of attraction between nucleus and electron to be gained

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6
Q

what does the relative oxidising strengths of the halogens give them the ability to do?

A

• displace one another
• Cl2 will displace both Br- and I- ions
• Br2 will displace I- ions
• I2 won’t displace any halide ions
• what happens to each thing can be written as half equations

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7
Q

what is oxidising power?

A

ability to gain an electron

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8
Q

trend in reducing ability of halide ions and why?

A

• increases down group
• more shielding
• atomic radius increases
• weaker attraction between outer electron that is lost and the nucleus

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9
Q

equation, reaction type and observations for the reaction between solid NaF / NaCl and conc. sulfuric acid?

A

• NaF + H2SO4 → NaHSO4 + HF
• NaCl + H2SO4 → NaHSO4 + HCl
• steamy fumes
•reaction type - acid-base

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10
Q

equations, reaction types and observations for the reaction between solid NaBr and conc. sulfuric acid?

A
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11
Q

equations, reaction types and observations for the reaction between solid NaI and conc. sulfuric acid?

A
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12
Q

ability of halide ions to reduce sulfuric acid?

A
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13
Q

how to test for halide ions?

A

• add silver nitrate solution that has been acidified by dilute nitric acid (acidified to remove ions that may interfere with results, so result in false positive results)
• chloride ions produce a white precipitate (AgCl)
• bromine ions produce a cream precipitate (AgBr)
• iodide ions produce a yellow precipitate (AgI)

to distinguish between the precipitates:
• AgCl dissolves in dilute ammonia
• AgBr dissolves in conc. ammonia
• AgI doesn’t dissolve any ammonia solution

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14
Q

equation for the reaction of chlorine with water?

A

Cl2 + H2O ⇌ HCl + HClO

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15
Q

equation for the reaction of chlorine with water, in the presence of UV light?

A

2Cl2 + 2H2O ⇌ 4HCl + O2

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16
Q

equation for the reaction between cold, aqueous NaOH and chlorine, and use of the product formed?

A

sodium chlorate (I) solution is an ingredient of bleach and used to disinfect

17
Q

Chlorine is used to treat water, despite being toxic to humans. Why is water treated with chlorine, and why is it used, despite the toxicity?

A

• sterilises water
• health benefit outweighs the risk and it is only used in small quantities/low concentrations

18
Q

What is observed when silver nitrate solution is added to sodium fluoride solution?

A

Colourless solution

19
Q

What is the role of (1) halide ions and (2) sulfuric acid when reacting with conc. sulfuric acid to form NaH2SO4 and HX [X = halogen]?

A

(1) base / proton acceptor
(2) proton donor

20
Q

Halide ions reactions and observations (no organic solvent)

A
21
Q

Halide ions reactions and observations (with organic solvent)

A
22
Q

Explain why some of the reactions that occur when sodium bromide/iodide react with conc. sulfuric acid are redox reactions.

A

• Br/I changes oxidation state from -1 to 0 and is oxidised
• S changes oxidation state from +6 to +4/0/-2 and is reduced

23
Q

Explain why bromide ions react differently from chloride ions

A

• Bromide ions are bigger than chloride ions
• So, bromide ions are more easily oxidised

24
Q

A colourless solution contains a mixture of sodium bromide and sodium chloride.

Using aqueous silver nitrate and any other reagents of your choice, develop a procedure to prepare a pure sample of silver bromide from this mixture.

Explain each step in the procedure and illustrate explanations with equations, where appropriate.

A

• Add silver nitrate to form precipitates of AgCl and AgBr:
– AgNO3 + NaCl → AgCl + NaNO3
– AgNO3 + NaBr → AgBr + NaNO3
• Add an excess of dilute ammonia to the mixture of precipitates to dissolve the AgCl precipitate:
– AgCl + 2NH3 → Ag(NH3)2+ + Cl-
• Filter off the remaining silver bromide precipitate
• Wash to remove soluble compounds
• Dry to remove water

25
Q

A solution of sodium chlorate(l) was added to a colourless solution of potassium iodide.

Suggest what is observed.

Explain the reaction that leads to this observation.

A

Goes brown due to iodine, because iodide ions are oxidised.

26
Q

State which gas produced in the reaction between solid NaI and conc. H2SO4 smells gross

A

hydrogen sulfide (H2S)

27
Q

Equation for the addition of ammonia to AgX precipitate when testing for halide ions with silver nitrate solution and ammonia?

[X = halogen]

A

AgX + 2NH3 → Ag(NH3)2+ + X-

28
Q

Suggest a disadvantage of treating water with chlorine.

A

• Wasteful as most potable water isn’t used for drinking
• Some people suffer eye irritation
• Some people find the taste unpleasant
• Can react with organic compounds to produce harmful substances

29
Q
A