Kinetics Flashcards

1
Q

Requirements for collision to result in a reaction

A

1) sufficient collision energy to meet activation energy
2) correct collision orientation

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2
Q

Activation energy is

A

collision energy to break bonds and produce a reaction.

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3
Q

Graphically, activation energy is

A

the energy from the reactants to the top of the hill.

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4
Q

When looking at an elementary step, the rate law can be determined from

A

the coefficients

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5
Q

Rate constant (k) units formula

A

M1-n • time-1

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6
Q

Graph to linearize 0th order

A

[concentration] vs. time
Slope equals –k

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7
Q

Graph to linearize 1st order

A

ln[concentration] vs. time
Slope equals –k

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8
Q

Graph to linearize 2nd order

A

1/[concentration] vs. time
Slope equals k

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9
Q

Ways to speed up reaction

A

1) Increase reactant concentration (increases number of collisions unless 0th order)

2) Add catalyst (lowers activation energy)

3) Increase surface area of solid (increases number of collisions)

4) Decrease volume of gas to increase pressure (increases number of collisions)

5) Increase temperature (increases number of collisions AND collision energy)

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10
Q

Catalysts lower activation energy by

A

providing a different reaction mechanism.

Note: Catalysts are NEVER consumed in the overall reaction. They are used in an early step and remade in a later step.

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11
Q

Nuclear decay of radioisotopes follows __________ order kinetics.

A

1st

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12
Q

Reaction order with a constant half-life

A

1st

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13
Q

Greater activation energies correspond to _________ reactions.

A

Slower

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14
Q

On a reaction energy diagram, the ___________ hill represents the slowest step.

A

Tallest

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15
Q

Which elementary step in a reaction mechanism determines the rate law?

A

Slowest step/rate-determining step

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16
Q

How do you determine the rate law of a reaction based on a reaction mechanism?

A

Coefficients of slowest elementary step

17
Q

Intermediates ________ in an early step and _______ in a later step.

A

made: used

18
Q

The concentrations of intermediates are usually

A

Extremely low due to instability

19
Q

What do we generally try to remove from a rate law based on a reaction mechanism?

A

Intermediates

20
Q

How do we remove an intermediate from a rate law?

A

Use a previous fast equilibrium/fast reversible step

21
Q

Catalysts are _______ in an early step and ______ in a later step.

A

Used: made

22
Q

Catalysts ___________ be used in a rate law.

A

CAN