Key Topic 4: Resistance, Capacitance, & Inductance Flashcards
3-4A1: What formula would calculate the total inductance of inductors in series?
A. Lt = L1 / L2
B. Lt = L1 + L2
C. Lt = 1 / L1 + L2
D. Lt = 1 / L1 x L2
B. Lt = L1 + L2
3-4A2: Good conductors with minimum resistance have what type of electrons?
A. Few free electrons.
B. No electrons.
C. Some free electrons.
D. Many free electrons.
D. Many free electrons.
3-4A3: Which of the 4 groups of metals listed below are the best low-resistance conductors?
A. Gold, silver, and copper.
B. Stainless steel, bronze, and lead.
C. Iron, lead, and nickel.
D. Bronze, zinc, and manganese.
A. Gold, silver, and copper.
3-4A4: What is the purpose of a bypass capacitor?
A. It increases the resonant frequency of the circuit.
B. It removes direct current from the circuit by shunting DC to ground.
C. It removes alternating current by providing a low impedance path to ground.
D. It forms part of an impedance transforming .circuit.
C. It removes alternating current by providing a low impedance path to ground.
3-4A5: How would you calculate the total capacitance of three capacitors in parallel?
A. Ct = C1 + C2 / C1 - C2 + C3
B. Ct = C1 + C2 + C3
C. Ct = C1 + C2 / C1 x C2 + C3
D. Ct = 1 / C1 + 1 / C2 + 1 / C3
B. Ct = C1 + C2 + C3
3-4A6: How might you reduce the inductance of an antenna coil?
A. Add additional turns.
B. Add more core permeability.
C. Reduce the number of turns.
D. Compress the coil turns.
C. Reduce the number of turns.