JOVD 2015 #3: The Influence of Crown Height to Diameter Ratio on the Force to Fracture of Canine Teeth in Dogs Flashcards
Authors?
Jason W. Soukup, DVM
Caitlyn Collins, MS;
Heidi-Lynn Ploeg, PhD
Aim of this study?
To investigate the influence of H/D on force to fracture and probability of fracture of canine teeth in dogs.
Prevalence of dental fracture in dogs?
The prevalence is reported to be as high as 27% .
According to literature, which of the following is false?
A) The prevalence of dental fracture in domestic dogs is 27%.
B) The most commonly fractured tooth in dog is the canine tooth with a reported frequency between 25 to 37%.
C) Canine tooth are more vulnerable to fracture due to their prominent rostral position in the oral cavity, their used as apprehension and defense and their morphology (in particular crown height (H) to base diameter (D) ratio (H/D)).
D) Finite element model revealed an inverse relationship between tooth height and both tooth strenght and fracture resistance in wild canivores.
B) is partialy false since the most commonly fractured tooth in the dog is the canine tooth with a reported frequency between 35.5% and 57.1%.
Orignal Study
Study design?
- 30 canine teeth from Beagle
- 3 groups:
- Group A: unaltered H/D
- Group B: 10% reduction in H/D
- Group C: 20% reduction in H/D
- Teeth potted in clear autopolymerizing orthodontic acrylic; placed in a universal materials testing machine.
- Force applied at speed of I-mm/min to the distoocclusal line angle at an angle of 45° to the long axis of the crown.
- Force to fracture (FF) = maximum measured force at time of fracture
To what correspond the following terms:
- Expected Force (FE)
- Margin of safety (MoS)
- Paired MoS
- Biting-pulling force expected on canine teeth (FE) (for 1 canine tooth = ½ FE) (obtained from previous study)
- Margin of safety (MoS) = FF - FE (for 1 canine tooth used ½ FE) = probability of fracture of a canine tooth when subjected to typical biting- pulling forces. (more MoS in hight, less chance of fracture)
- Paired MoS = impact of a 20% H/D reduction of a single maxillary canine on the fracture probability of the unaltered contralateral canine
How would you define “moment” ?
- Moment:
- amount of stress on a tooth when a load is placed near the cusp
- M = F x a
M=moment; F=force; a=moment arm (= crown height when force applied perpendicular to long axis of tooth)
Why was tissue volume calculated?
-
Hard tissue volume
- Used to minimize the variability in the size of the teeth
- = total crown volume – pulp chamber volume
- total crown volume calculated using formula for right elliptical cone V= πab(h/3); V = volume, a = minor base diameter, b = major base diameter, and h = crown height.
- Pulp chamber volume calculated using formula for a cone V=1/3(πr2h); V = volume, r = pulp chamber radius, and h = pulp chamber height
How H/D ratio of canine tooth influence its probability to fracture?
-
MoS (probability of canine tooth to fracture)
- Group A (unaltered): 36.7%;
- Group B (10% decrease in H/D): 27.8%;
- Group C (20% decrease in H/D): 14.5%
- 10% decrease in H/D decreased probability of fracture by 24.1%;
- 20% decreased in H/D decreased probability of fracture by 60.4% compared to unaltered teeth.
Which of the following statement is false
A) “Factor Safety” refer to the ratio between the force required to cause a structure to fail and the force that the structure is expected to withstand in routine use.
B) Zoological studies of wild canid and felid dentition present the hypothesis that the factor of safety is larger in biological structures when their failure is associated with greater consequences.
C) Given that fractured teeth do not have the ability to repair themselves afterfracture, teeth should possess a high factor of safety that would allow teeth to withstand high forces.
D) Similar to a factor of safety calculation, the present study utilized aMoS analysis to compare the normal distributions of a structure’s strengtht of the expected loads and determine the probability of failure of the structure.
E) According to the MOS analysis of this study, the factor of safety of canine tooth of domestic dog is high.
E) is false
The probability of fracture of a canine tooth when subjected to typical biting- pulling forces = Margin of safety (MoS) = FF - FE (for 1 canine tooth used ½ FE) )
The MoS in the unaltered group A is 36.7%; so, probability of fracture of a canine tooth when subjected to typical biting-pulling forces of canine tooth in domestic dogs is considered low; so, typical force applied to the canine teeth during routine activity is probably less than that required to fracture the tooth in most dogs.
.
What is the influence of H/D ratio of a canine tooth when expected biting-pulling force is distributed across 2 canine teeth according to their relative heights?
-
Paired MoS analysis
- = probability of fracture of a canine tooth and its contralateral canine tooth when expected biting-pulling force was distributed across 2 canine teeth according to their relative heights
- 20% H/D reduction of one canine tooth reduced its probability of fracture by 86.5%, however, it increases by 54.4% the probability of fracture of the unaltered contralateral canine tooth.
- efforts to improve the biomechanics of a single tooth by altering H/D may have a negative influence on the biomechanics on the entire oral cavity.
Is there a canine height at which the canine is not at risk to fracture during a bitin-pulling exercice?
It is plausible that canine teeth of any height may fracture under the forces that dogs can generate during biting-pulling exercises.
In which of the following situation the canine teeth are less prone to fracture?
A) When biting force in directed occlusally
B) When trumatic force is directed mesio-distaly
C) When biting-pulling forces is directed disto-mesialy
A) ; Canine teeth do not fracture under occlusally directed masticatory loads; canine teeth more often fracture due to a frontally-mediated traumatic force or biting-pulling forces
What are the mean forces required to fracture teeth of each group?
-
mean FF:
- group A : 494 N;
- group B: 573 N;
- group C: 630 N
- 10% reduction in H/D increased µF by 78.8 N compared to the unaltered teeth;
- 20% reduction in H/D increased µF by 136 N compared
Does the H/D of canine tooth is solely responsible for the variance in force to fracture found in this study?
No
Only 13.8% of the variance in force to fracture found in this study could be explained by H/D alone; therefore, other factors must contribute to the fracture resistance of the tooth such as mechanical properties (e.g., modulus of elasticity, hardness, toughness), differences in hard tissue volume, and other unknown factors.