intro to mechanisms Flashcards

1
Q

homolytic fission

A

each atom gets one electron from the covalent bond

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2
Q

what does a one headed arrow show?

A

movement of one electron

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3
Q

free radical

A

reactive species which possess an unpaired electron. free radicals do not have a charge and are represented by a dot

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4
Q

what happens when a bond breaks by homolytic fission?

A

forms two free radicals

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5
Q

heterolytic fission

A

one atom gets both electrons

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6
Q

what does a two headed arrow show?

A

movement of a pair of electrons

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7
Q

what does heterolytic fission produce

A

ions

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8
Q

why do we use curly arrows?

A

we use curly arrows in mechanisms to show the movement of an electron pair showing either breaking or formation of a covalent bond

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9
Q

where does a curly arrow start?

A

always from a lone pair of electrons or the centre of a bond

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10
Q

where will electrons move from

A

more negative areas to more positive areas

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11
Q

where can pairs of electrons be found

A

lone pairs or covalent bonds

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12
Q

addition

A

adding atoms onto a molecule

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13
Q

elimination

A

taking away atoms from a molecule

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14
Q

substitution

A

swapping atoms

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15
Q

oxidation

A

adding oxygen

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16
Q

reduction

A

removing oxygen

17
Q

hydrolysis

A

splitting water, or splitting another molecule using water

18
Q

polymerisation

A

joining many small molecules together

19
Q

types of reaction/mechanism

A

addition
elimination
substitution
oxidation
reduction
hydrolysis
polymerisation

20
Q

what condition is needed in free radical substitution

21
Q

why dont alkanes generally react with many reagents

A

the C-C bond and the C-H bond are relatively strong

22
Q

free radical substitution steps

A

initiation
propagation
termination

23
Q

step one: initiation

A

essential condition: UV light
e.g. Cl2 = 2Cl*

24
Q

what does the UV light do?

A

supplies energy to break the e.g. Cl-Cl bond. it is broken in preference to others as it is the weakest
UV light doesn’t have enough energy to break the C-H bond

25
Q

step two: propagation

A

all propagation steps have a free radical in the reactants and the products
e.g. CH4 + Cl* = HCl + CH3*
CH3* + Cl2 = CH3Cl + Cl*

26
Q

step three: termination

A

collusion of two free radicals does not generate further free radicals, the chain is terminated
e.g. CH3* + Cl* = CH3Cl
CH3* + CH3* = CH3CH3 (write this step using structural not molecular formulae)
Cl* + Cl* = Cl2