Integration Flashcards

1
Q

Basic integration

A

∫ π‘Žπ‘₯ⁿ 𝑑π‘₯ =
[π‘Žπ‘₯ⁿ⁺¹] / [𝑛+1] + 𝑐 , 𝑛 β‰  βˆ’1

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2
Q

Properties of indefinite integral (3)

A

∫[𝑓(π‘₯) + 𝑔(π‘₯)] 𝑑π‘₯ = ∫ 𝑓(π‘₯) 𝑑π‘₯ + ∫ 𝑔(π‘₯) 𝑑π‘₯
∫[𝑓(π‘₯) βˆ’ 𝑔(π‘₯)] 𝑑π‘₯ = ∫ 𝑓(π‘₯) 𝑑π‘₯ βˆ’ ∫ 𝑔(π‘₯) 𝑑π‘₯
∫ π‘˜π‘“(π‘₯) 𝑑π‘₯ = π‘˜ ∫ 𝑓(π‘₯) 𝑑π‘₯ π‘˜ = constant

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3
Q

The definition of a definite integral

A

βˆ«α΅‡β‚ 𝑓(π‘₯) 𝑑π‘₯ = [𝐹(π‘₯)]ᡇₐ = 𝐹(𝑏) βˆ’ 𝐹(π‘Ž)

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4
Q

Integral properties

A

βˆ«α΅‡β‚ 𝑓(π‘₯) 𝑑π‘₯ = – βˆ«α΅ƒα΅¦ 𝑓(π‘₯) 𝑑π‘₯
βˆ«α΅ƒβ‚ 𝑓(π‘₯) 𝑑π‘₯ = 0

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5
Q

Integration of exponential functions 𝑒ˣ

A

∫eˣ dx = eˣ + c
∫eᡏˣ dx = 1/k eᡏˣ + c , k β‰  0

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6
Q

Integration of reciprocal 1/π‘Žπ‘₯+b

A

∫1/π‘₯ 𝑑π‘₯ = 𝑙𝑛|π‘₯| + 𝑐 , π‘₯ β‰  0

Take any constants out in their form
eg
5/x becomes 5ln|x|+ c
1/5x becomes 1/5ln|x|+ c

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7
Q

Special cases for trig integration

A

∫sinΒ²(x) dx = x/2 – 1/4 sin(2x) + c
∫cos²(x) dx = x/2 + 1/4 sin(2x) + c

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8
Q

The trapezium rule

A

Area of Trapezium = ([π‘Ž+𝑏]/2) Γ— β„Ž

The trapezium rule with 𝑛 intervals states that
βˆ«α΅‡β‚ 𝑓(π‘₯) 𝑑π‘₯ β‰ˆ h/2 (yβ‚€+2y₁+2yβ‚‚+ … +2yₙ₋₁+yβ‚™)

where h = b-a/n

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9
Q

Integrating quotient t π‘˜π‘“β€²(π‘₯)/𝑓(π‘₯)

A

∫f’(x)/f(x) dx = ln|f(x)| + c
∫kf’(x)/f(x) dx = k ln|f(x)| + c

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10
Q

Integrating chain rule

A

∫ g’(x) x f’(g(x) = f[g(x) + c

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11
Q

Integration by substitution

A

Steps:
1. Choose correct substitution (of u)
2. Change everything in terms of new variable and calculate new integral
3. Change back to original variable

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12
Q

Integration of rational functions

A

When finding integrals such as
ax + b / cx + d and other expressions in fractional form it is sometimes best to divide using algebra long division first

remaining is the numerator
successful division is added

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13
Q

Integration with partial fractions

A

When given an equation that can be turned into a partial fraction, convert it and then integrate using standard integration procedures

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14
Q

Integration by parts

A

Recall that if u and v are differentiable functions of x, uv = uv’ + v’u

∫uv’ = uv - ∫vu’

Note: the goal of this procedure is to end up with a single term or terms that can be integrated after the ∫

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