identidades trigonométricas e integrales conocidas Flashcards by agusgarcia ghffg | Brainscape

Q

cot(x)

A

cos/sen

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Q

sec(x)

A

1/cos

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Q

cosec(x)

A

1/sen

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Q

identidad trigonométrica fundamental

A

cos2^+sen^2=1

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Q

qué tipo de función es el seno

A

función impar porque sen(x)= - sen(-x)

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Q

qué tipo de función es la tangente?

A

función impar porque tg(x)= - tg(-x)

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Q

sen(a+b)?

A

sen(a+b)=sen(a)cos(b) + sen(b)cos(a) (sen cos + sen cos)

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Q

cos(a+b)?

A

cos(a+b)=cos(a)cos(b) - sen(a)sen(b) (coscos - sensen)

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Q

sen(x)^2

A

sen(x)^2 = (1-cos(2x))/2
sen(x)^2 = 1- cos^2(x)

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Q

cos(x)^2

A

cos(x)^2 = (1+cos(2x))/2
cos(x)^2 = 1- sen^2(x)

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Q

sen(2x)

A

sen(2x)= 2sen(x)cos(x)

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Q

cos(2x)

A

cos(2x)=1 - 2sen(x)^2

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Q

senh(x)

A

senh(x)=(e^x - e^-x)/2

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Q

cosh(x)

A

cosh(x)=(e^x + e^-x)/2

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Q

identidad fundamental hiperbólica

A

cosh^2 - senh^2 = 1

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Q

senh’(x)

A

cosh

Q

cosh’(x)

A

senh

Q

qué tipo de función es el cosh

A

función par porque cosh(x) = cosh(-x)

Q

qué tipo de función es el senh

A

función impar porque senh(x) = - senh(-x)

Q

integral de a^x

A

a^x / ln(a)

Q

integral de la secante

A

ln|sec(x) + tg(x)|+c

Q

integral de la cosecante

A

ln|csc(x) + cot(x)| + c

Q

integral de 1 sobre la raiz de (x^2 - 1)

A

arcosh(x) + c, x>1

Q

integral de 1/ la raiz de(1+x^2)

A

arsenh(x) + c

Q

integral de 1/xpor la raiz de(x^2-1)

A

arc cosech(x) + c

Q

integral de 1/la raiz de (1-x^2)

A

arcsen(x) + c

Q

integral de -1/la raíz de(1-x^2)

A

arccos(x) + c

Q

integral de 1/(1+x^2)

A

arctg(x) + c

Q

integral de -1/(1+x^2)

A

arc cot(x) + c