Gene expression 2 Flashcards

1
Q

Protein subunits of RNA polymerase?

A

AlphaX2
Beta’
Beta
Omega

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2
Q

Subunits of holo RNA polymerase?

A

AlphaX2
Beta’
Beta
Omega
Sigma

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3
Q

In prokaryotic transcription, what enzyme recognises promoter?

A

Holo RNA polymerase.

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4
Q

What binds the consensus sequence in the core promoter?

A

Sigma factor.

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5
Q

Consensus element?

A

-35 and -10 elements

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6
Q

What is found to be the optimum spacing in consensus?

A

17

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7
Q

Open complex formation?

A

Promoter opening allows for exposure of template strand for complementary RNA strand.
This formation is in equilibrium.

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8
Q

Anchored transcription?

A

Only short transcripts can be synthesized whilst sigma factor remains bound to the promoter.

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9
Q

Promoter escape?

A

Sigma factor released from the promoter.
Elongation factor binds and transcription proceeds.
Enzyme becomes processive and makes longer transcripts.

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10
Q

Transcription termination in prokaryotic cells?

A

The palindromic sequence in the RNA forms a hairpin loop causing RNA polymerase to stall.
The u-rich stretch downstream of the termination signal allows the transcript to fall off the template, thereby terminating.

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11
Q

4 rough steps of prokaryotic transcription.

A

Open complex.
Anchored transcription.
Promoter escape.
Termination.

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12
Q

Rho-independent termination?

A

A terminating hairpin forms on the mRNA interacting with the NusA protein to stimulate release of transcript from the RNA polymerase complex.

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13
Q

Rho-dependent termination?

A

The Rho protein binds at the upstream rut site, translocates down the mRNA, and interacts with the RNA polymerase complex to stimulate release of transcript.

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14
Q

RNA polymerase I structure?

A

5.8S, 18S and 28S rRNA genes.

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15
Q

RNA polymerase II structure?

A

All protein-coding genes, plus snoRNA genes, miRNA genes, siRNA genes, IncRNA genes and most snRNA genes.

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16
Q

RNA polymerase III structure?

A

tRNA genes, 55rRNA genes, some snRNA genes and genes from other small RNAs.

17
Q

How many subunits make up bacteria?

18
Q

How many subunits make up eukaryotes?

19
Q

What are the two important DNA sequences in Eukaryotic transcription?

A

Core promoters
Promoter proximal and distal elements.

20
Q

Core promoters role in eukaryotic transcription?

A

Recognised by general transcription factors that recruit RNA polymerase.

21
Q

Steps of general transcription at core promoters?

A

-RNA polymerase itself cannot find promoters.
-TFIID makes multiple specific contacts with core promoter elements such as TBP interacting with TATA box.
-TFIID recruits TFIIB.
TFIID is critical for recruitments of RNA polymerase II (with TFIIF)
-This complex cannot initiate transcription even though RNA polymerase II is there.
-Once TFIIE and TIFFIH have joined a transcription initiation component pre-initiation complex has formed.
-TFIIE and TFIIH stimulate and stabilize promoter opening to allow initiation of transcription by RNA polymerase.

21
Q

Role of promoter proximal and distal elements in eukaryotic transcription?

A

Regulatory sequences and binding sites for transcriptional activators and repressors.

21
Q

Order of TF complex in general transcription at core promoter?

A

TFIID
TFIIB
TFIIE TIFFIH

21
Q

Role of TFIIB

A

Recruits RNA polymerase.

22
Q

Role of TFIID?

A

Makes multiple specific contacts with core promoter elements.
Recruits TFIIB

22
Q

What happens when TFIIE and TIFFIH joins.

A

Transcription initiation competent pre-initiation complex forms.
Stimulates and stabilizes promoter opening to allow initiation of transcription by RNA polymerase.

22
Q

What can affect the rate of transcription initiation?

A

-Sequences that bind specific transcription factors may be far from actual transcription site
-DNA bending allows specific transcription factors to interact with the RNA polymerase complex and rate of transcription.

23
Q

DNA binding of transcription factors?

A

-Specific hydrogen bond between an amino acid and a base
-A typical protein-DNA interaction might involved about 29 similar contacts.

24
Q

4 dimerization domains?

A

-Helix-turn-helix motif
-Zinc finger motif
Leucine zippers motif
Helix-loop-helix motif

25
Q

Role of dimers?

A

Dimers of transcription factors binds sequence-specifically to those short sequence-specifically to those short sequence elements, which are often arranged in palindrome.

26
Q

What determines differential gene expression?

A

Transcription factors.

27
Q

How in mRNA processed in eukaryotes?

A

-A 5’ cap (modified GTP) is added at the 5’ end, which facilitates binding to a ribosome and protects mRNA from being digested and protects mRNA from being digested by ribonucleases.
-A poly A tail is added at 3’ end: sequence AAUAAA after the last codon signals an enzyme to cut the pre-mRNA; the another enzyme added 100-300 adenine (to form tail). The tail assists in export from the nucleus and is important for stability in mRNA.

28
Q

Explain how genes are split in eukaryotes?

A

In eukaryotes, the coding sequences are interrupted with non-coding sequences (introns) that are spliced out of the mature mRNA transcript.

29
Q

Explain RNA processing?

A

RNA splicing removes intron sequences from newly transcribed pre-mRNAs.
The precursor mRNA transcript introns are removed by a process called RNA splicing, leaving the protein coding sequences (exons) in the mature mRNA.

30
Q

Steps of RNA splicing involving the spliceosome?

A
  • Small nuclear ribonucleoprotein particle bind to consensus sequences in RNA near 5’ donor and 3’ acceptor splice sites.
  • Binding of snRNAs recruits other proteins
  • A cut is made between the 5’ exon and the intron
  • After the first cut at the 5’ end, the intron forms a closed loop.
  • The free 3’ end OH group ,at end of cut, exons’ reacts with 5’ phosphate group of other exon.
  • The 3’ exon is cleaved and spliced to the 5’ exon and the mature mRNA is exported to cytoplasm for translation
  • The excised intron is degraded in the nucleus.
31
Q

Explain alternative RNA splicing?

A

Alternative splicing can give more than one product from single genes.
Alternative splicing can be regulated to give differential gene expression.

32
Q

Eukaryotic and prokaryotic order of transcription and translation.

A

Prokaryotic cells are translated at the same time and transcribed.
Eukaryotic cells RNA transcripts must be processed and transported to cytoplasm before being translated. Leaves nucleus through nuclear pore complexes.