Further mechanics Flashcards

1
Q

What is simple harmonic motion

A

Where an object oscillates either side of an equilibrium point

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2
Q

What is the condition for SHM to take place

A

The acceleration is directly proportional to the displacement from the equilibrium and acts towards the equilibrium

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3
Q

Why does the acceleration act opposite to the displacement

A

The displacement increases away from the equilibrium and acceleration is due to the restoring force which brings the system back to equilibrium

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4
Q

How does energy change during SHM

A
  • Total energy (Ek + Ep) remains constant
  • As displacement gets further from equilibrium, Ep (which is either elastic potential for a spring or GPE for pendulum increases) increases and Ek decreases
    (and vice versa)
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5
Q

Explain how you can draw a graph of displacement against time for an SHM system

A
  • It is a function of Cosine
  • Max value = A (symbol for amplitude)
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6
Q

Explain how you can draw a graph of velocity against time for an SHM system

A
  • gradient of displace/time so function of negative sine
  • Therefore the phase difference between the v/t graph and x/t graph is π/2
  • Max value = wA where w is angular frequency
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7
Q

Explain how you can draw a graph of acceleration against time for an SHM system

A
  • Gradient of velocity/time so function of negative cosine
  • Therefore π out of phase with x/t
  • Max value at w^2 A
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8
Q

Define frequency in an SHM system

A

Number of complete cycles per second

(where 1 cycle is e.g. left to right and back to left)

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9
Q

Define time period in SHM system

A

Time taken for one complete cycle

(where 1 cycle is e.g. left to right and back to left)

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10
Q

Define angular frequency in SHM

A

Angular displacement per second

w = 2π/T or w = 2πf

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11
Q

What is the relationship between amplitude and frequency (or time period) in SHM

A

They are independent from each other so f and T remain the same even if oscillations get smaller

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12
Q

Explain the formula relating acceleration and displacement

A

a = - w^2 x

Because a is directly proportional to x and acts opposite so negative and constant is w^2

(Therefore e.g. the force restoring back to equilibrium doubles as displacement doubles)

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13
Q

Explain the formula for max acceleration

A

a max = -w^2 A

Because a is proportional to x so max a is when x = A

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14
Q

Explain the formula for max velocity

A

v = w * sqrt(A^2 - x^2)
and v max is where x = 0
v max = wA

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15
Q

What is the formula for displacement as a function of cosine

A

Acos(wt)

max displacement is when cos(wt) = 1 so t = 0

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16
Q

How can you find w in an experiment

A

plot a straight line graph of a against x and w = sqrt(gradient)

17
Q

Describe the experiment to find the formula for T in a mass spring system

A
  1. Suspend a mass and find the time taken for 10 oscillations then divide by 10 to get T
  2. Repeat for different values of mass, spring constant (by using different combos of series and parallel) and amplitude with separate experiments for each
  3. You would find that T ∝ sqrt(m) and T ∝ sqrt(1/k) and A has no affect
    So T = 2π*sqrt(m/k)

Also to remember: use a fiducial marker as a point of reference for midpoint and wear safety goggles

18
Q

What are free vibrations

A

Occur when no external forces act on the system so oscillates at natural frequency (known as resonant frequency)

Imagine swing if you let it go but don’t push it

19
Q

What are forced vibrations

A

Occur when you apply an external driving force to make the system oscillate

Imagine pushing a swing

20
Q

Explain resonance

A

Where the amplitude of oscillations drastically increase because the driving force was applied equal to the resonant frequency

21
Q

Give 3 examples of resonance

A
  1. Flutes which cause a column of air to resonate creating a stationary wave
  2. Radios which are tuned so that the circuit resonates at the same frequency as the broadcast for max signal
  3. A swing where someone pushes you at the resonant frequency causing you to swing higher
22
Q

What is damping

A

Where energy is lost to surroundings due to frictional forces like air resistance (known as damping forces)

23
Q

What is a use of damping

A

To reduce the number of oscillations which stops resonance from occurring which could be unsafe i.e.

24
Q

Describe light damping

A

Where the amplitude decreases slowly over time

25
Q

Describe heavy damping

A

Where the amplitude decreases over time but more quickly than with light damping

26
Q

Describe critical damping

A

Amplitude goes to 0 straight away (think of a cos graph from 0 to 90 and then straight line at 0 for the rest of the time)

27
Q

Describe overdamping

A

There are no oscillations like with critical damping but it takes a lot longer to get to 0
(the cos graph from 0 to 90 stretched the the x axis)

28
Q

Explain how damping affects the amplitude when resonance occurs

A
  • If you plot a graph of amplitude against driving frequency, the graph would look like a normal distribution curve with some A when DF is 0 and no A at high driving frequencies and a peak A when the DF = RF
  • Lighter damping causes the peak amplitude to be higher and sharper
  • sharper means less range of driving frequencies cause resonance
29
Q

Describe the condition for circular motion

A

Where the (centripetal) force applied is always perpendicular to velocity

30
Q

Define angular speed

A

The angle that the object rotates through per second

31
Q

What is the relationship between angular speed and linear speed

32
Q

Define frequency and time period for circular motion

A
  • Frequency is the number of revolutions per second
  • Time period is time taken for 1 full revolution
33
Q

Explain the relationship between angular speed and frequency for circular motion

A
  • w = 2π/T (think of 1 full cycle)
  • So w = 2πf
34
Q

Explain acceleration in circular motion

A
  • The direction is constantly changing even though speed is constant - - Changing velocity causes centripetal acceleration which acts towards centre of circle
  • a = w^2 r = v^2 / r
35
Q

Explain centripetal force in circular motion

A
  • Centripetal acceleration which acts towards centre must be caused by centripetal force which also acts towards centre
  • F = mv^2/r = mw^2 r
36
Q

Explain what would happen to the roller coaster on a loop if the track ran out

A
  • When travelling on the loop centripetal force acts towards centre and velocity is perpendicular so at tangents to circle
  • If track runs out, the carriage would fly off in the direction of velocity so at a tangent to circle
37
Q

Example: swinging bucket of water around in a circle with a string

Explain the forces acting on the bucket of water at different points in the motion

A
  • There is a support force in the string bringing it to centre of circle and weight acting down of bucket which together make up centripetal force
  • At the top of circle centripetal force = S +Mg
  • At the bottom CF = S-Mg
  • At the right or left CF = S
38
Q

Example: swinging bucket of water around in a circle with a string

Explain why the water doesn’t fall out of the bucket

A
  • Water is in circular motion so the forces cause its velocity to be at a tangent to a circle and not straight down
39
Q

Example: swinging bucket of water around in a circle with a string

Explain the conditions required to maintain the bucket of water in circular motion without water falling out

A
  • At the top mv^2 /r = s + mg
  • Only at the top, weight acts down and if it is greater than the centripetal force, the water will fall out
  • Therefore, to maintain circular motion mv^2 /r ≥ mg so s ≥ 0
  • v^2 /r ≥ g meaning you should increase v or decrease r to stop water falling out
  • When the water falls out mv^2 /r < mg which would imply s<0 i.e. impossible so no circular motion