From PALS To Effectivity Flashcards

1
Q

Limitations of multifocals and what are pals

A

lenses have a limited focussing range through each of the fixed focus zones.
May no longer be sufficient to provide range of wds for older presbyopes.
younger presbyopes dont want to wear bifocal- visible divison of segment is a sign of ageing.

What are pals-
progressive addition lenses, aka varifocals or progressive power lenses aka ppls
these give continuous clear vision over all distances
PALs can be considered to have 3 zones: distance, progression, near
power is worked in the front surface and the sph or toroidal rx is on the back surface. Its normally semi-finished as cant rotate the cyl.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Owen aves what did he do

A

Came up with first design of progressive lens.

Came up with using two surfaces and both surfaces reduce in radius from the top to bottom. More +ve power on front surface.
Stuck them together
problem- not able to produce commercially as each lens is unique and you would need to work individual rxs on with the design so individually would be expensive.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Maitenaz- Essel later essilor two types

A

designed the first commercially successful progressive lens launched by Essel later Essilor.

Varilux 1- spherical sections ‘hard design’
spherical surfaces of decreasing radius of curvature towards bottom of lens, stable distance and reading areas but there was a severe blending in intermediate and near areas giving rise to large amounts of peripheral surface astigmatism.
Aspheric curve from distance and near so we get surface astigmatism. For aspheric we want surface astigmatism to get rid of OAE but for varis we dont want that we want the powers to change spherically so we need to get rid of this.

Varilux 2- aspheric sections- ‘soft design’
elliptical surfaces for distance and near so spread out blending so bit more in distance as well so not as much peripheral astigmatism. People got on with these more, easier and quicker to adapt to. Reduced swimming feeling.
Conic sections of varying asphericity, reduced peripheral surface astig and near portion is narrower than for hard design and some surface astig in distance.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Comparing Aves and v1 and v2 again

A

Aves- the change is gradual no stable distance and near areas. Gradual. No distinct wide area for distance and reading. Had to make individually for all pxs, not commercial.

V1- wide area for distances, stable distance and reading areas, steep change in power, more astigmatism

V2- gradual change in power compared to v1, not as wide reading and distance narrower, doesnt reach full progression till further down progression, slower rate of change. Less astigmatism and swimming feeling people got on with these. Conic sections of varying asphericity

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

The design of a pal what do we need and what is the purpose fo a pal

A

need a length in corridor to fit that changing power in, not too long as they want to read at bottom also not too short as you have to fit that power in. DP at top, intermediate and np underneath and aberrations on the sides.

purpose of progressive lens feature- stable distance at top, stable near at bottom, progressive corridor connecting the two stable power areas.
Complete invisibility, no lines or ridges
generally progression is worked on front surface of a lens- semi finished lens. Finished rx is worked on back surface= sph/toric

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Design of a pal with the power and the add

A

The design of pal is determined by what happens in the progression zone. The power could change in a linear way, we assume this for calculations but in actual fact, power changes quadratically.

For a linear progression of 0.133D/mm starting from oc (prism checking point). 10mm below the oc the power of the addition will be 10 times 0.133= 1.33D.
Add= length of linear progression zone times progression- D/mm
As the add increases the rate of change of power will increase if the progression length remains constant.

there will be induced prism at the NVP= P=Fc. F= total power at nvp and c= distance from optical centre (or prism checking point if no prism worked on)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

How are pals made whats the idea behind them
Explain with the intermediate

A

Imagine PAL is two spherical surfaces with different radii. Larger radius for distance portion smaller radius for near portion.

If stuck together would be like an e style seg w visible dividing line, instead they are joined by a third aspheric surface- intermediate- where the radius of curvature decreases continuously from DP to NP and the radius at the top exactly matches DP and radius at bottom exactly matches NP. This produces an ovoid surface with no dividing lines.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

How are they made- what is the first main determinant

And explain about surface astigmatism do we want it

A

complex aspheric surfaces to give you that change in power, only possible to produce with computer numeric control (CNC) grinding machines.

the rate of change of curvature is determined by a mathematical formula. Formula is the first main determinant of the optical performance of a PAL design.

2) power progression formula with p value gives us required tangential error we want but if we plot a field diagram of resultant sag and tang powers, we see tangential power gives required addition at each point but sag and tang powers do not match therefore we have surface astigmatism. For pals we want a spherical change in power along the progression and surface astigmatism is unwanted.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

so what do they need to do to get rid of it

A

radius of curvature in tangential and saggital powers will not be the same. Lens designers must match them to eliminate unwanted astigmatism along the meridian line. This pushes surface astigmatism into the periphery.
The way in which powers are matched determines the amount of peripheral surface astigmatism and is the second main determinant of optical performance of a pal design.

The level of surface astig is proportional to the rate of change of power which increases with an increase in addition and a decrease in progression length.

Eliminating higher levels of astigmatism along the meridian line leads to higher resultant peripheral surface astigmatism as you pushed it out and smaller useful intermediate and near areas. Really you want less surface astig at the start so choose v complex equation so you have to push less over. Best designs are complicated and difficult to make and expensive.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Explain what the corridor of clear vision is and if you have a low add will you get away with cheaper designs

A

The corridor of clear vision is often taken to be the area where astig does not exceed 1.00D. More complex designs allows the lens designer to push the aberrations further out towards the periphery giving wider intermediate zones and larger reading areas.

If you have a low add you might get away with cheaper design as not as much astig to get rid of as rate of change of power wont be as high along the meridian so not a lot of peripheral astig as not a lot to be pushed over into the periphery with lower powers. And esp if you have a longer corridoor then the rate of change of power wont have to be as high. Rate of change of power increases w increase in addition and decrease in progression length.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

How to measure the amount of astigmatism
Talk about the two maps of two diff types of varis

A

rotlex progressive lens mapping equipment- computer controlled mapping device that maps the power of the lens. Ancient+modern maps. Modern are no longer referred to as hard or soft though.

So called ‘hard design’- Varilux 1 has unwanted cyl
varilux 2 soft- can see more of a gradual change with soft, less unwanted cyl but also smaller reading areas.
note- can also do mean sphere plots showing power change.

ISO cylinder plot or mean sphere plot.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

As add increases

A

Astigmatism increases so iso cylinder gets more together and clear reading area gets smaller. So bif to vari 3D lots to adapt to.

Iso cyl plot of a lens with the same design and progression length showing how astigmatism increases with increasing add.
better for pxs to get started w varis earlier with lower adds to get used to surface astigmatism and they wont notice it as much fi they started off with their add being higher.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Comparison of PAL designs what is intolerance often due to

A

Can be very difficult as diff companies use diff measurement techniques and apply diff standards to their lenses.

One company may take their corridor width to where astigmatism is less than 1.00D and another less than 1.5D. Moulds are often used of the Same design by companies when they make other claims for their lenses.

We only know if a design works for a px when they try it. Most often intolerance to PALs is due to poor dispensing or poor fitting.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Short corridoor pals vs conventionals depth and everything

A

conventional pals require a frame deep enough, depth of around 18mm, long enough to keep rate of change of power down and good reading and allows the progression to reach the full addition. This is minimum depth for each design. This limits the choice of frames for PAL wearers.

Short corridor pal lenses are available to fit into narrower frames with a minimum depth of around 14mm but since astigmatism increases as corridor length decreases these lenses are more difficult for px to adapt to esp for higher adds. Px should be warned ab limitations of these lenses and advised advantages of choosing a deeper frame. Rate of change of power greater in these so peripheral astigmatism is greater and they get a narrower reading area. Full reading rx is reached at a point close to the distance portion and all the reading area fits into the frame.

If you have more depth than you need, the reading area will just be higher up in the lens.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Occupational pals

A

general term- lens made to suit an occupation
generally designed for intermediate and near working distances only so no or very small distance rx. More comfortable as px dont have to lift their head to look at screens, distance area at top small one not suitable for driving.

For these as its just two wds, rate of change of power is decreased as intermediate to near so less peripheral astigmatism as well and wider reading and intermediate areas as less getting pushed out. Fitting procedure diff for diff manufacturers. Establish range of wds your px needs and choose the lens accordingly.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Free form lenses

A

allows designer limitless options in their designs so can tailor lens surface for each px rx. Can include control of magnification and differential prism for anisometropia. Best form lenses.

Each point given 3d coordinate rather than formula controlling x/y/z

produced on concave rear surface of lens along with cyl correction on the front surface being aspherical or spherical, some even use both surfaces to produce the power progression.

individual design for specific back vertex distance, pantoscopic tilt and dihedral angle when designing lenses for these individuals. Extra measurements must be taken when dispensing.

Main limitation of these lenses= cost
free form technology not limited to varis

More popular than old compensating methods eg slab off bi prism and iseikonic lenses
by matching peripheral astig for right and left lenes can reduce swimming effect

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

The swimming effect

A

experienced with pals when looking through periphery, can be a problem walking up and down stairs- greater with higher adds= greater periph astig

or large diff in rate of change of astigmatism in the right and left lens as the wearer moves their eyes from central gaze causing diff amounts of mag= causes diff in the perceived velocity and objects appear to change direction. Apparent change in direction is diff for each eye producing swimming effect

wearer adapts more quickly to low add or smaller changes in add

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

Cosmetic prism thinning

A

base down prism is worked on the concave surface along with the final rx to equalise the edge thickness of the finished lens, prism will now be equal in both eyes so no differential prism.

Top edge needs to be fat to get knife edge at bottom so prism will create knife edge at both ends, no differential prism. Cosmetic

often find some vertical prism at prism checking point. If the same in right and left= prism thinning. If any difference in vertical prism right and left eye- should prescribe vertical prism.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

Dispensing pals

A

mark heights at centre of pupil at eye level when looking straight ahead into distance.
Frame should be adjusted first and confirm enough depth for the PAL design.
Directly face px eye level, natural head position.
px fixates practitioners left eye when marking right pupil and right eye when marking left pupil. Remove frame and replace and recheck marks.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

Verifying pal rx and fit

A

use permenant engraved markings and a manufacturers template to remark the lenses as above in lens markings

distance checking point is the circle
prism checking point is the dot
near ceiling point is the N on the lens marking diagram

alternatives to pals- lens systems, diffractive lenses, liquid crystal lenses, gradient index materials, deformable lenses.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
21
Q

1)What are the two main factors which determine the design of a conventional PAL lens-

A

The choice of aspheric surface to produce the power progression, and the method by which the astigmatism along the meridian line is eliminated so formula

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
22
Q

2) What does an iso cylinder plot tell us and why a re these often not a useful method when comparing PAL designs

A

An iso cylinder plot gives us a colour coded contour plot of the areas on the lens surface which have the same range of astigmatism. They are not always good comparison of lens designs as the methods of measuring astigmatism can vary from company to company. The plots may also be misleading if the colour ranges do not match or if the first contour on one plot represents a higher level of astigmatism than the first contour on another plot.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
23
Q

3) Why are short corridor PAL lenses not advisable for high additions

A

as surface astigmatism increases as the add increases and the corridor length decreases and you get a faster rate in change of power. The combination of a high add with short corrridoor= high levels of peripheral astigmatism and narrow intermediate and reading areas.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
24
Q

4) why do occupational PAL lenses generally give wider reading and intermediate zones than conventional PALS-

A

as there is only a small power change over the progression zone and this lower rate of change in power over the length of the corridor leads to less astigmatism in the periphery as less would then need to be pushed over, which results in wider zones of clear vision at near and intermediate.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
25
Q

5) What are the differences between conventional and free form PAL designs

A

conventional pals use a formula to determine the shape of the lens surface but for free form lenses each point on the lens surface can be determined individually.

Conventional pals are produced on the front surface, free form pals are often produced on the back surfaces or both surfaces, the pxs individual rx is often included in the design.

conventional pals usually only require mono cd, and height measurements. Free form PALs require BVD, pantascopic tilt, and sometimes the dihedral angle. Free form can be tailor made to the individuals rx and to the frame fitting but conventional pals hase the same design for a range of rxs.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
26
Q

6) Explain why pal wearers sometimes get a swimming effect in vision

A

as varifocal wearer looks through the edge of the lens the rate of change of astigmatism will differ in the right and left lens which will cause a difference in the magnification which is perceived as a difference in velocity which causes an apparent change of direction which is different for each eye.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
27
Q

Why do we often find vertical prism at the prism checking point, why is it usually base down prism and how will you know if its prescribed prism-
and about prism thinning and six of intoleranaece with it

A

due to prism thinning which is applied purely for cosmetic reasons to balance the edge thickness at the top and bottom of the lenses.

it is base down as the power of the lens becomes increasingly positive as we move towards the bottom of the lens which results in a reduced edge thickness. Applying base down prism will increase the edge thickness to compensate for the decrease due to increased positive power. Reduced edge thickness is generally desired for cosmetic reasons, but for lenses that have higher positive power towards the bottom, reducing edge thickness too much can lead to an imbalance in appearance between the top and bottom of the lenses. This can create an unbalanced look, with the bottom of the lens appearing significantly thinner than the top.To counteract this imbalance and achieve a more uniform appearance, base down prism can be applied. Base down prism increases the edge thickness at the bottom of the lens, helping to balance out the thickness between the top and bottom. So, while reducing edge thickness is generally preferred, in certain cases, like those involving high positive power at the bottom of the lens, it may be necessary to apply base down prism to maintain aesthetic balance.

How will you know if it’s prescribed prism- if its the same right and left then it isnt prescribed prism, vertically prescribed prism will be different right and left, you will have some differential prism. Otherwise there is baso no differential prism= prism thinning. So any differential prism= prescribed.

Prism thinning is applied automatically and does not have to be ordered, very occasionally a px may have a non tolerance to the prism thinning and the dispenser may ask for it to be cancelled. Symptoms of prism thinning non tolerance- exaggerated head movement for distance and near, intermediate blurred, narrow clear distance, strain or pulling. Or just not right. check by applying equal and opposite prism over the spectacles to see if there is any improvement= to cancel it out to see if it is intolerance so could just put some base up.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
28
Q

Dispensing scenario- Mr K, age 55. Rx= +5.00/-2.00 X 160 LE- +5.25/-2.00 X 15 add 2.25
bank manager, hobbies restoring vintage cars, golf, snooker

A

rx- thinning, BVD, anisometropia= remember your standard axes!! Re= 160 is symmetrical with about 20 in left eye. Remember this
Occupation- lens choice, standard varifocals occupational, free form. Bifocal. Single vision

frame choice- minimum depth, short corridor= not good optically. Edge thickness, frame shape= cyl is baso horizontal which means the widest edges will be top and bottom if spherical lens, narrow frame would reduce the edge top and bottom. Balance this with minimum depth for varifocal.

Hobbies lens choice, head position and option of reading area in relation to near vision requirements. Will he be able to look through near vision bit when looking under cars probably not. Cheap Sv pair. Safety specs as well. Wds what is involved where there head may be etc. think of problems they may encounter.
measurements- what facial measurements would you need to take for each dispense.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
29
Q

If differential vertical prism is base down how can we compensate for differential vertical prism in varifocals

A

We can compensate for the differential prism by slabbing off base down prism in the left near portion to give base up in the left near portion. Similar to bi prism bifocal

Or most likely today would use free form lenses to allow us to control differential prism and even magnification within the design.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
30
Q

PD
Why are they required =, how to ensure accurate measurements
If the practitioners eye is 40cm away from spectacle plane what is the approx error for every mm so for an 8mm difference whats the error if closer

And mono pds and when would you do them
For strabismus what do we do

A

required so optical centres are placed in front of pupil centres so no unwanted prismatic effect. Unwanted prism- visual discomfort or tired eyes, diplopia.

To ensure accurate measurements- arms length to minimise errors due to difference in pxs or practitioners pd. secure ruler on pxs forehead resting on bridge of nose. Close re and instruct px to look at le, place ruler so zero mark and re make sure 0 doesnt move and read measurement off= distance pd. Square on to px, level with px, no movement or steady hands, if fails with child go from the canthus of the eyes.

if pxs pd is a lot smaller than practitioners= over estimation. If the practitioner’s eye is 40cm from spectacle plane there will be an approx error of 1/16th of a mm for every mm difference in pd between patient and practitioner. So for an 8mm difference= 0.5 error. So divide by 16. If practitioner closer= angle of rotation of pxs eye will be greater so get a greater error thats why arms length is good. Further away= less error or overestimation due to difference. So if theres a diff greater than 8mm so you’re further back not as much difference but if closer more difference so bigger error.

Mono pds- centre ruler on bridge of nose and measure to centre of each pupil. PALs and aspherics generally measured by dotting centre of pupil on the dummy lens.
Assymetry, strabismus or amblyopia, pals, aspheric lenses, anisometropia. Progressive and aspheric also measure pupil heights. For strabismus occlude the pxs other eye to ensure correct fixation.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
31
Q

Near centration distance

A

we do not measure near pds, instead measure near centration distance in the plane of the spectacles but frames must be fitted first.

Place an object eg pen centrally and close to one of your eyes, at the pxs near working distance and ask the px to fixate it. Close your other eye and place the ruler against the frame and line up the zero point in the RE. Switch to the pxs le and read off the measurement at the relevant measurement point.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
32
Q

Pupillometer how does it work

A

uses first purkinje image to take pds, avoids inaccuracies due to parallax errors.

Px holds it like binoculars and looks through two eye pieces towards a target and the practitioner looks through the single eyepiece on the other end of it, adjusts the sliders to move the line targets so they pass through the purkinje image which marks the centre of the pupils.

Binocular and mono pds can be taken at various wds. Each eye can be occluded so mono pds can be taken as well for pxs with strabismus.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
33
Q

Multifocals and PALS What do you have to do

A

Ensure correct relative positioning, square on eyes level natural head position, frame fitted as worn- including pantoscopic and dihedral angles. Binocular pds sufficient unless aspheric or any of those other reasons above.
Mark segment top positions- generally at lower limbus or lower lid. Measure relative to the HCL.
Lower segment top- less annoyance better when walking down stairs eg d segs. Higher stp- if used mainly for near. Ask if existing wearers are happy.
Trifocals are generally fitted w top of the segment at the bottom of pupil.

pantoscopic angle between 8-12 degrees. Dot centre of pxs pupil
remove frame, remark refit and double check. Heights and mono pds measured using frame ruler or a manufacturers varifocal template
british standard heights measured relative to hcl. In practice often measured relative to lowest point on frame.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
34
Q

BVD british standards. What are the diff tools we have to measure it

A

The Varilux measuring gauge
digital methods like zeiss visufit (avatar) or apps eg Hoya visureal

distometers- tool to measure BVD. Place pad on the end of the gauge placed against the closed eyelid, plunger on end pushed in until the other arm of the gauge touches back surface of the lens and then there is a converter scale to work our rx adjustment as well.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
35
Q

British standards for bvd and error of measuring bvd with ruler

A

British standards say measure for rx over +-/5.00D
Distance between back vertex of lens and corneal apex is measured along line of sight perpendicular to spectacle front.
Measurement must be taken with 0 pantoscopic tilt, instruct px to tilt head until lens plane is perpendicular to floor and instruct to look straight ahead.

difficult if frame is thick or if the edge of the lens is thick
need to estimate position of the back vertex,
errors will occur if measurement is not taken along the optical axis of lens.

Accuracy can be improved by taking the measurement from the front surface and then deducting the centre thickness measured with a thickness gauge. BVD of glazed specs may differ if the base curve differs from the curve of the dummy lenses used to measure the BVD. Slightly.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
36
Q

Pantoscopic angle what is it and how do we measure it what instruments exist

A

important particularly for varifocal wearers+ free form as they are individually paying for it.

Pantoscopic angle is the angle in vertical plane between optical axis of the spectacle lens and the visual axis of the eye in the primary position (assumed to be horizontal)
centre of rotation distance remains constant as the eye rotates which ensures constant BVD or effective power.

Optical centres dropped 1mm for every 2 degrees of pantoscopic angle so that the optical axis passes through the centre of rotation- already incorporated in PALS if angle between 8-12 degrees. Fitting cross 4mm above the optical centre.

Measurement of pantoscopic angle- Zeiss pantoscopic gauge, E sill or Varilux measuring gauge can be used to measure BVD, panto, and dihedral angle.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
37
Q

Dihedral angle

A

Frame wrap. Horizontal angle of the lens. What I change when i heat glasses to make tighter i bring them in.
Free form progressive lenses- gives optimum performance in the as-worn position.

Mono pds and heights, BVD, pantoscopic angle, dihedral angle
manufacturers provide fitting kit with measuring gauge to help take required measurement.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
38
Q

Fairbanks’s facial measurement ruler and what can you measure with it
-apical radius

A

Lots of things on it, used to take measurements for making a frame from scratch, not commonly used, HES maybe.

For custom designed frames you need-
PD, apical radius, head width, bridge projection, bridge height, splays angle, frontal angle, DBR at 10 below crest and 15 below crest, angle of crest.

Apical radius- find the cutout that fits the bridge of the nose the best, if in between measurements choose the slightly looser one= one w the greatest radius. So various things n this ruler to help design the perfect frame.

Head width- measured just above ears using callipers or using rulers measure the width of head and frame head width is side to side at the ear point

Temple width- measured 25cm from the front of the frame or 25mm above the ear. Short end of arm against temple and separate ruler against temple on other side and note reading

Bridge projection- in line with lens plane, slider just clears lashes that’s how far your bridge comes out.

Bridge height- place ruler on crest of nose, place scale over lower limbus

Frontal angle- needle, rotates to see the angle of the nose. Line up centre line with centre part of nose, rotate pointer and measure angle. Equivalent frame measurement is frontal angle of pad.

Splay angle- Line up end of ruler against pxs nose and measure how much the nose splays out. Centre line w centre of nose and ask px to tilt head down.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
39
Q

Distance between rims- 10mm and 15mm

A

10mm below crest- hold ruler with 10 correct way up and place extended part of it on crest. Vertical distance to edge=10mm, place edge against right side of nose, slide until just touching left side and read off lower scale.

15mm below crest- same thing, should be bigger measurement this time place edge against the left side of the nose and hold the ruler with 15 correct way up, place edge against left side of nose, slide until just touching right side. Read off lower scale.

40
Q

Frame fitting-

A

frame set up and set it flat upside down ensure sides are level, the other way if its unequal may have unequal LTB and or angle of drop so that can be normal for assymetrical faces.

41
Q

difference between frontal head width and frame head width

Head width
Angle of let back
Bridge

A

Difference between frontal head width and frame head width should not be excessive

Head width- difference between frontal head width and frame head width should not be excessive or too much pressure is brought to bear on the side joint and the side may be in tight contact w the skin

Angle of let back- if its too great bring the sides inwards at the frame joint but do not deform the side itself.

bridge- plastic frame cannot be adjusted so care taken to ensure bridge fits, bridge must closely follow the profile of the nose at the resting point. Too wide- frame slips down nose to point where it fits, uncomfortable in position where it doesn’t fit- small weight bearing area. Too narrow and its uncomfortable to wear= pressure at sides of nose

42
Q

Nose pads and front
Pantoscopic angle

And side

A

nose pads- on metal frames can be adjusted for splay angle and frontal angle and move in and out to fit different bridge widths. Pads flat against he nose at the point of fitting- maximum possible area of contact to spread the weight and reduce the pressure.
front- make sure BVD are the same. High rx +-5.00 ensure BVD same

Pantoscopic angle- adjusted for frame fitting and to ensure optical requirements of lens are met- varifocals and aspheric lenses. BVD remains constant as eye rotates. Adjust angle of side= correct angle

Side- bend of side should begin at the ear point. If the length to bend is too long= then frame moves to fit at the ear point resulting in the frame slipping downwards. If the ltb is too short the frame levers upwards and tips forwards and will slip down the nose. Pressure sores may develop at the tip bearing surface and the same may occur if the downward angle of drop is excessive. the inward angle of drop must follow closely the shape of the head.
If inward angle of drop is too close- pressure on the mastoid process (v painful) may also put pressure on mastoid if downward angle of drop is not sufficient.
inward angle of drop too wide= deforms the ear lobe.
Length of drop too long= cosmetically unsightly, sides may need to be shortened. Check at initial frame assssment.

43
Q

If the pantoscopic angle is too flat what happens to bvd and what is the correct angle

A

Angle too flat- BVD increases as the eyes ravel down the lens

Correct angle- bvd remains constant as the eyes travel down to the lens

44
Q

Why measure distance and near cds

A

when px viewing. a distant object their visual axes are parallel and the separation of the pupil centres will be the same in both the spectacle and facial plane. When a px is converging to view a near object, the separation of the pupil centres will be less in the spectacle frame. We want to ensure px is looking through Ocs of the lenses so we must measure the pupil centre distance in the spectacle plane.

45
Q

-Explain the procedure for taking measurements for bifocal spectacles

A

Px/ practitioner alignment- the practitioner must face the px and ensure their eyes are aligned with the pxs. If not aligned= parallalax errors. same height as well.
Make sure px has a natural head position. Pxs try be helpful. If they tilt their heads up you’re going to measure the limbus too far down so you would set the heights too far downwards.

measure distance pds- binocular sufficient unless otherwise indicated- explain procedure for aligning the px and practitioner axes and measurement from equivalent points right and left eye.

fit frame in as worn position check it, check heights.
Mark segment top- lower limbus or as worn in existing wearers.
Measure segment top position rel to hcl

46
Q

What is the purpose of the pantoscopic angle

A

Ensures that the centre of rotation distance remains the same as the eye rotates behind the lens. Ensures BVD remains constant and reduces off axis power errors as well as BVD errors.

47
Q

What are the 3 additional measurements needed to dispense free form

Give 3 instances when it’s necessary to measure mono pds rather than bin

A

Back vertex distance, pant angle, dihedral angle or frame wrap angle

strabismus, varifocals, aspheric lenses (asymmetric features,high rx, anisometropia)

48
Q

Describe the procedure for measuring distance mono pds with a ruler for a px with a small alternating strabimsus (7)

A

why occlude for pxs with strabismus- if your px has a left esotropia eg may fixate your right eye with their re. This may not be obvious if the esotropia is only small. Occluding the right eye will force them to fixate with their left eye.
If they have a deeply amblyopic eye it is usually okay to take the mono pd for the good eye and give the same for the amblyopic eye.
For an alternating strabismus it is important ton measure both mono pds whilst occluding the other eye.

Setup to avoid parallax errors
pracitioner positioned facing px square on with their eyes at the same height as px
alignment- ask px to look into your left eye with their right eye whilst occluding the left eye to ensure correct fixation. Occlusion can be achieved by using the right hand holding the ruler or you can ask the px to cover their eye but ensure they do not move when they swap to occlude the left eye.
Measurement- with the ruler at arms length, align zero mark with centre of the bridge of the nose or use a ruler with a cut out for the nose and read off the scale at the centre of the pupil.

49
Q

6) Define pantoscopic angle-(3)

A

The pantoscopic angle is the angle in the vertical plane between optical axis of the spectacle lens and the visual axes of the eye in the primary position (assumed usually to be horizontal)

50
Q

7) What are the potential sources of error when measuring BVD with a rule (4)

A

Estimation of back vertex position can be difficult esp w thick lenses/ frames
Errors will occur if measurement not taken along optical axis
parallax errors if practitioners eye and rule are not aligned correctly
if measurement of the BVD is taken for the new frame with dummy lenses the BVD may differ in the glazed spectacles due to the difference in base curve

(First three are most important, cant account for the last one and hopefully shouldnt give significant errors, if it does the measurement needs to be taken again in the glazed spectacles and appropriate adjustments made to the BVD)

51
Q

8) Why measure PDs at arms length (2)

A

To minimise any errors occuring due to misalignment of pxs and practitioners visual axes. Esp important if there is a mismatch between pd measurements eg when measuring small children’s pds. The further away the practitioner is the smaller the error when the two eyes are not aligned.

52
Q

Define dbl DEFINE hcl

A

Define DBL
distance between lenses, british standards definition- horizontal distance between the nasal vertical side of the rectangular boxes which make up the the right and left lens shape.

10) Define HCL- horizontal centre line- british standard definition- line located at an equal distance from the two horizontal tangents of the boxed lens system.

53
Q

What do the numbers x square y, zzz often printed on inside of frame side tell you

A

is the horizontal boxed lens size, y is the distance between lenses and zzz is the total length of the sides.

54
Q

12) When might you need to take measurements with the Fairbank’s facial measurement rule

A

when having to make a made to measure frame for someone with unusual facial dimensions

55
Q

Which two measurements can you use in place of frontal angle-

A

we can use the distance between rims at 10mm and at 15mm below the crest and this also gives us a measure of the changing width of the nose at the position the nose pads generally rest.

56
Q

Where and why do you measure temple width and head width-

A

Temple width is measured 25mm from the front of the frame. We need to ensure there is some clearance between the sides of the frame and the wearers face. Head width is measured at the point the sides of the frame begin to bend, at the top of the ear- we need to make sure the frame is wide enough for the sides to fit without putting undue pressure on the side joints.

57
Q

Most facial measurements have equivalent frame measurements, why arent pantoscopic angle and angle of side equivalent-

A

the pantoscopic angle is the angle the front of the frame makes, measured relative to the vertical when the px is wearing the frame. Strictly it is the angle between optical axis of the lens and the visual axis in the as worn position. It can be altered by altering the angle of side but may not be the same as the angle of side which is simply tje angle between the front surface and the side of the frame.

58
Q

16) Why dont we need to measure splay angle and frontal angle for most metal frames-

A

can adjust it after, for frames w individual nose pads we can alter these two parameters to fit.

59
Q

What is convergence
Z, l, object height, convergence angle and how do we check convergence

A

As you’re looking at a distant object the visual axes is parallel but if converge to something nearer the eyes rotate inwards so both eyes are looking at object so the brain can fuse the two images together. Each eye rotates by the angle theta which you can work out.

Z- centre of rotation distance (15mm)
And l- distance from eye to object
Object height= 1/2pd
Tan theta= 1/2pd (l-z)
Assume object is on a line halfway between eyes. And then convergence angle is prism dioptres so 100 times tan theta. So convert to prism dioptres times by 100.

To check convergence have to be wearing distance rx, not near add as we want them to use their accom not add. If wearing rx at near wd then measure CD to ensure px is looking through the optical centre to ensure no prism.

60
Q

When myopes converge vs hyperopes and Emmetropes

A

When myopes converge and look away from the optical centre= base in prism which appears to move the image further away so they dont have to converge as much, Myopes need to accom less than emmetrope when corrected with spectacles. Myopes don’t need an add as early. Myopes to cl requires more accom.

positive lenses= opposite this gives a base out effect bringing image so hyperopes have to converge more.hyperopes need to accom more. Require add earlier.

For Emmetropes- For emmetropes looking at distant objects the vergence hitting the ocular surface is 0 as parallel rays hit the surface and now if they look at near objects vergence hitting the ocular surface will be -ve and a reciprocal of object distance so for these the eye will have to add positive power to neutralise that. So for them 0-(-ve for near)= plus so lenses change the vergence.

61
Q

If the object is closer than the first focal length or if negative lens

And also why do we multiply by 100

A

if the object is closer than the first focal length or if we have a negative lens= virtual image and image forms in front of the lens= -ve. real objects always have negative distance and vergence or 0 for a distant object at infinity. dont deep just do sign convention.

Why do we multiply by 100-
tan theta= metres for prism diopters we want cm/m as 1 prism dioptre is a deviation of 1cm at a distance of 1m. So to convert from tan theta to diopters multiply by 100.

62
Q

If converging with no specs at the same distance. For centre of rotation distance

A

Specs you measure from the lens, if not measure from corneal apex. Now we dont have that BVD in there which we assume to be 10mm so previous centre of rotation distance of 25mm changes to 15mm so 0.015m.

63
Q

Calculations ocular vergence for distant objects (k)
Talking about l’ and d

And K and B

A

positive lens forms a real image behind the retina at the eyes far point. So l’ is +ve and d=+ve. So l2=l’-d (l2 will be positive and smaller than l’)
negative lens forms a virtual image in front of retina at the eyes far point. So l’=-ve l2=l’-d. So l2 is negative and larger than l’.

B will always be more negative or less positive than k, for myopes both k and b are negative so a is positive and hyperopes k pos b is either less pos or neg so again a will be positive. Accom= positive.

64
Q

Corrected hyperopic and myopic eye

A

Corrected hyperopic eye- parallel light through positive lens will be converging when it hits the surface of the eye (k) diverging light from near object will be less converging or diverging after passing through the lens. Depends on l and F (B) baso L’ will be more positive than L as it will be more converging after the lens.

a corrected myopic eye- parallel light passes through negative lens and will be diverging when it hits surface of the eye. Diverging light from near objects will be more diverging after passing through the lens. L’ will be more neg than L as it is more diverging after the lens. Nidpic

65
Q

Apparent field of view and macular fields of view
Compare fov for plus lens and minus lens

A

Apparent field of view is the field of view limited by the frame only (no lens) dependant on the frame aperture and distance from the frame to the centre of rotation of the eye. So not lens effect.
Apparent macular field of view= 2 theta’. Depends on number of factors eg size of frame, BVD. As increase BVD the fov decreases as you’re essentially getting further away= keyhole effect, tan theta=y/z. Increased Z reduces apparent fov.

Macular field of view- how far the eye can rotate for a lens to form an image

Power and macular field of view- FOV is reduced by the converging effect of a plus lens due to base in effect.
FOV is increased by the diverging effect of a minus lens due to the base out effect.

Difference between apparent field of view and macular fov- apparent fov is the field of view which is limited by the aperture only and the macular fov is the fov which is limited by the frame aperture and the prismatic effect at the edge of the lens.

66
Q

Calculations for total macular fov

A

work out apparent fov and minus prismatic effect and then convert prism into degrees.

67
Q

Peripheral fov plus and minus lens

A

Plus- base in effect as field of view you look through outer part away from nose. Convergence is base out as looking at inner part of the lens. (Base in effect decreases fov)

get a annular scotoma at the edge of a plus lens. The shaded area cannot be seen at the edge of the lens or just beyond the edge of the lens unless the head is moved.
Light travelling along the blue line will bend towards the edge of lens, light travelling between two lines will bend and fall outside the lens so wont be seen outside lens, only light beyond the red line will be seen outside the frame.

Minus lens- base out effect increases fov. Base in effect for convergence.
Area of diplopia at the edge of a minus lens, objects seen both through the edge of the lens and just beyond the lens. Light travelling along the blue line bends towards the centre of the lens and will travel around the red line. Any light travelling between both lines will be seen twice causing diplopia.

68
Q

Apparent speed what happens with positive and minus lenses compared to normal

A

Normal- When an object moves from A to B it will move at the speed of the angle per second eg 60 degrees per second.

Minus lenses- distance diminishes the time is teh same. the image will minify so the angle is smaller so it travels by a smaller amount in the same time so it travels slower. Objects appears to slow down- speed of object is now 50 degrees per second. Only appears not really.

Plus lens- the distance travelled is magnified but time to travel between two points does not change. Object appears to speed up. Object now moves from point a to b in 1 second and the speed of the object is now 80 degrees per second.

69
Q

Cause of the swimming effect in pals

A

when mag differs between eyes in peripheral zones which can be equalised with free form. So the difference in speeds perceived by each eye when a wearer looks through the area of peripheral astigmatism in a varifocal= swimming effect= non tolerance.

70
Q

Explain why myopes converge less through their specs than hyperopes

A

Base in effect of negative lenses at the near point means that an object A will appear to come from object B further away and so the wearer will not have to converge as much when wearing their specs. Or base in effect moves the image out for each eye therefore reducing convergence.

Hyperopes- base out effect of positive lenses means that an object A will appear to come from a closer point B and the wearer would the have to converge more when wearing their specs. Therefore myopes will have to converge less than hyperopes when viewing at the same object distance.

71
Q

What is accomodatio. And explain accom for Emmetropes, ametropia.

Ocular vergence for hyperopes and myopes

A

Accomodation- is the difference between ocular vergence when viewing a near object and that of the ocular vergence when viewing a distant object.

For an emmetrope the ocular vergence when viewing a distant object will be 0 and the ocular vergence when viewing a near object will simply be the reciprocal of the object distance so accom= 0-(1/object distance) remember the object distance will be -ve so we get a positive value for accom.
For an ammetrope we need to work out the ocular vergence for distance and near by ray tracing through the lens and then we subtract the ocular vergence for the near object and that for distant object to get the accom.
accom will always be positive, since ocular vergence for the near object will always be more negative or less positive than the ocular vergence for a distant object.

For a hyperope, ocular vergence will be convergent for an object at infinity and for a near object the light can be less convergent than the distant object, parallel or divergent- less positive.
For a myopes the ocular vergence will be divergence for an object at optical infinity, for a near object the light will be more divergent than for the distance object= more minus.

72
Q

Explain the difference between apparent fov and macular fov-

A

apparent fov is the fov which is limited by the frame aperture only
the macular fov is limited by the frame aperture and the prismatic effect at the edge of the lens

73
Q

Show how a ring scotoma forms around the periphery of a plus lens-hard memorise

A

Base in prism effect at the edge of the positive lens means that light travelling along the solid green line is bent towards the apex and travels along the dotted blue line hitting the edge of the lens. Light travelling at any angle between the solid and dotted lines will be bent so that it falls outside the lens and so will not be seen through the lens. Only light beyond the blue dotted lines can be seen outside the spectacle frame and so objects in the shaded area will not be seen either within or outside the lens and an annular scotoma forms around the edge of the positive lens.

74
Q

Explain why an object appears to move slower when viewed through a minus lens than it does when viewed without the lens

A

An object travelling from A to B when viewed without the lens travels at 60 degrees over second. Through a minus lens there is a mini field image and in the same time the object only appears to move from A to B through an angle of 50 degrees. Since it appears to travel by a smaller amount in the same time it appears to travel slower.

75
Q

Mr W age 45 rx r: -5.50/-0.25 X 30. L: -6.00/-0.50 x 150
his rx has not changed for 2 years and he ran out of daily disposable cls a year ago and ordered some more to same spec previously. He came back saying he’d been given wrong cls and he cannot read in them esp in poor lighting. His va is fine for both distance and near and in specs he didnt have this problem the last time he wore his cls. The cls supplied are correct to the specification- what could be the reason for his problem

A

Pre presbyopes s his amp of accom is just sufficient to comfortable focus at his reading distance when wearing his specs. In his spectacles he does not have to accomodate as much as he does when wearing cls so when wearing cls his amp of accom isnt quite sufficient to focus at his reading distance comfortably. In low lighting the contrast is poorer and the depth of field will be decreased, since the pupil size increases.
His accom amp wouldve been higher a year ago when he last wore his cls

now we know why accoms better in effectivity lecture at the end- as edges of lens become more positive

76
Q

Mrs c 32, Rx RE: +6.75/-2.00 x 180 L: +6.00/-1.50 x 175 what fo you need to consider when choosing and fitting her frame, fi you were to use aspheric or flatter form lenses what difference would that make to your choice of frame
FOV q

A

This is a fov question, you have a high positive rx what determines the fov. Frame size smaller frame smaller fov and will be reduced further by positives frame but larger frame means thicker lenses. BVD smaller the BVD the greater the apparent fov/

Aspheric lenses for positive lenses flatten in the periphery and so have a reduced power therefore reduced prismatic effect in the periphery, so the FOV is greater for aspheric lenses. They also give thinner lenses and so a larger frame can be used without making th lenses too thick.

77
Q

When calculating semi macular fov what assumptions do you make

A

Assumption that lens is centred on visual axis

78
Q

What is the back vertex and what it’s he back vertex power
What is back vertex focal length

What is dioptric power
What is principal power

What is ocular vergence and refraction

A

Back vertex- point where the back surface of the lens intersects the optical axis

Back vertex power- reciprocal of that back vertex focal length. This is the power emerging at the back vertex when the vergence of light entering it is 0.

Back vertex focal length- distance from back vertex to F’

Dioptric power of lens is the amount by which it changes the vegrence of parallel light as it passes through it

Principal power- measured from the principal plane and will be different from Fv’ for thick lenses. This is the reciprocal of second principle focal length but we like to measure from back vertex as we know where it is rather than the principle plane

Ocular vergence- vergence at corneal apex for distant objects. Positive if hyperopes
Ocular refraction- vergence at corneal apex for distant objects when the initial vergence is 0. Light is focused on the macula when eye in relaxed state.

79
Q

What determines the power of a lens or refractive surface

A

surface curvature/ radius
-refractive index. Surface powers= F=n’-n/r
lens thickness and distance between lenses
back vertex distance
object distance- distance or near, amount of vergence changes
lens form
angle of gaze- BVD changes with gaze angle so looking away from optical centre power of lens changes so choose best form lens

80
Q

When we refract what is the aim

And define the far point of the eye

Explain it for hyperopes

A

When we refract the aim is to find the lens with a second principle focus which is coincident with the eyes far point. The second principal far point of the lens and the far point of the eye coincide.

The far point of the eye- is the point from which light needs to be converging for hyperopes or diverging myopes in order for the eye in a relaxed state to be able to focus that light onto the retina. Second principle focus of lens= bvd+ fpd for them two to coincide.

Hyperopes dont have enough positive power in the eye so when in relaxed state need to add positive power to help rays converge from the far point of the eye so that when they hit the lens rays focus on macula whilst eye in relaxed state. Hyperopes far point is behind the retina so need to bring that forward with positive lenses.

81
Q

What happens if we move a positive and negative lens further away so when we increase the BVD

A

+ve lens= decrease positive
-ve lens= increase negative
Make both more negative essentially

Far point stays where it is, F’ moves with the lens by same amount. F’ does not coincide with far point of eye so get blurry image. We have positive vergence at the corneal apex as vergence increases as you get closer to an object or object and here we are getting closer to the image so we have increased convergence at the ocular surface so too powerful and acts like a myope so in front of retina. We need to reduce the power if we want the lens further away for positive lenses so reduce power by increasing focal length.

Doesn’t matter as much for low powered lens as they have a long focal length so F wont change by that much to get a significant difference up to 0.25

Myope- diverging rays at cornea, if we move lens further away it will still be diverging but less as ocular surface is now further away from the image so vergence reduced at ocular surface so the effective power of the cornea at the ocular surface is less negative so we need to increase the negative power of the lens as the effective power has gone too positive in comparison again, so reduce focal length and make more powerful.

BVD errors are significant when rx is more than 4.00D bs say 5
If we decrease bvd closer to eye- +ve lens= increase positive
-ve lens= devrease -ve so now make both more positive
Complete opposite now

82
Q

Back vertex power effective power rearranging equations

A

we know second principle focal length of lens needs to be equal to bvd plus the far point distance. So fv’= fpd+bvd. Rearrange that to get fpd= fv’-bvd
If bvd increases, fv’ must increase by the same amount, as you want it to stay the same so you’ve taken some off due to bvd so need to add some onto the focal length for fpd to stay the same.
increasing focal length= power decreases

For negative- remember sign convention
fv’ and fpd are negative. So -fpd= -fv’-bvd
increasing bvd you have to reduce the focal length by reducing the lens’ negative power.

83
Q

Adjusting corrections for BVD

A

If BVD has been increased by x, to ensure the same effective power the focal length needs to be adjusted to fv’+x so lengthened.
Your new adjusted power= 1/ ans. 1/(fv’+x) answers in m

If bvd has been increased by X in a negative lens, to ensure same effective power again focal length is adjusted to fv’+x but in this case as fv’ is negative it has been shortened. Makes it more negative.

positive lens- increase in bvd need less positive power
negative lens- increase in bvd need more negative power

84
Q

Define near vision effectivity error NVEE

A

the difference between distance and near vergence
Thicker lenses means NVEE is higher

The change of vergence produced by a thick steeply curved lens is not the same for both distance and near- diff between the two is near vision effectivity error. Rate of change of vergence is less for near objects and so near object lens thickness contributes less power. NVEE in thicker, steeper spectacle lenses will be greater than in trial lenses, so may need to increase near rx.

Mainly worry about NVEE for hyperopes with thick lenses eg reading specs. Especially presbyopes as if they are looking at something near they cant accomodate as easily. May need to adjust reading rx so may need to add some extra plus power onto rx after refraction. Not as much for myopes as thinner lenses.

85
Q

NVEE on axis

A

With an object at infinity initial vergence is 0. Vergence coming out of back vertex would be equal to the back vertex power. Object at infinity L1=0 so L2’=Fv’ as L2’=L+Fv’. Emerging=initial vergence+BVP for a distant object.

With a near object at finite distance, we cant predict L2’ = we cant take initial vergence and add the back vertex power to work out the emerging vergence. Initial vergence is no longer 0 so cant use L’=L+F which is used if the object is at infinity. Near vision effectivity comes in to it.

86
Q

NVEE in trial lens vs spectacle lens

A

NVEE distance- thickness contributes positive power but for reading thickness wont contribute as much positive power so they will need some extra positive power for reading sometimes with the trial lens thin so wont have noticed that for reading. For myopes back surface would be less negative so add some more negative to help them get to their true rx.

NVEE is greater in specs than trial lenses bc:
trial lenses- biconvex or Plano convex and smaller aperture so thinner and flatter surfaces. Spec lenses- bulbous+ thick and lens thickness contributes positive power.
So back surface wont be exactly -8.00D as lens thickness contributes some positive power so you need to add some more negative onto it to neutralise that to get the true rx.
So when forming spectacle lens take thickness into account.

Example below- second one thickness provides some pos power so less neg than 8 which means its going to be a bit more positive than 6.00.

87
Q

Why do we have steep lenses

A

bc of best form lenses and tschernings ellipse. + 6.00 back vertex power means the back surface needs to be about -8.00 and the front would be about +14.00D for good off axis performance. (6- -8 bvp-back surface) lens thickness contributes positive power which means lens is effectively more positive so back surface needs to be more negative to cancel out lens thickness pos power.

lens power= change in vergence
we have a difference in effective power of lens thickness
distant object- vergence is greater after the first surface than for a near object.
rate of change of vergence will be greater for the distant object giving a greater effective power over the thickness of the lens.
High rate of change= high NVEE.
think ab NVEE for hyperopes or high adds
flatter thinner lenses difference in vergence is less and rays do not have to travel as far to reach the second surface

88
Q

What is NVEE dependent on

A

dependent on lens thickness+ form. Lenses with similar form will have similar NVEE.

for near- effective power due to the thickness of the lens decreases due to the object being close up. Slope is less so rate of change of power or vergence is less. Closer effective power decreases further it increases.

Trial lenses are often flat lenses whereas most spectacle lenses are curved
A curved lens has one convex and concave surface, in spectacle lens the front surface is usually convex and back is concave
NVEE is greater for thicker steeper plus lenses
compare NVEE of spec lens to trial lens.
Negative NVEE means the addition or positive near rx should be increased.
Taken into account by progressive addition lens designers.

89
Q

Calculation

A

Can use equation for Fv’ to work out back vertex power and then work out focal length and adjust the focal length for new bvd to get new power needed.

Or for longer question working out nvee- need to work out L2’ for both. Could use back vertex power equation or could use step along to work out L2’ and L1’ for the equation. If we are given bvp use it for the near. Use L=0 for distant and re arrange for a surface power F1 or F2 and then use it for the near object and work out L2’ and L1’ and Fv’ and put it in equation.

For near objects- positive thickness contributes less positive power so rate of change is less so you need to add some more positive power for a near Rx add.

REMEMBER= If you adjusted for BVP in previous question, NEW Fv’= FV’ PLUS THE ADD!!!!!!! AND PUT THIS FV’ in the Fv’ equation. Also work out F1 AND F2 FOR FV’ big equation by just putting the powers in from the q.

90
Q

NVEE for plus lenses

A

A- Plano convex trial lens- incident vergence -4 (object at 25cm in front) BVP is +10 for all of them. Plano front surface only 0.004m so all bending happens at back surface which needs to be +10.
B- biconvex trial lens- 5.00D front surface which means back has to be +5 theoretically but NVEE due to it being 25cm away not initial vergence cant assume that you can add them together. Emerging vergence will change as 5mm thickness now which adds some positive power which means back doesnt need to be as positive so its 4.92 so thickness contributed 0.08D positive power.
C- curved surface- front surface power +10 which means back has to be -0.71 as we want plus ten so this means the thickness contributed +0.71 so we had to take it off with the back surface.
D= n= 1.67 flatter curved surface- +10 front surface again, flatter as high index. Rear surface needs to be -0.44 so the positive thickness now only contributes 0.44D of positive power. (Radius greater so flatter as higher n)
E= steeper surfaces thicker lens= 12.00 the back surface here is -3.27 so the back surface wouldve needed to be -2.00 but instead the positive power must have contributed an extra 1.27D as well.

NVEE for all is L2’- (L1+Fv’) True exit vergence- (Incident vergence+ Back vertex power)

91
Q

Near effectivity off axis. Distant and near objects best form= 1 working distance only.

A

To do with best form. When we choose best form for a lens it only works for one working distance.
For distant objects good NVEE as eye rotates.
near objects- best form no longer works as diff wds so get decrease in -ve power

tends to happen w high -ve rxs as negative powers tend to decrease in periphery of lens so you have an effective positive power or a decrease in negative power in these lenses with eye rotation. So pre presbyopes not great accom left so they might discover this in their lenses which may help them see up close so wont have to accomodate as much. Its bc edges of their lens are more positive so wont have to accom much looking down through edge of their lenses sometimes. If you take this edge away from them in cl or aspherics where off axis performance is good they may think they cant read as well now.

(Comparing off axis power for distant object and near. Best form for distant power changes v little in periphery and best form designs do not work for near objects)

92
Q

3) Mrs T is 45 years old and is happy wearing svd spectacles at the moment. Can you think of any reason she might not adjust to cls- she is a myope.

A

Myopes do not have to accomodate as much through specs compared to cls. At 45 mrs t will have low accomodation which could be sufficient when wearing spectacles but not sufficient with cls.
There also may be some off axis decrease in mean negative power in her specs giving effective addition in the periphery of her lenses.
She will also have to converge more with cls, whether this is a problem will depend on her binocular stat

93
Q

4) Mr p is 44 years old and is wearing single vision cr39 specs. His old rx was -5.00/-0.50 x 20 and his new one is -5.25/-0.25x 25. He is happy with near vision through sv and doesnt want multifocals or pals. He would like a larger frame but thinner lenses so you prescribe aspheric lenses. Mr p returns complaining he cant read, why?

A

myopes often benefit from an increase in their positive mean oblique error which is a decrease in negative power in the periphery of their lenses with spherical surfaces. This means their lenses act a little like a varifocal. This may be one reason why some moderate to high myopes dont need a reading add as early or dont need to increase their add as often in single vision reading specs.
aspheric lenses this increase in positive MOE so edge positive power is less so at age 44 mr p will have low accomodative reserves and it is likely he has been using this effect to compensate. By changing from spherical to aspherical lenses he no longer has this advantage and his accom reserves are not enough for him to focus at his usual working distance.

94
Q

2) Is there a better solution, any problems with this solution-

A

high index lenses may have been a better solution since they generally produce better results for minus rxs. However these require flatter surfaces for the same rx so this may reduce the peripheral MOE but not by as much as aspherics
also need to be wary of increased tcas which results from a lower constringence value for higher index materials. This may produce colour fringes or blurring when mr p is using the peripheral zones of his lenses.

95
Q

3) Mrs h 66, rx +5.00/-0.75 x 90 L +5.00/-0.75x 90 Add=2.50D
you give her a pair of varifocals for everyday use and a separate pair of reading specs bc she is a reader and reads in bed has to tilt head in uncomfortable way in varifocals. She returns a few days later and says varis are fine but has to hold book a little further away when using reading specs. She also finds if she slips the specs a little further down her nose where they are fitted she can read much better at her normal reading distance. What may the problem be how would you check and what can you adjust the rx to

A

back vertex distance in the trial frame during the refraction could have been larger than the bvd the specs are fitted to. You would need to check if the bvd was recoded for the trial frame and compare it to the fitted frame. If it was bvd it would persist for distance as well and same for her varifocals. So check but probably isnt that.

If it isnt a problem then it is due to near vision effectivity error. More likely explanation since varifocals are okay as the lens manufacturers for varifocals usually include an adjustment to the addition to compensate for the NVEE which would explain why she can read in her varifocals but not in her reading specs. Assume trial lenses have 0 nvee.

When her specs moved further down nose effective positive power increases which is why she can read more easily when her specs slip down her nose. This suggests she needs more positive power in her lenses.

To check what adjustment you need to make to the rx fit rms h’s specs carefully and over refract. So its not enough positive power. For near objects the positive thickness contribtues less positive power for a near object so need to add some extra positive power for near.

For near- thickness doesn’t contribute as much positive power so need to add some positive reading power at near. Increase. Add.

96
Q

Explain nvee cal one more time

A

So make sure you know the F1 F2 then do step along to work out the real emerging vergence for a near object. L2’

If dont know F2 of F1 re arrange front or back vertex equation to get it. Fv’=adjusted power+add. And then do step along to work out L2’ for near object.

The nvee is the difference between vergence we predicted which is Fv’ (adjusted+add) + initial vergence from step along. Difference between this and the actual value we got for emerging vergence. If NVEE is negative this means that the value is less negative than we want which means the thickness must have contributed that amount of positive power so we then need to adjust the Fv’ and add that nvee onto it to get the new rx. Remember Fv’ is the same as ocular refraction as initial vergence is 0. So add that on so you account for that and give the person their full rx.