fle4 Flashcards
The anomeric carbon of a sugar is …
an invertible epimer
The oxidation of succinate via the citric acid cycle produces one NADH and one FADH2 molecule. What is the ratio of succinate molecules entering the citric acid cycle to the number of ATP molecules formed?
knowing that :
NADH –> 10 protons pumped by ETC / molecule –> 2.5 ATP pumped per proton
FADH2 –> 6 protons pumped by ETC / molecule –> 1.5 ATP pumped per proton
a) 1: 1.5
b) 1:2.5
c) 1: 4
d) 1:5
Answer C is correct. There are a total of 16 protons (10 from NADH and 6 from FADH2) that are pumped back across the inner mitochondrial membrane by the ETC. The NADH molecule produces an average of 0.25 ATP per proton, so the 10 protons pumped per NADH molecule will produce approximately 2.5 ATP molecules. Similarly, the 6 protons pumped due to the FADH2 molecule will produce 1.5 ATP molecules. Together, that is 4.0 ATP molecules per oxidized succinate molecule, or a ratio of 1:4.
Oxytocin is a mammalian hormone with the primary amino acid sequence CYIQNCPLG. The tertiary structure of oxytocin is primarily stabilized by:
A) hydrophobic interactions. B) hydrogen bonds. C) charge-charge interactions. D) disulfide bonds.
d) Oxytocin is a short peptide hormone that is critical during childbirth and other important mammalian processes. Looking at the primary structure, CYIQNCPLG, one can see that there are both polar and non-polar amino acids. But, more importantly, there are two cysteine residues. Answer D is correct because, with two cysteines in close proximity (especially as part of a small peptide with very little additional protein structure) it is very likely that a disulfide bond will form. A disulfide bond in a peptide that is only 9 amino acids long will be the primary source of stabilization.
A new bacteria is discovered that utilizes a novel nucleotide, designated as H. The H nucleotide replaces guanine in the bacteria’s genome and base pairs with cytosine. This bacteria is likely to be highly successful at evading host immune system responses because the:
A) bacteria’s genome will not be recognized by antibodies in the host’s immune system.
B) bacteria will produce new proteins which cannot be detected by the host’s immune system.
C) H nucleotide will disrupt restriction endonucleases that target non-self DNA molecules to degrade them.
D) H nucleotide will make the bacterial surface proteins more similar to human surface proteins.
Answer C is correct. The newly discovered bacterium has a genome that uses ATCH instead of ATCG, but no other changes are described. We are told that H base pairs with C, so one can assume that it behaves in most respects just like G does. Answer C is the best answer because one way that organisms fight foreign invaders is through restriction endonucleases that recognize ‘non-self” DNA sequences. These endonucleases have very specific restriction sites (It would be very dangerous to have endonucleases without specific sites, since they could cleave any DNA). Answer A is incorrect because antibodies are generated against proteins, not DNA molecules. Answer B is incorrect because there is nothing to indicate that new proteins are being generated. If H base pairs with C, tRNA should interact with codons the same way whether H or G is being used. Answer D is incorrect for the same reason, there is no reason to believe the bacteria will produce new proteins, or that those proteins will be more like host surface proteins because of the H for G transition.
A typical blood bicarbonate concentration is 26 mM. Based on Equation 1, what must the carbonic acid concentration be to achieve a pH of 7.0 if the Ka for carbonic acid at physiological temperature is 9.9 ×10–7?
A)2.6 mM
B) 519 mM
C) 20 mM
D) 7.1 mM
Answer A is correct; The Henderson-Hasselbalch equation is given in the passage as Equation 1: pH = pKa + log([HCO3]/[H2CO3]). To solve, we must first convert the Ka given to pKa. pKa = -logKa. First, round the pKa to 10 x 10-7. pKa = -log(10 x 10-7) = -log(1 x 10-6) = 6. Substituting into Equation 1 gives: 7.0 = 6.0 + log(26mM/x). Subtracting 6.0 from both sides yields: 1.0 = log(26mM/x), or 26mM/x = 1 x 101, or 26mM/x = 10. Therefore, x = 26mM/10, and x = 2.6. This is Answer A. Answers B, C and D are obtained through making various calculation errors.
what does an anhydrase enzyme do?
removes water from a single substrate
What equation has reagents responsible for maintaining homeostasis of blood pH?
H2CO3 (aq) + H2O (l) ⇌ H3O+ + HCO3– (aq)
when is pH = pKa?
According to Henderson Hasselbach equation, when the base concentration = acid concentration
Suppose the RNA strand shown below is a segment of viral genomic RNA. Using this RNA as a template, the enzyme reverse transcriptase would produce which of the following nucleotide polymers?
5’ GGAUCCUGAAC 3’
A) 3’ CCUAGGACUUG 5’
B) 5’ GGATCCTGAAC 3’
C) 5’ GUUCAGGAUCC 3’ 3’ CAAGUCCUAGG 5’
D) 5’ GTTCAGGATCC 3’
d
To answer this question, one must remember that reverse transcriptase is an RNA-dependent DNA polymerase and, as such, it will generate a DNA molecule. This means that the answer must contain “T” instead of “U”. It must also be complimentary to the genomic DNA given in the question, 5’ GGAUCCUGAAC 3’.
A normal adult human has approximately 80 mg of copper in their body. Ammonia is normally converted to urea by the liver. Inadequate liver function can result in ammonia reacting with copper (II) ions to form an octahedral complex with which formula? A) Cu(NH4)24+ B) Cu(NH3)42+ C) Cu(NH3)62+ D) Cu(NH3)82+
Answer C is correct. The octahedral shape has six positions occupied by coordinated atoms, so only choice C can be correct. Choice A is a complex that can exist at lower ammonia concentrations, but it is not octahedral. Choice B does not have six coordinated ammonia ligands.
When the muscles of the diaphragm contract, the volume of the lungs is:
increased, and the pressure inside the lungs is decreased.
for a first oder reaction, what are axis on graph?
y axis is Ln (concentration of reagent that is to first order)
x- axis is time
If a patient’s original lung volume (V1) is decreased by 33% (V2), what is the relationship between the total pressure in the patient’s lungs before (P1) and after (P2) this change?
A) P2 = 1/3P1
B) P2 = 2/3P1
C) P2 = 3P1
D) P2 = 3/2P1
The Ideal Gas Law demonstrates that pressure and volume are inversely related. Therefore, if the volume of the lungs is decreased, the pressure inside the lungs must increase. This immediately eliminates answers A and B because they both indicate that the pressure after the change was less than the pressure before the change. Answer C is incorrect because for the pressure after the change to be three-fold larger than the pressure before the change (P2 = 3P1), the lung volume would have had to decrease by a factor of three (a 66% decrease). Because lung volume decreased by only 33%, Answer D is the only possible answer. A simple way to calculate the exact change in pressure is to convert the percentage change in volume to a fraction. A decrease in volume of 33% is equivalent to multiplying V1 by 2/3. Therefore, because pressure is inversely related to volume, P1 must be multiplied by 3/2 (the inverse of 2/3) to give P2. This is Answer D.
what is electrophilic addition?
a reaction where a π (double/triple) bond is broken and two sigma (single) bonds are formed.
what’s ionization energy?
amount of energy required to take a valence electron away from atom- it increases as you go to the right on periodic table because it gets harder to remove a valence electron as you go to non metals and closer to halogens.
The pyruvate dehydrogenase complex (PDH) is naturally inhibited by ATP because:
A) ATP mimics pyruvate, acting as a competitive inhibitor for the ATP synthase enzyme.
B) pyruvate is converted to ATP in a subsequent oxidation step, leading to feedback inhibition.
C) enzymes of this class utilize ADP, rather than ATP, to dehydrogenate substrates.
D) the PDH product generates ATP via the citric acid cycle, leading to feedback inhibition.
D
what’s 1 pascal?
1 n/m^2
One of the bone-resorbing enzymes secreted by osteoclasts requires a covalently bound zinc ion to exhibit normal enzyme function. In this scenario, zinc is acting as:
I. a coenzyme.
II. an allosteric effector.
III. a prosthetic group.
III
Because the question states that the zinc is covalently bound and is necessary for normal function, the zinc is an example of a prosthetic group; which is a non-protein cofactor that is tightly bound to an enzyme and is necessary for its function.
coenzyme are loosely bound
and allosteric effector are bound to a part that is NOT active site.
Which physiological process prevents cross-species fertilization among hominids?
A) Social constraints that prevent interspecies mating. B) Eggs fertilized with sperm from another species are always unviable. C) Cross-species fertilization results in polyspermy and death of the zygote. D) Species-specific receptors on the egg bind species-specific ligands on the sperm.
D-
The mechanism that prevents cross-species fertilization is species-specific receptors expressed on the outside of the egg, which are bound by species-specific ligands expressed on the outside of the sperm. Answer D is therefore the correct answer. Social constraints may be a tempting answer because human beings would logically express social opposition to interspecies mating, but this is neither a physiological process, nor would it prevent fertilization if mating did occur contrary to social constraints. Eggs fertilized with sperm from another species do not always die, if the genetic material is almost identical. An example is the ability of a horse and a donkey to mate and produce a mule. Therefore, Answer B is incorrect. Answer C is incorrect because there is no reason to believe that polyspermy, or the fusion of more than one sperm with the egg, would automatically occur if a sperm and an egg were from two different species. It may also be helpful to note that only Answers A and D would actually prevent fertilization. Answers B and C allow for fertilization, but the fertilized egg or zygote is unviable. Because the questions stem asks for something that PREVENTS fertilization, this is another reason to dismiss choice B and C.
Which physiological mechanism is LEAST likely to result in a significant decrease in blood acidity?
A) Exhalation of carbon dioxide
B) Release of H3PO4 into the blood stream
C) Conversion of bicarbonate to carbon dioxide in the blood
D) Excretion of protons into the urine by the kidneys
Choice B is the best answer. The major physiological mechanisms used to control blood pH include exhalation of carbon dioxide, conversion of carbon dioxide into bicarbonate in the blood, and the excretion of protons through the kidneys. In the precise way they are stated here, all three mechanisms will decrease blood acidity (i.e., increase blood pH). Answer A will decrease blood acidity according to Le Chatelier’s Principle as it is applied to the following equation:
CO2 + H2O ⇄ H2CO3 ⇄ H+ + HCO3-
Calcium is a necessary structural or functional component in which of the following processes?
I. Bone tissue formation II. Blood clotting III. Muscle contraction IV. Nerve signal transmission A) I and IV only B) III and IV only C) I, III, and IV only D) I, II, III, and IV
Choice D is correct. Calcium combines with phosphate and hydroxide in hydroxyapatite, the major component of the extracellular bone matrix.
An experiment focused on anaerobic respiration in muscles under hypoxic conditions should focus on which cellular compartment?
A) Mitochondrial matrix B) Mitochondrial intermembrane space C) Cytoplasm D) nucleus
Choice C is the correct answer. In mammalian cells, anaerobic respiration is the alternative pathway taken when oxygen is not available for oxidative phosphorylation, such as during the oxygen debt created during extended periods of exercise. Glycolysis occurs in the cytoplasm and the products from that pathway will be the final electron acceptors to produce lactic acid. Because this occurs in the cytoplasm rather than the mitochondria, Answer C is correct.
how do protein based vaccines work? what do they recognize?
Vaccines that are protein-based work because the antigens they contain resemble the antigens of the invading pathogen. For example, viral vaccines usually contain viral capsid proteins, and bacterial vaccines contain surface proteins. This allows the host immune system to initiate a primary immune response and prepare for a secondary immune response without an actual pathogen infection.
Although the average pKa of the Glu side chain is approximately 4.2, the enolase enzyme contains a glutamate in its active site that is protonated at physiological pH. This Glu residue is protonated because:
A) it is buried in the center of the protein, inhibiting proton dissociation.
B) enolase functions inside of lysosomes, where the pH is naturally much lower.
C) the local environment lacks a basic molecule to act as a proton acceptor.
D) the local environment increases the pKa of the Glu side chain.
D- Choice D is the correct answer. The local environment causes the pKa of the Glu side chain to become more basic, causing the proton on the Glu side chain to remain bound. Answer A is not correct since the active site of most enzymes is on or near the surface of the protein, making it accessible to the surrounding solvent, not buried inside the core of the protein (which is usually almost exclusively hydrophobic). Answer B is incorrect since enolase is one of the enzymes of glycolysis, which occurs in the cytoplasm, not in lysosomes. Further, a lower pH doesn’t change the pKa of the side chain; rather, the pKa value tells us the approximate pH at which the proton will be 50% dissociated. Answer C is not correct since the active site is exposed to the aqueous cellular fluid and water is a common proton acceptor.