Finite Dimensional Vector Spaces Flashcards

1
Q

Linear combination

A

A linear combination of vectors v₁,…,vₙ is a vector λ₁v₁ + … + λₙvₙ

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2
Q

0 is regarded and a L.C. of …

A

any set

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3
Q

Subspace spanned by A (span A)

A

is the set of linear combinations of vectors from A

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4
Q

proposition 5.4 (span A is a subspace)

A

if A⊆V the the set of vectors span A is a subspace of V

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5
Q

How to find the span of a set of vectors {a,b,c…}

A
  1. put all the vectors in a matrix (as rows)
  2. apply row operations to get into echelon form
  3. the span of {a,b,c…} is equal to the span of all the non-zero rows
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6
Q

How to determine if a vector is part of a spanning set

A

if a vector can be written as a L.C. of the vectors in the spanning set then it is inside the span

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7
Q

How to find a vector that is not in a spanning set

A
  1. take a vector that is in the span

2. change is last element to 0 (or some other value that isn’t a multiple

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8
Q

Proposition 5.6. if W⊆V then for A⊆W we have

A

(1) A ⊆ span(A) ⊆ W
(2) A ⊆ span B so span A ⊆ span B
(3) if x is in span A then span A = span A U {x}

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9
Q

linearly dependent

A

if there is a linear combination λ₁v₁ + … + λₙvₙ = 0 where not all λs are equal to 0

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10
Q

linearly independent

A

not linearly dependent.

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11
Q

How to prove a set is linearly independent

A
  1. take an arbitrary L.C. λ₁v₁ + … + λₙvₙ = 0
  2. prove all the scalars are equal to 0
    OR
  3. put all the vectors in a matrix (as rows)
  4. use row operations to get into echelon form
  5. if a row can be made as a linear combination of the others then not linearly independent
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12
Q

if X is linearly independent OR dependent then any subset of X

A

remains linearly independent or dependent

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13
Q

The empty set is linearly…

A

independent

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14
Q

Proposition 5.11. linear dependence of subsets

A

if X is linearly dependent then so is every subset of X

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15
Q

Theorem 5.12. subset of A that is L.I with the same span.

A

If A⊆V then there is a linearly independent B⊆A s.t. span A = span B

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16
Q

How to find a linearly independent subset B of A with the same spanning set

A

for each vector in B: if a is linearly independent to current B (start from {}) add a to B. If not linearly independent then discard

17
Q

Theorem 5.14. subset of A that is L.I with the same span (2nd thrm)

A

If C⊆A⊆V where C is independent, then there is an independent subset B⊆A containing C for which span A = span B

18
Q

basis

A

a subset B⊆V which is linearly independent s.t. spanB=V

19
Q

The Exchange Lemma

A

if b∈span(AU{a}) and b∉span(A) then a∈span(AU{b}).

Also if AU{a} is independent then so is AU{b}

20
Q

Theorem 5.20. Sizes of spans.

A

if A,B⊆V are independent and A⊆spanB then |A|≤|B|

21
Q

span S

A

is the set of all linear combinations of the vectors in S

22
Q

If C is independent and A is a basis of V then B…

A

is a basis of V containing C

23
Q

dimension

A

If B is a basis of V then |B| is the dimension of V

24
Q

Corollary 5.21. size of bases.

A

if A,B⊆V are bases of V then |A|=|B|