Eigenvectors / Eigen Values (Cayley Hamilton) Flashcards
eigenvector/eigenvalue of a matrix
Is A is an nxn matrix over a field 𝔽 and v∈𝔽ⁿcol is non zero then v is an eigenvector with eigenvalue λ when
Av=λv
(where A is a matrix that represents a linear map)
An eigenvector has…
exactly one eigenvalue
An eigenvalue has…
many possible eigenvectors
if v is an eigenvector then…
every multiple of v is also an eigenvector
0 can and cant be…
0 can be an eigenvalue
0 can’t be an eigenvector
eigenspace
If λ is an eigenvalue, the corresponding eigenspace is given by key(f-λI) and is the set of all non zero eigenvectors corresponding to λ.
Eigenvalues are the roots of the equation…
det(f-xI) = 0
each eigenspace has dimension…
atleast 1
0 is an eigenvalue of f iff…
iff the nullity of f is non-zero
Lemma 9.3. eigenvalue of a square matrix.
A scalar λ is an eigenvalue of a square matrix A if and only if n(A-λI)>0
Corollary 9.5
A scalar λ∈ℂ is an eigenvalue of an nxn square matrix A (over ℂ or ℝ) iff det(A-λI)=0
If det(A-λI)=0 then…
there are infinitely many eigenvectors for λ
How to find eigenvalues
solve det(A-xI)=0
How to find eigenvectors
- find A-λI
- put into echelon form
- find ker(A-λI). Extract equations from this form.
- if equations each in terms of two variables only, put into a vector
- otherwise let x = equation in terms of other two variables. let a=y, b=z and write a () + b () where you put 1s in correct position for y and z in each and in x position put the coefficients of the equation.
if λ is an eigenvalue of a then:
- there is a v s.t. Av = λv
- dim ker (A - λI)>0
- nullity (A- λI) > 0
- rank (A - λI) < n
- det(A-λI)=0 (i.e. matrix is not invertible)