Final Exam Review Section 6

Question 1

STP Values

Answer 1

T = O deg Celsius or 273.15 K
Pressure = 1 atm

Question 2

Pressure Conversion

Answer 2

1 atm = 760 mm Hg = 760 torr = 1.013 bar = 14.7 psi = 101.32 kPa = 101320 Pa

Question 3

Ideal Gas Law Eq

Answer 3

PV = nRT
P-atm
V-Liters
T-Kelvin
R- .0821 (Latm/molK)

Question 4

Boyles

Answer 4

P1V1 = P2V2
p-atm
V-Liters

Question 5

Charles

Answer 5

V1/T1 = V2/T2
V-Liters
T-Kelvin

Question 6

Avogadro’s

Answer 6

V1/n1 = V2/n2
V-Liters
n-# of moles

Question 7

Combined Gas Law

Answer 7

(P1V1)/T1 = (P2V2)/T2
P-atm
V-Liters
T-Kelvin

Question 8

Gay-Lussac

Answer 8

P1/T1 = P2/T2
P-atm
T-Kelvin

Question 9

Density

Answer 9

Density = (PM)/(RT)
P-atm
M-Molar mass
T-Kelvin
R- .0821 (Latm/molK)

Question 10

P total

Answer 10

P total = PA + PB + PC

Question 11

PA

Answer 11

PA = XA*P total
Where XA is the % composition

Question 12

Kinetic Energy

Answer 12

KE = 1/2(mu^2)
m-mass in kg
u-speed in m/s

Question 13

Root-mean-square speed

Answer 13

= sqrt[(3RT)/M]
where
T-Kelvin
M-molar mass in kg/mol
R- 8.314 J/(K*mol)