Feb. 19th (Exam 2) Flashcards

1
Q

What is the first general phase of B-cell development?

A
  1. Repertoire assembly in the bone marrow
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2
Q

What distinguishes undifferentiated precursor/progenitor cells?

What is present on all hematopoietic stem cells?

A

Cell-surface markers

CD34

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3
Q

What are Pro-B cells?

Can they still self renew?

A

These are the earliest identifiable cells of the B-cell lineage.

They have retained a limited capacity for self-renewal and can make other pro-B cells and cells that further develop.

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4
Q

What is the stroma?

A

This is the supportive cells and connective tissue of any organ.

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5
Q

What do bone marrow stromal cells do?

A
  1. They interact with the developing B cells through adhesion molecules.
  2. They produce growth factors that act on the attached B cells.
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6
Q

What was the example of the adhesion molecule that we saw holding B cells to the bone marrow?

What was the growth factor that is produced on the surface of bone marrow stromal cells that binds to the B cells?

What on the B cells allows for this?

What is the cytokine secreted by the bone marrow stromal cells that acts on Late Pro-B cells and Pre-B cells?

A

CAM - Cell Adhesion Molecule

SCF (Membrane bound Stem Cell Factor) binds to Kit

Interleukin 7 or IL-7

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7
Q

Where do the most immature B-cells reside in regards to the bone marrow stromal cells?

A

Sub Endosteum

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8
Q

Where do maturing bone marrow cells go?

A

Towards the central axis (interior surface) - they don’t need as much contact with the surrounding stromal

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9
Q

What makes gene rearrangement inherently imprecise and inefficient?

Explain.

A

The addition of P and N nucleotides during the junction of heavy chain parts (junctional diversity)

These additions can shift the reading frame so bad that it does not code for a functional heavy chain.

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10
Q

For each junction what are the chances that we maintain the correct reading frame?

A

33%
!!!

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11
Q

What is a non-productive rearrangement?

A

A non-productive rearrangement happens when there is a gene rearrangement that results in a non-functional protein.

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12
Q

What is one advantage we have against those horrible odds of 1/3 being faulty?

A

Every B cell has two copies of the immunoglobulin heavy-chain locus.

So… if one of the rearrangements on chromosome n is bad, the cell may still have a chance to complete another rearrangement on the homologous chromosome.

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13
Q

What happens if negative rearrangements are made on both homologous chromosomes?

A

The cell will certainly undergo apoptosis.

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14
Q

What are E2A and EBF?

What do they do?

When are they used to turn stuff on?

A

They are transcription factors.

  1. They are responsible for the transcription of Pax-5 TF
  2. RAG 1+2
  3. . VpreB and 5 surrogate light chains

TFs active in early-pro B cells.

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15
Q

What is Pax-5?

What does it do?

A

It is a transcription factor that is turned on by E2A and EBF.

  1. Responsible for transcription of the Ig(alpha)
  2. Responsible for transcription of cell surface protein CD19
  3. Also helps transcribe the surrogate chains

TF is used in the late pro B cell

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16
Q

Why is the first rearrangement event joining the heavy D and J segments relatively efficient?

A

Because no matter where D ends up getting attached to the J segment, can be read (transcribed) no matter how it is attached - it works no matter which reading frame we are in.

17
Q

What is the default for B cells in development?

What is needed for survival and continued differentiation?

Define this.

A

Apoptosis

Survival Signals

Survival Signals are positive signals for survival and further differentiation.

18
Q

How many of the Early Pro-B cells make it to the Late Pro-B cell stage?

How many of the Late Pro-B cells make it to the Large Pre-B cell phase?

A
  1. Most of them make it because D-J rearrangement is pretty good.
  2. Only 50% make it because of non-productive rearrangements.
19
Q

What are the criteria that a Pro-B cell must satisfy before it is allowed to become a Pre-B cell?

A
  1. They must make a mu heavy chain
  2. They must be able to demonstrate the ability of the mu heavy chain to combine with an immunoglobulin light chain.
20
Q

How does a Late Pro-B cell demonstrate the ability to bind its newly made heavy chain (mu) with a light chain if there are no light chains yet?

A

There are separate genes that are used as Surrogate Light Chains.

Surrogate Light Chains are made up of two proteins whose genes are found at different loci and are conventional and require no rearrangement:

  1. VpreB - pseudo variable region
  2. Lambda 5 pseudo constant region
21
Q

What all happens within the ER of the Late pro-B cell?

A

The heavy chain that was just made has a chance to combine with VpreB and Lambda 5 and Ig(beta)-Ig(alpha) to form a complex that looks similar to that of the B-cell Receptor

This is called the Pre-B cell receptor

22
Q

What is the job of Ig-(beta)?

A

Survival Signals

It acts as a pathway for signal transduction (from the complete pre-B cell receptor) to shut down the gene rearrangement of the immunoglobulin heavy chain.

It also drives the Late Pro-B cell into several rounds of cell division that give rise to a clonal population of pre-B cells.

23
Q

Once the DNA that contains the VDJ rearranged sequence through the C (mu), how does the mRNA get cleaned up so that it can become a functional heavy chain within the ER?

A

It is cleaned up via RNA splicing.

24
Q

How is allelic exclusion ensured in Late Pro-B cells transitioning to Large Pre-B cells

A
  1. There needs to be proper Pre-B cell Receptor assembly.
  2. Ig (beta) acts as a signal transducer to signal for the RAG gene to stop being transcribed
  3. Ig (beta) acts as a signal transducer for the RAG protein to be degraded
  4. Ig (beta) acts a signal transducer to restructure the chromatin of the heavy chain locus.
25
What is the advantage of having allelic exclusion? What is the issue with having B cell receptors that have low affinity binding?
We get homogenous B-cell receptors that have high-avidity binding. It only becomes a massive problem when we consider that the first antibodies that would be produced would be IgM (pentameric) and they are already low affinity but their quantity allows them to have relatively higher avidity. But in this case, only 1% of the polymers would have the same specificity for all 10 binding sites.
26
What are the characteristic of the Large Pre-B cell before it has started the light chain rearrangement?
1. The surrogate chains are no longer made. 2. They have identical heavy chains 3. They don't make the Pre-B cell receptor.
27
What is required before we can see rearrangement of the light chains?
RAG gene is turned back on.
28
Which type of light chain is rearranged first? Kamma or Lambda?
Kamma
29
What advantage does a single light chain locus (one chromosome) have in rearrangement? Why is it not possible for the heavy chain to do this?
It is able to keep trying on the same one if it has a nonproductive recombination. Because the first two arrangements that join a V to D and J excise all the other D segments.
30
When can we officially know something is a small Pre-B cell?
Once the light chain rearrangement has begun.
31
What is responsible for the 85% success rate that we can see in the light chain rearrangement of B cells?
1. 4 different light chain loci (2x K and 2x Lambda) 2. Multiple attempts per locus
32
Explain the shift from a small Pre-B cell to an immature B cell. How is the control of the now mature B-cell receptor different than that of the pre-B cell receptor?
The light chains are made and assembled with the (mu) heavy chain in the ER. They associated again with Ig (alpha) and Ig (beta). They both signal to stop the rearrangement, but the B-cell receptor has regulation that consists of both allelic exclusion and Isotype exclusion - ensuring only one type of light chain is used.