Exam Questions Paper 1 Bio Flashcards
How to test for non reducing
1.Heat with acid and neutralise
2.Heat with Benedict’s solution
3.red precipitate if present
Role of dna polymerase in dna replication
Joins the adjacent nucleotides on new strand via condensation reaction
Semi conservative replication
1.Dna helicase breaks down hydrogen bonds between complementary bases
2.Two strands act as a template
3.Dna nucleotides attached to exposed complementary base pairing
4.Dna polymerase joins adjacent nucleotides on new strand via condensation reaction
5.two daughter cells
Water
Solvent -reaction occurs faster
Polar molecule- acts as a solvent
Metabolite -water is reactive
Strong cohesion -this supports the water columns
Give two ways which the structure of starch is similar to cellouse
- There both polysaccharides
- Monomers are linked by glycosidic bonds
Give two ways in which the structure of starch is different from cellulose
- Starch is a polymer of a-glucose
2.strach is coiled
Explain the difference in the structure of the starch molecule and cellulose molecule shown in disarray above
- Starch is a polymer of a-glucose , whilst cellulose is a polymer of b-glucose
- Hydroxyl and hydrogen groups on carbon 1 are inverted
Explain one way in which starch molecules are adapted for their function in plant cells
Starch molecules are helical so are very compact
Explain how cellulose molecules are adapted for their function in pant cells
- Cellulose are long and straight
- Which are linked by hydrogen bonds this forms fibres called fibrils
- Which provide strength to cellulose can support cell wall
Monosaccharides and disaccharides taste sweet
The lactose free milk made after hydrolysis with lactase taste sweeter than the cows milk containing lactose
Suggest why
- Lactose is hydrolysed to glucose and galactose
- More sugar molecules are present
Which part of a phospholipid bilaterally is formed from a particular molecule
Glycerol
Explain the importance of maintaining a constant blood ph 3marks
Enzymes in the blood are sensitive to changes in ph
Changes in oh can change the tertiary structure of the active site
This means that fewer enzyme substrate complex can be formed
Suggest how binding of cyanide to cytochrome oxidases the affects of enzymes
Cyanide acts as a competitive inhibitor
so blocks the active site of cytochrome oxidases
This means fewer enzyme substrate complex can be formed