equations//reactions Flashcards
Metal + acid –>
Metal salt + H^2
Metal + water –>
Metal hydroxide + H^2
Metal carbonate + acid –>
Metal salt + carbon dioxide + water
How many moles are there in 12g of carbon-12?
n = m / Mr
= 12g / 12g/mol
= 1 mole
How many atoms are there in 2 moles of carbon-12?
No. of atoms = N~A * n
= (6.02 10^23) 2
= 1.204 * 10^24 atoms
If 2H~2 and CO~2 are products and hydrogen is useful, what is the atom economy?
“Mr of all = 48
Mr of 2H~2 = 4
Atom economy = (4 * 100%) / 48 = 8.33%
Atom economy is 8.33%”
The mass of CuSO~4.xH~2O = 6.8g and the mass of anhydrous CuSO~4 = 4.35g. Find x
xH~2O = 6.8g - 4.35g = 2.45g
N = m / Mr is used for the CuSO~4 and the H~2O
Water = 0.1361 mol
Anhydrous salt = 0.027 mol
Ratio of anhydrous salt to water = 1:5
CuSO~4 + 5H~2O
x = 5
What volume is taken up by 10 mol of CO~2?
“N = V / 24
V = 24N
V = 24 dm^3 mol^-1 * 10mol
V = 240 dm^3”
Find the volume of 64g of O~2 gas
“2 formulas are needed here
N = m / Mr = 64g / 32
2 moles of oxygen gas
V = 24N
V = 24 * 2
V = 48dm^3”
“SiCl~4 + 2H~2O
There is 5g of SiCl~4.
Find the mass of the 2H~2O”
“The ratio of moles from SiCl~4 to 2H~2O is clearly 1:2 due to the amount of molecules
N = m / Mr = 5g / 170.1 = 0.0294
Number of SiCl~4 moles = 0.0294 mol
Using the ratio, 2H~2O has 2 times more moles than SiCl~4
0.0294 * 2 = 0.0588
There are 0.0588 mol of water”
What temperature gives a molar volume of 24dm^3 mol^-1?
“P = 101kPa (as usual) = 101000Pa
V = 24dm^3 = 0.024m^3
n = 1 mol
R = 8.314
PV = nRT
T = PV / nR
T = (101000 0.024) / (1 8.314)
T = 291.6K”
Find the concentration of 0.0032 mol of HCl dissolved in 250cm^3
“n = 0.0032 mol
V = 250cm^3 = 0.25dm^3
n = c * V
c = n / V
c = 0.0032 / 0.25
c = 0.128 mol dm^-3”
“Find the mass of KOH needed to prepare 250cm^3 of a 0.2mol dm^-3 solution
The Mr of KOH = 56.1”
“V = 0.25dm^3
c = 0.2 mol dm^-3
n = c * V
n = 0.25 * 0.2
n = 0.05mol
m = n * Mr
m = 0.05 * 56.1
m = 2.805g”
“2NaOH + H~2 SO~4
Acid volume = 0.02365dm^3
Alkali volume = 0.025dm^3
Alkali concentration = 1.25 mol dm^-3
Calculate the concentration of the acid”
“n of alkali = c V = 0.025 1.25
= 0.03125 mol
2 alkali molecules and 1 acid molecule
Ratio = 2:1
n of acid = n of alkali / 2 = 0.03125 / 2
= 0.015625 mol
So c of acid = n / V = 0.015625 mol / 0.02365 dm^3
= 0.6607 mol dm^-3
Concentration of acid is 0.6607 mol dm^-3”
“A solution contains 0.564g of CaCl~2 in 250 cm^3 of water
Find the mass concentration
“
“Mass concentration = 0.564g / 0.25dm^3
= 2.26 g dm^-3”
“A solution of NaOH has a concentration of 0.25 mol dm^-3
Calculate the mass concentration”
“Mass concentration = 0.25 * 38
= 9.5 g dm^-3”
How do the 4 main acids dissociate?
“H~2 SO~4 –> 2H+ + SO~4 2-
HCl –> H+ + Cl-
HNO~3 –> H+ + NO~3-
CH~3 COOH –> H+ + CH~3 COO-“
How many chlorine ions surround each sodium ion and how many sodiums surround each chlorine in sodium chloride?
“6 sodium around each chlorine
6 chlorine around each sodium”
How would you draw water in 3D?
“It has 2 bonded pairs and 2 lone pairs
So it is non-linear
Draw with an O in the middle
Show 2 hydrogens with a 104.5 bond angle
Also draw the 2 lone pairs”
What is the polarity of a C-H bond? You need to remember this
“Non-polar
Unusual as it seems”
What is the IMF for HCl?
“Permanent dipole-dipole forces
You have to remember this”
“Describe and explain how electrical conductivity in mercury bromide and in mercury in both solid and molten states
5 marks”
“HgBr~2 conducts when molten but not when solid
Because ions are free to move in molten state
But ions are in a FIXED LATTICE in solid state
Mercury conducts in both states
Because delocalised electrons carry charge in both states”
“There are 3 carbons in the chain
There is a chlorine on the first and second carbon
Name this organic”
“The base alkane is propane
So it is called:
1, 2 - dichloropropane”
“The base alkane is ethanol
If there are 3 bromines on one of the carbons
What is the name of this organic?”
1, 1, 1 - tribromoethane
If there are 4 halogens on an organic, what is the prefix used before the halogen name?
Tetra
E.g 1, 2, 3, 4 - tetrafluorobutane
“What are the 3 structural isomers of C~5 H~12?
Give their names and structural formulas”
“Pentane
CH~3 (CH~2)~3 CH~3
2-methylbutane
CH~3 CH(CH~3) CH~2 CH~3
2,2-dimethylpropane
C(CH~3)~4”
What are the 5 structural isomers of C~6 H~14?
“Hexane
2-methylpentane
3-methylpentane
2, 2-dimethylbutane
2, 3-dimethylbutane”
What are the 2 structural isomers for C~3 H~7 Cl?
“1-chloropropane
2-chloropropane
“
What is the combustion equation for hexane?
“C~6 H~14 + 9.5O~2
–>
6CO~2 + 7H~2 O
What is the incomplete combustion of pentane?
“C~5 H~12 + 5.5O~2
–>
5CO + 6H~2 O
What is the complete combustion of propanol?
“C~3 H~8 O + 4.5O~2
–>
3CO~2 + 4H~2 O”
“What do you have to always remember in combustion of alcohols?
Don’t forget that there is always one oxygen on the LHS when you try to balance it
How is homolytic fission shown in an equation?
“H~3 C-CH~3
–>
H~3 C• + •CH~3
The 2 products are radicals”
“How do you write an equation for heterolytic fission?
“
"H~3 C-Cl --> H~3 C+ \+ Cl-"
Show the addition reaction of but-2-ene and water
“C~4 H~8 + H~2 O –> C~4 H~10 O
Butan-2-ol is formed”
What are the initiation, propagation and termination stages of CH~4 + Br~2?
Initiation:
Br~2 –> Br• + Br•
Propagation:
CH~4 + Br• –> CH~3• + HBr
CH~3• + Br~2 –> CH~3 Br + Br•
Termination:
Br• + Br• –> Br~2
CH~3• + CH~3• –> C~2 H~6
CH~3• + Br• –> CH~3 Br
This works for any alkane and any halogen
Show how chlorine and ethane can react to form a molecule with 4 carbon atoms
Initiation:
Cl~2 –> Cl• + Cl•
Propagation:
C~2 H~6 + Cl• –> C~2 H~5 + HCl
Termination:
C~2 H~5• + C~2 H~5• –> C~4 H~10
This isn’t all of the possible stages but only the ones needed to make C~4 H~10
Show how oxygen gas forms ozone
“O~2 –> 2O•
O~2 + O• O~3”
What is the general equation for how ozone is removed?
O~3 + O –> 2O~2
“Show how CFCs remove ozone
“
“Initiation:
CF~2 Cl~2 –> Cl• + CF~2 Cl
Propagation:
Cl• + O~3 –> ClO• + O~2
ClO• + O –> Cl• + O~2
Overall:
O~3 + O –> 2O~2
Show how NO• removes ozone
We don’t need to know initiation here
Propagation:
NO• + O~3 –> NO~2• + O~2
NO~2• + O –> NO• + O~2
Overall:
O~3 + O –> 2O~2