equations Flashcards
relative atomic mass
(1st isotope x abundance) + (2nd isotope x abundance) / 100
mass of element in compound
(mass of element in compound / mass in compound) x 100
moles in a solid
mass
—————————
mr (molecular mass)
atom economy=
mass useful product
—————————— x100
mass of all products
% yield =
actual
————— x100
theoretical
1st stage of theoretical yield
1) no of moles :
mass
———
mr
second stage of theoretical yield
ratio:
CaCo3 | 2CaO
1 | 2
0.1 mole | 0.2 moles
what is stage 3 of theoretical yield
answer question
mass = moles x mr
how to find limiting factor
mass
———
mr
least is limiting factor
concentration
moles
————————
volume of solution
cm^3 > dm^3
x1000
moles in a liquid
concentration x volume
———————————
1000
moles in a gas
volume
———
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