Equations Flashcards

1
Q

Amount of substance

A

“n” used to count the number of particles in a substance

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2
Q

Unit for amount of substance

A

Mole

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3
Q

Avogadro constant

A

The number of particles per mole, 6.02 x 10^23 mol-1

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4
Q

Molar mass

A

The mass per mole of a substance, units g mol-1

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5
Q

Empirical formula

A

The simplest whole number ratio of atoms of each element present in a compound. You divide the mass of the elements by their mr, then divide that by the smallest number to get the ratio. You may have to multiply to get a whole number and not a decimal.

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6
Q

Molecular formula

A

The number and type of atoms of each element in a compound. You divide the mr of the actual compound by the mr of the empirical formula. You then multiply the empirical formula to get this number.

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7
Q

Hydrated

A

Water molecules are part of the crystalline structure

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8
Q

Water of crystallisation

A

The water molecules which are part of the crystalline structure

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9
Q

Anhydrous

A

When the water molecules are no longer part of the crystalline structure

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10
Q

How to find the water of crystalline

A

Calculate the moles of water by dividing the mass change by the mr of water. You divide the anhydrous compound by its mr to find its moles. You find the ratio between the two moles to figure out the water of crystallisation.

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11
Q

Moles, mr, mass

A

moles = mass/ mr

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12
Q

Moles, volume, concentration

A

concentration = moles / volume

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13
Q

moles, volume

A
moles =  volume (dm) /24
moles = volume (cm)/24000
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14
Q

Ideal gas equation

A
PV = nRT
pressure (pa)
n=mol
volume m^3
Temperature K
R= ideal gas constant 8.31
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15
Q

Nitrate

A

NO3 -

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16
Q

Carbonate

A

CO3 2-

17
Q

Sulphate

A

SO4 2-

18
Q

Hydroxide

A

OH -

19
Q

Ammonia

A

NH4 +

20
Q

Zinc

A

Zn 2+

21
Q

Silver

A

Ag +

22
Q

cm^3 to m^3

A

x 10^-6

23
Q

Dm^3 to m^3

A

x 10^-3

24
Q

C to k

A

+273

25
Q

Kpa to Pa

A

x 10^3

26
Q

Why do we use balanced equations

A

To find out the exact ratio of products and reactants

27
Q

Percentage yield

A

(actual yield / theoretical yield) x 100

You find out the theoretical yield by using moles

28
Q

Atom economy

A

Sum of mr of desired product / sum of mr of all products

x100

29
Q

Why is atom economy important

A

Improving atom economy makes industrial processes more efficient, preserves raw materials and reduces waste