EOY Test Flashcards
Grams to Moles
Divide
Moles to Grams
Multiply
Percent composition first thing
Find molar mass
Percent composition 2nd thing
Take the mass of each element and divide by the molar mass
Percent composition 3rd thing
Times the answer by 100 ( this will be your answer)
How much Al could be produced from 20.36g of Al2(SO4)3. Give how to set up Step 1
Write g of (element) over the given grams. Then write the percent composition of the element over 100.
How much Al could be produced from 20.36g of Al2(SO4)3. Give how to set up Step 2
Cross multiply then divide both sides by 100
Empirical formula step 1
Percent given for one element times 1 mole divided by the mass of said element ( same thing for each element)
Empirical formula step 2
Divide all answers by the lowest/smallest answer. The answer you get for that element goes to that specific element
Molecular formula step 1
Find the molar mass of the empirical formula
Molecular formula step 2
Divide the given mass by the calculated molar mass g/cg.
Molecular formula step 3
Take your answer and multiply it by the whole empirical formula. ( this should be your answer)
Mole
A unit of measurement to quantify the amount of a substance
Molar mass
The mass of one mole of a substance
Formula mass
The sum of the average atomic masses of a compounds elements
Percent yield
The percentage of what was made compared to what could have been made in a reaction
Percent composition
The percentage of each element in a compound based on their masses
Actual yield
The amount of product that was made and measured in a reaction
Theoretical yield
The amount of product that should be able to be made in an reaction
Avogadros number
The number of particles in exactly one mole of a pure substance
Limiting reactant
The reactant that gets used up first in a reaction
Excess reactant
The reactant that does not determine the amount of product made in a reaction
