Energy Flashcards

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1
Q

What factors affect the energy transferred when

charge flows through a component?

A

● Amount of charge
● The potential difference across the
component

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2
Q

Give an equation linking energy, current and p.d.,

giving all SI units

A

energy (J) = p.d. (V) x current (A) x time (s)

E = VIt

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3
Q

Define potential difference in terms of charge

A

The work done per unit charge

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4
Q

Give an equation relating potential difference to

charge

A

energy transferred (J) = charge (C) x p.d. (V)

E = QV

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5
Q

When an electrical current flows through a resistor why does it heat up?

A

There are collisions between the electrons and the ions in the resistor’s lattice. This causes a transfer of kinetic energy into thermal energy, which is released into the surroundings

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6
Q

How do low resistance wires reduce unwanted energy transfers?

A

A smaller resistance will mean there are fewer collisions, therefore less energy will be wasted through heating

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7
Q

What are some advantages of the heating effect?

A

It is useful for appliances such as
toasters or electrical fires, where the
heat is the desired product.

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8
Q

What are some advantages and disadvantages of

the heating effect?

A

● The loss of energy as heat energy can
make an appliance inefficient
● If an appliance overheats it can catch fire or
overheat, which could ruin the device or
injure the user

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9
Q

The energy transferred per second is also known

as…

A

Power

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10
Q

Define Power

A

The rate of energy transfer, or the rate at which work is done

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11
Q

What are the units of power?

A

Watts, W

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12
Q

Give an equation linking power and

potential difference, giving all SI units

A

power (W) = current (A) x p.d. (V)

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13
Q

Give an equation to work out power

without p.d., giving all SI units

A

power (W) = current² (A) x resistance (Ω)

P = I²R

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14
Q

Give an equation linking power and energy, giving all

SI units

A

power (W) = energy (J) ÷ time (s)

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15
Q

Give equations linking power and resistance, including all SI units

A

power (W) = current² (A) x resistance (Ω)

P = I² x R

power (W) = p.d.² (V) ÷ resistance (Ω)

P = V² ÷ R

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