Energetics II Flashcards
How does an ionic compound form
Metallic atoms transfer electrons to nonmetallic atoms to form positive and negative ions which attract to form a lattice
Melting point and boiling point of ionic substances?
High
Lots of energy to overcome strong electrostatic attraction between oppositely charged ions
Standard enthalpy change of formation definition
Enthalpy change when one mole of a compound is formed from its elements under standard conditions
Enthalpy of lattice formation (AKA lattice energy) definition
Enthalpy change when one mole of a solid ionic lattice is formed from its gaseous ions
Making bonds so exothermic so always NEGATIVE VALUE
Lattice energy is always…
And it is a measure of…
Negative
Ionic bond strength
General born-haber cycle to work out lattice energy if have to do calculation?
Gaseous ions -lattice enthalpy—> ionic solid (on top)
Elements (on bottom)
Arrow form elements up to gaseous ions - atomisation, ionisation, atomisation, electron affinity etc.
Arrow from elements to ionic solid - enthalpy of formation
Steps to convert elements to gaseous ions
1) Change elements in standard form to gaseous state (enthalpy of atomisation)
2) Change gaseous metal atoms to (positive) ions (ionisation energy)
3) Change gaseous non-metal atoms into (negative) ions (atomise first if diatomic then electron affinity)
Standard enthalpy of atomisation definition
Enthalpy change when one mole of gaseous atoms are produced from one mole of an element under standard conditions
Eg. 1/2Br2 (l) —-> Br- (g)
Always positive because have to supply energy to atomise
First electron affinity
XXXX
Enthalpy change for one mole of gaseous atoms
to gain one mole of electrons
to form one mole of gaseous ions with a 1- charge
Eg. X(g) + e- —-> X-(g)
——————
First electron affinity is exothermic for atoms that normally form negative ions WHY???
Second electron affinity
Enthalpy change when one mole of gaseous 1- ions
gains one electron per ion to produce
one mole of gaseous 2- ions
Eg. X-(g) + e- —-> X2- (g)
——————
Second electron affinity is ENDOTHERMIC because energy must be taken in to overcome repulsion between already negative ion and electron you are trying to add
Equation for lattice enthalpy
(energy change of elements to ionic solid aka enthalpy of formation) - (energy change the elements to gaseous ions)
Going round the cycle it’s negative gaseous ions to elements + enthalpy of formation of ionic solid from elements
How can we calculate the theoretical lattice enthalpy? And what do we assume?
Visualise perfectly spherical ions in a lattice
Calculate all forces of attraction and repulsion in the lattice
Assume perfect ionic model where ions are 100% ionic and spherical and attractions are purely electrostatic.
What kind of values are the values determined by the born-haber cycle?
Value is determined by experiment
Reflect the actual value
(We assumed perfect ionic model but if the experimental value is different we know this assumption was wrong and there is covalent character which is causes this difference)
What does a MORE -VE value of lattice enthalpy of FORMATION mean?
And LESS -VE value?
More negative value More exothermic More heat energy released Stronger bonds made Stronger lattice
Less negative value Less exothermic Less heat energy released Weaker bonds made Weaker lattice
What does a great a difference between the experimental and theoretical value of the born-haber cycle mean?
Greater degree of covalency in the lattice (and thus more polarisation)
Perfect ionic model
Ions are 100% ionic and spherical
Attractions are purely electrostatic
Polarised ionic bonding
Cation attract electrons
What does the extent of polarisation depend on?
How much
the cation pulls the electrons (polarising power)
The anion lets the electrons be pulled away (Polarisability)
Factors which increase polarisation in ionic compounds?
1) size of cation (smaller cation attracts e- more so more polarising)
2) size of anion (larger anion more polarisable)
3) increased charge of cation or anion
What type of polarisation would
K+F- have?
Low polarisation
K is a large cation
F is a small anion
low charge (both +/-1)
What type of polarisation would
Al3+ (I-)3 have?
High polarisation
Al3+ is a small cation (more polarising power)
(I-)3 is a large anion (more polarisable)
More +ve value of lattice DISSOCIATION enthalpy means
More +ve value of dissociation enthalpy More heat energy taken in More endothermic Stronger bonds had to be broken Stronger lattice
Less +ve = weaker lattice
High polarisability (Anion) High polarisation (cation)
LARGE ANION
SMALL CATION
What causes polarisation and what does a greater polarisation mean?
Covalency causes polarisation
Greater polarisation means more covalent character
Link difference in actual and theoretical values of lattice enthalpies , covalency and polarisation
Larger difference = higher covalency degree = more polarisation
What can the actual and theoretical values of lattice enthalpies be used to find?
Degree of polarisation
Why do some ionic compounds not dissolve in water?
Strong electrostatic attraction between oppositely charged ions is too large to be overcome by water molecules
Explain how water molecules interact with an ionic compound?
Delta positive hydrogen attracted to negative ions
Delta negative oxygen attracted to positive ions
Water molecules vibrate and shake ions free from lattice
What two things occur when ionic compounds dissolve in water?
1) Lattice broken apart (endothermic)
2) New bonds form between water molecules and ions (exothermic)
Enthalpy change of solution definition
ionic equation for dissolving ionic solid NaCl
Exothermic enthalpy change when one mole of ionic compound is dissolved in excess water and ions are well separated & don’t interact with each other
Ionic solid —> hydrated ions
NaCl(s) + (aq) —> Na+ (aq) + Cl- (aq)
Enthalpy of hydration definition
Exothermic enthalpy change when
one mole of gaseous ions dissolve in excess water
to form an infinitely dilute solution (such that further dilution causes no further heat change)
M+(g) + aq —-> M+(aq)
X+(g) + aq —-> X+ (aq)
M+(g) + X-(g) + aq —-> M+ (aq) + X-(aq)
—————
Always exothermic because bonds are MADE between ions and water molecules
Enthalpy of lattice dissociation
*opposite of lattice formation enthalpy
Enthalpy change to convert 1 mole of solid ionic lattice to
1 mole of its constituent gaseous ions
Breaking bonds so always a POSITIVE VALUE
How is lattice enthalpy formation connected to lattice enthalpy dissociation?
Lattice enthalpy dissociation is the OPPOSITE of lattice enthalpy formation
Lattice enthalpy of formation is exothermic eg. -200
Lattice enthalpy of dissociation is (-ve formation) so -(-200) so +200
Characteristics of a weak ionic lattice
Small cation
Large anion
High charges on ions
What happens to lattice energy as the size of the anion increases?
Anion size increase
Charge density decreases
Electrostatic attraction between oppositely charge ions decreases
Value of lattice energy decreases (aka. strength decreases)
What is charge density?
Charge per unit volume
What happens to lattice energy as the size of the cation increases?
Size of cation increases
Charge density decreases
Less electrostatic attractions
Lattice energy decreases
What happens to lattice energy as the charge on either the cation or anion increases?
Charge on ion increases
Charge density increases
Electrostatic attraction increases
Lattice energy increases
Define enthalpy of hydration
Enthalpy change when one mole of gaseous ions
become hydrated such that further dilution causes no further heat change
(Heat energy given out when they dissolve)
How does the size of the ion affect enthalpy of hydration?
Size of cation/anion increases Charge density of ion decreases Electrostatic attraction between water molecule and ion decreases Weaker bonds made Less energy given out Hydration enthalpy decreases
Charge density decreases
Hydration enthalpy decreases
What does a higher charge on ion mean for hydration enthalpy value?
Higher charge Higher charge density Electrostatic attraction between ions and water molecules increases Stronger bonds made More heat energy given out Larger hydration enthalpy value
Enthalpy of solution equation
Enthalpy of solution =
Lattice enthalpy of dissociation + lattice enthalpy of hydration
What is lattice enthalpy of dissociation equivalent to?
-ve lattice enthalpy of formation
Picture born-Haber cycle for NaCl
Top: gaseous ions Na+ (g) + Cl-(g)
Midway between: aqueous ions Na+(aq) + Cl-(aq)
Very bottom: ionic lattice NaCl(s)
1) gaseous ions to ionic lattice is LATTICE ENTHALPY OF FORMATION
2) gaseous ions to enthalpy of solution is ENTHALPY OF HYDRATION
3) ionic lattice to aqueous ions is ENTHALPY OF SOLUTION
Enthalpy of solution is turning what to what
Solid ionic lattice to aqueous ions