Acid - Base equilibria Flashcards
How to calculate H+ concentration and hence pH for a WEAK acid
- use the Ka equation (conc. products/ conc. reactants)
- then once you have the H+ from this, use -log[H+] = pH to calculate pH
Equation to calculate pH
-log[H+] = pH
Equation to calculate H+ concentration
10^-pH= H+
Definition of pH
-log[H+] = pH (this is the definition, don’t just say the concentration of H+ ions)
What is Brønsted–Lowry acid?
a proton donor
What is a Brønsted–Lowry base?
a proton acceptor
What do acid-base reactions involve the transfer of?
protons
Hydrogen ion concentration units
mol dm^3
How to identify Brønsted–Lowry conjugate acid-base pairs? Explain using this example.
H2O (l) + CO3 2- (aq) ⇄ OH- + HCO3 -
1) Identify the acid on the reactant side.
HELP: an acid is a proton donor so it will be the reactant that starts off with a proton (hydrogen). But then you need to look at the products to find that exact same species but without the hydrogen which the original reactant had now donated.
EXPLANATION: the acid is H2O because it is on the LHS and it contains a hydrogen which it donates meaning that on the RHS it then becomes just an OH- (because it has donated an electron)
2) identify the thing that pairs with the acid you just identified. This thing is called the conjugate base. (NOT conjugate acid. acid + base go together)
HELP: a base is a proton acceptor so you must find the species on the RHS * that, when you look at the backwards reaction, it now accepts a proton from the acid you just identified. So look for the species on the LHS which when you read from right to left, has a hydrogen added to it and becomes something else.
*(always the RHS because this is where you will find things that have formed after either losing/gaining a proton)
EXPLANATION: so we know the acid is H2O so we need to find its conjugate base on the RHS which, in the backwards reaction, accepts a proton from the H2O acid we identified earlier. So if you look, OH- , reading from left to right (backwards reaction) turns into H2O and is accepting a prton so OH- is the proton acceptor and hence the conjugate base
EASIER WAY TO DO STEP 2 BUT IT WOULD MEAN NOT UNDERSTANDING THE CONCEPT:
to identify the thing that pairs with the acid you just identified. (This thing is called the conjugate base) then just search for the exact same species (as the acid) on the RHS but with a hydrogen knocked off. So in this case, H2O, our acid, with a hydrogen knocked off is just OH- and thus this is the conjugate base.
3) Because the acid and base are always on the reactant side, the other species on that side is the opposite to the species next to it. So in this case, CO3 2- is the base.
The actual reason it is a base is because it is a proton acceptor; it turns to HCO3 - on the RHS having accepted a proton.
4) Then the conjugate acid is what the base on the reactant side turn into after a proton has been added. So in this case it turns into HCO3 - and therefore it is the conjugate acid.
what does a strong acid in terms of dissociation mean?
it has lots of H+ ions and fully dissociates into ions
what does a weak acid in terms of dissociation mean?
it has less H+ ions and only partially dissociates into its ions
-log is not the same as
reverse log
What does log(100) equal?
2
Why does only a weak acid, not a strong acid have an equilibrium arrow?
because it only PARTIALLY dissociates into ions
some ions will rejoin and ASSOCIATE again (hence a backwards reaction would be occurring)
What does what is the log of x (number quoted) mean?
It means what power do I need to raise ten to in order to get to the number I’m quoting (x)