Energetics Flashcards
all pages from energetics chemrevise except the experiment page
standard conditions
100 kPa and 298 K and standard states
Bond enthalpy
the amount of energy required to break one mole of the stated bond at gaseous state
Mean bond enthalpy
When does this definition only apply?
the enthalpy needed to break the covalent bond into gaseous atoms, averaged over different molecules
when the substances start and end in the gaseous state.
Standard enthalpy of reaction definition and symbol
🔺rH (circle with line through it meaning standard conditions)
Enthalpy change for the reaction to occur completely under standard conditions and at the molar quantities stated in the equation
Standard enthalpy of formation definition and symbol
🔺fH (circle with line through it meaning standard conditions)
Enthalpy formation of one mol of the product, made from its elements, with all substances under standard conditions. ONE MOLE OF THE PRODUCT IS FORMED
Standard enthalpy of combustion definition and symbol
🔺cH (circle with line through it meaning standard conditions)
Energy change when one mole of a substance is burnt completely in excess oxygen with all substances under standard conditions.
ONE MOLE OF SUBSTANCE IS COMPLETELY BURNT (reactant has to be one mole)
Enthalpy of neutralisation definition and symbol
🔺neutH (circle with line through it meaning standard conditions)
Enthalpy change when an acid is neutralised by an alkali to produce one mole of water under standard conditions.
What to remember about enthalpy of combustion and moles?
Energy change calculated during a combustion reaction will be according to however many moles you reacted so if they ask you for the enthalpy of combustion it won’t always be the value you got in your experiment as you have to make sure it’s the value obtained when burning one mole.
Therefore say you got enthalpy of 100Kj for 2 moles then the enthalpy of combustion would be 50Kj as that would be per one mole.
Bonds broken - bonds made is the same as…
Reactant bonds - product bonds
What are the four types of reaction and explain an enthalpy of reaction value?
Every reaction has a standard enthalpy of reaction value it’s just that their are different types of reaction such as formation, combustion and neutralisation. According to whatever type of reaction it is the enthalpy of reaction value will be the same. Eg. The standard enthalpy of reaction for Mg + O2 —> CO2 + H2O might be 500Kj however this is also a combustion reaction so the enthalpy of combustion is also 500Kj.
Why might the experiment bond enthalpy be different to the data book bond enthalpy?
The experiment bond enthalpy is enthalpy of the bond for a different state than to what is in the book
What is the state standard bond enthalpy quoted in data books?
Gas
Write an equation to represent the bond enthalpy of O—H in water?
H2O (g)—> HO(g)+ H(g)
Write an equation to represent the mean bond enthalpy of O—H in water?
H20 —> OH + H
OH —> O + H
Each of these have separate bond enthalpies you add them up and divide by 2.
H2O + OH —> OH + H + O + H
Cancel out OH on both sides
H2O—> 2H + O
Simplify
1/2H2O(g) —> H(g) + 1/2O(g)
Describe directions for measuring standard enthalpy of two substances when you put them in a beaker and stir them.
Pipette
Initial temp
Add other substance and stir
Measure final temp
State Hess’ Law
total enthalpy change for a reaction is independent of the route by which the chemical change takes place
If it gives you an enthalpy of formation value what does this suggest
eg. enthalpy of formation of C2H6 is 100kj mol
you need to write an equation at the TOP which is for enthalpy formation (so the product is the thing it has given the value for)
eg. so you would write 2C + 3H2 –> C2H6 with 100kj mol over the top
if it asks you to work out a bond energy using a hess cycle then what usually goes on the top and bottom
and which way do arrows point and why?
top: they usually give you an equation involving the species with the bond it is asking you to find an enthalpy of so use this equation on top
bottom: the singular gaseous atoms of the elements required to make the substance that has the bond it is asking you to find the enthalpy of
arrows point DOWNWARDS because you are breaking the bonds into their singular atoms to get the enthalpy
hess cycles what to always include
STATE SYMBOLS
If you are doing a hess cycle to work out a bond enthalpy and at the bottom are the single atoms which make up the thing that has the bond you are trying to find, what state should these singular atoms be in
GAS
What goes on top of a hess cycle
the equation you want to find!!!
if you are trying to find the enthalpy associated with one arrow which direction should you go
base of the arrow you want to its tip (sometimes means taking the longest version of this route)
bond enthalpy is always
POSITIVE
because it is always ENDOTHERMIC since breaking a bond requires energy absorption
If it gives you an equaton showing a molecular liquid going to an atomic gas what should you be aware of
somewhere in your calculations you need to factor in these two separate enthalpy changes (enthalpy of going from a liquid to a gas [breaking intermolecular forces] AND of going from a molecule to an atom [breaking intramolecular forces])
how do you set up the hess cycle if they give you enthalpy of formation but you are working out enthalpy of combustion
top: enthalpy of combustion (because that is what you want to work out)
bottom: elements
diagonal arrow from elements upwards