Energetics Flashcards
exothermic reaction
When heat energy released forming bonds in the products is greater than the energy required to break bonds in the reactant, energy is transferred to the surroundings so enthalpy change is negative
example of exothermic reaction (2)
combustion and displacement
use of exothermic reaction example
combustion of wood/ fossil fuels to heat homes
endothermic reaction
When the energy released when forming bonds in the products is less than the energy required to break the bonds in the reactants, energy is transferred from surroundings
example of endothermic reaction (2)
thermal decomposition and photosynthesis
use of endothermic reaction example
cold pack for sports injuries
catalyst definition
speeds up the rate of reaction without being chemically changed after the reaction so can be reused
how do catalysts work
provides an alternative pathway for the reaction with a lower activation energy so more particles have the activation energy and therefore a higher frequency of collisions are successful
activation energy
minimum amount of energy required to break bonds between the atoms of the reactants
ΔH
heat energy change measured under conditions of constant pressure
Standard enthalpy change of formation (ΔHfƟ)
when one mole of a compound is formed in its elements under standard conditions with all substances in their standard states
what is the enthalpy of formation of an element
0kj/mol
compare incomplete and complete combustion
Incomplete combustion is less exothermic than complete combustion
Standard enthalpy change of combustion (ΔHcƟ)
when one mole of an element or compound reacts completely with oxygen under standard conditions with all elements in their standard states
Calculating ΔH per mole in a reaction
Q=mc∆T
- m: mass of solution being heated cm3= g
- c: specific heat capacity 4.18J/g/K
- convert Q into ΔH in kJ by adding negative sign if exothermic and ÷1000
find the number of moles of reactant not in excess
- moles =cv
- moles = mass/Mr
ΔH for 1 mol
- ΔH/ moles (kJ/mol) 3sf
calorimetry practical errors (4)
heat loss to surroundings
assuming all solutions have heat capacity of water
ignoring heat absorbing apparatus
incomplete/ slow reaction
Hess’s law
the total enthalpy change for a chemical reaction is independent of the route by which the reaction takes place, provided the initial and final conditions are the same
why is hess’s law used
Used due to difficulties in measuring temperature change (solid)
enthalpy of formation equation
ΔH reaction = ΣfH products - ΣfH reactants
enthalpy of combustion equation
ΔH reaction = ΣΔcH reactants - ΣΔcH products
mean bond energy
enthalpy needed to break the covalent bonds into gaseous atoms averaged over different molecules
enthalpy using bond enthalpy data
ΔH = Σ bond energies broken - Σ bond energies formed
which is more accurate and why: using mean bond enthalpy values or Hess’s law
Average bond enthalpy values are averaged values from various compounds so less accurate than value using Hess’s law
relationship between number of carbon atoms and size of enthalpies of combustion in a homologous series
Why tho?
as number of carbon atoms increases, size of enthalpies of combustion increases (directly proportional) so more exothermic
Able to form more CO2 and H2O molecules which energy released is greater than the energy required to break extra bonds of the reactants from increased size