Electrode Potentials Flashcards

1
Q

If it is more reactive where with it go

A

To the anode
The more negative the E value is the more reactive, so more easily it goes under oxidation, so it gives up its electrons
AO let’s go
Anode is oxidisation

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2
Q

More positive E value will go to anode/cathode?

A

Cathode
More positive E value the more it gains electrons, so the more reductive.
CR
Christiano Renaldo
Cathode is reduction

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3
Q

Calculate emf value

A

Right - left
More positive - more negative

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4
Q

Units of emf value

A

Volts

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5
Q

What is the salt bridge for

A

Allows ions to move across

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6
Q

Standard condition of Electrochemical cell

A

Conc - 1 mol dm-3 but be careful if H2SO4 used as this needs 0.5 mol em-3 as there are 2H+ this equals to 1 Mol dm-3
Temp - 298K
Pressure - 100kPa

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7
Q

Why is Hydrogen 0V

A

By definition

Everything is relative to hydrogen

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8
Q

Why is Pt used sometimes

A

Inert metal that can conduct electricity for electrons to move
I think usually used when reactions only contain aqueous substances - double check

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9
Q

Electrode potential equation

A

R O || O R
Only compounds going through redox is put into this
Solid, aqueous || aqueous, solid
Left - anode
Right - cathode
This is because you have to lose electrons before you gain electrons so oxidation comes before reduction

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10
Q

How does changing the concentration of Zn2+ affect E value
Zn2+ + 2e- <—-> Zn
-0.76V

A

Increasing Zn2+ will shift equilibrium to the right towards Zn
This will increase the Zn E value making it less negative so the overall E value will decrease (between Zn and another ion)
- _________+
-0.76 —— -0.50 - this makes Zn E value less negative

Looking at Zn and another ion eg Cu which has E value +0.34V
Original E value = 0.34 + 0.76 = 1.1V
New E value = 0.34 + 0.50 = 0.84V so overall E value decreases.

Vice versa
Increase Zn equilibrium shifts to the left towards Zn2+
Makes Zn E value more negative to overall E value will Increase.

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11
Q

Which is at the anode/cathode
What is the emf value
What is the sentence used at the end of this
Reduction equations:
Zn2+ + 2e- <—-> Zn / E value = -0.76V
Cu2+ + 2e- <—-> Cu / E value = +0.34V

A
  1. Anode
    - Zn <—> Zn2+ + 2e- the equation flips as oxidation occurs here AO

Cathode
- Cu2+ +2e- <—> Cu the equation remains as reduction occurs here CR

  1. emf = 1.1V
  2. E value (Cu2+/Cu) > E value (Zn2+/Zn) so Cu2+ gains electrons from Zn
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12
Q

Different type of cells

A
  1. Non-rechargeable
  2. Rechargeable
  3. Fuel cells
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13
Q

Lithium cell equation

A
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14
Q

What type of cell is a lithium cell

A

Rechargeable

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15
Q

Fuel cells: Hydrogen-Oxygen fuel cell
The equations involved

A
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16
Q

Pros and cons of cells

A