Electrochemistry Flashcards
Define a redox reaction.
A chemical reaction where the oxidation states of the atoms change that there is an oxidation and a reduction.
Describe a basic hydrogen fuel cell.
There are 2 platinum electrodes connected by wire. H2 gas is fed into one side at the anode where oxidation occurs to form 2H+, the electrons from the reaction pass to the other electrode where O2 is fed in which is reduced in the presence of H+ ions to form water. The chemical energy can be thought to be converted into electrical energy by the current flowing though the wire.
Define the anode, cathode and the cell potential.
The anode is where the oxidation occurs (a⇒o vowels), the cathode is where the reduction occurs (c⇒r constanents).
The cell potential, Ecell, is defined as Ecathode - Eanode and must be positive for a spontaneous reaction. Represent this graphically.
Give the key equations for Gibbs free energy.
ΔGcell = -nFEcell where n is the number of electrons transferred, F is the Faraday constant and Ecell is the charge potential.
ΔG = -RTlnK where K is the equlibrium constant.
Define standard electrode potentials.
The measure of the individual potential of a reversible electrode under standard conditions which are: stated temp. usually 298 K, unit activity (simplified to 1 M for soluble species), partial pressur eof 1 bar for each gas and metals in their pure state.
Standard electrode potentials are defined relative to a standard hydrogen electrode which is assigned the E° value of 0 V.
Explain how to write out a cell diagram and give an example for the reactio between a Zn and Cu battery where Cu2+ is reduced to Cu(s) and the opposite happens for zinc.
- The anode is described first, then the cathode, with the reactants specified first and the products after.
- A single vertical line seperates species in contact but in a different phase, a double vertical line represents a salt bridge seperating the cells.
- The chemical phase is shown in parentheses as are any conditions that are non-standard.
Zn(s) | Zn2+(aq) || Cu2+(aq) | Cu(s)
Describe a Latimer diagram.
How can you calculate the cell potential for two of the states?
For one element the oxidation forms are drawn out with the most oxidised species on the left and the most reduced on the right. The states are connected by arrows from left to right that have labelled the numerical value of the standard potential for that reduction.
The standard electrode potentials cannot be added, only the ΔG values can be added. The ΔG values can be worked out by -nFE, so the difference between states is multiplied by the number of electrons in the transition and the Faraday constant. Then the standard electrode potential for the system can be worked out by ΔG/-nF where n is the number of electrons transferred between the states.
Describe a Frost diagram and the information that can be gained from it.
A Frost diagram is a plot of oxidation state on the X, and the nE value for converting the state to the zero oxidation state on the Y, where n is the number of electrons transferred. The zero oxidation state will always be the origin.
The Y axis is proportional to ΔG to convert to the elemental form, it represents the relative stability of the oxidation state. The lower the state is, the more stable it is, the zero ox. state is often not the most stable.
The gradient connecting two points is the potential for the reaction, E. Any species that lies above the points either side of it can undergo disproportionation to form both the states. If the gradient is above a point, then the two states around it may conproportionate into that one state.
How are Frost diagrams worked out from Latimer diagrams?
Construct a table with the columns: species, oxidation state, reduction potential to the next state (on the Latimer diagram) x number of electrons transferred, nE for converting from oxidation state to the zero state (adding the stepwise potentials down to zero together).
Give the Nernst equation. What is it used for?
E = Eº - (RT/nF)lnQ
E is the potential under non-standard conditions, Eº is the standard potential and Q is the reaction quotient which is the products of the activities of the products/the activities of the reactants (with each to the power of their empirical ratio).
Activity of a pure solid/liquid/gas = 1, aqueous liquid = concentration, gas = partial pressure.
This is used to adjust a potential to non-standard conditions.
How can the Nernst equation be used with a m-proton, n-electron, reversible process?
Defining the reaction as, X + ne- + mH+ ⇔ XHm(m-n)+
The Nernst equation can be substituted with [H+] = 10-pH, the terms seperated, and differentiated to find dE/dpH = - (mRT/nF) ln10
This gives the change in electrode potentials with the change in pH. Such as for a m = 1, n = 1, process, the electrode potential will change with pH by -59 mV pH-1 at 298 K.
How do Frost and Latimer diagrams change when the pH changes?
Using the equation, dE/dpH = - (mRT/nF) ln10, any process which includes a change in protons will depend on pH and temperature. This can drastically change the potentials ofa reaction.
What is a Pourbaix diagram?
A plot of electrode potential on the Y and pH on the X, mapping out the stable phases at certain conditions and are often overlapped with water.
At some reducing potentials, protons will form H2, at some oxidising potentials, H2O will form O2 and 2H+. Both are m=n processes to change by -59 mV per pH unit.
A similar graph can be drawn but with mole fraction of each oxidation state of an element. The fraction will increase when the pH favours its reaction.
Describe how to construct a Pourbaix diagram for the reduction of Zn2+ to Zn across a range of pH.
Establish the reactions that occur at the different pH values. At low pH, Zn2+ will be in that state in the solution. At pH 9 to 11, Zn(OH)2 will form and at pH 11 to 12, Zn(OH)3- will form.
All these states have different reduction reactions. The potential of Zn2+ will not be affected by pH as there are no protons, so up to pH 9, there will be a flat line between the states. Between pH 9 to 11, there is a m=n reaction giving the line a -59 mV pH-1 gradient and between 11 and 12 there is a 3H, 2e process so the line will be slightly steeper.
Lines are drawn between each state, as the pH changes and the potential where the reduction occurs.
How can you predict reactions that will occur from the Pourbaix diagram? What does the Pourbaix diagram assume?
When overlaid with another species, like water, the reactions can be visualised. A metal with a zero oxidation state below the H2 line on water shows that in water, the metal will react to form H2. The Ecell for the reaction is the difference between the metal phase line and the H2 phase line.
The diagram assumes no activation energy.