Electrochemistry

Question 1

(Conversion Factors) Faraday to Coulomb

Answer 1

96500 C / 1 F

Question 2

(Conversion Factors) Coulombs to Moles of Electrons

Answer 2

96500 C / 1 mol e⁻

Question 3

(Conversion Factors) Equation for Current

Answer 3

I = q/T

xA = yC / 1s

I = current (measured in amperes or amps, A)
q = charge (measured in Coulombs, C)
T = time (measured in seconds)

x and y are coefficients

Question 4

(Conversion Factors) Electron to Coulombs

Answer 4

• 1e⁻ = -1.60*10^(-19) C

* 6.25*10^18 e⁻ contain -1 C of charge

Question 5

(Trends and Misc.) E°cell Equations

Answer 5

1. E°cell = E°red.(cathode) - E°red.(anode)

2. E°cell = E°red. + E°ox.

Question 6

(Trends and Misc.) Gibbs Free Energy (ΔG°) and E°

Answer 6

As ΔG° becomes more negative, E° becomes more positive and vice versa.

Question 7

(Trends and Misc.) Le Chatelier’s Principle and Electrochemistry

Answer 7

1. Increase [R] = Increase ΔV = Increase I = Increase rate of forward reaction.
2. Decrease [R] = Decrease ΔV = Decrease I = Decrease rate of forward reaction.
3. Increase [P] = Decrease ΔV = Decrease I = Decrease rate of forward reaction.
4. Decrease [P] = Increase ΔV = Increase I = Increase rate of forward reaction.