dna genes and protein synthesis Flashcards

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1
Q

define genome

A

as the complete set of genes in a cell

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2
Q

define proteome

A

as the full range of proteins that a cell is able to produce.

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3
Q

describe how a gene is a code for the production of a polypeptide

A
  1. (Because) base/nucleotide sequence;
  2. (In) triplet(s);
  3. (Determines) order/sequence of amino acid sequence/primary
    structure (in polypeptide);
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4
Q

define the term exon

A

/triplet sequence coding for polypeptide

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5
Q

an intron is a non coding sequence of dna, where is it positioned in the genome

A

positioned between genes

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6
Q

differences between dna in nucleus of plant cell and dna in prokaryotic cell

A
  1. (Associated with) histones/proteins v no histones/proteins;
  2. Linear v circular;
  3. No plasmids v plasmids;
    4, Introns v no introns;
  4. Long(er) v short(er);
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7
Q

not all mutations in nucleotide sequence of a gene cause change in structure of polypeptide. why?

A

Triplets code for same amino acid
Occurs in introns /non-coding sequence;

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8
Q

compare and contrast dna in pro vs eu cells

A

compare:
Nucleotide structure is identical;
Nucleotides joined by phosphodiester bond;
DNA in mitochondria / chloroplasts same / similar (structure) to DNA
in prokaryotes;
contrast:
Eukaryotic DNA is longer;
5. Eukaryotic DNA contain introns, prokaryotic DNA does not;
6. Eukaryotic DNA is linear, prokaryotic DNA is circular;
7. Eukaryotic DNA is associated with / bound to protein / histones,
prokaryotic DNA is not;

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9
Q

what is a homologous pair of chromosomes

A

(Two chromosomes that) carry the same genes;

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10
Q

explain how number of chromosones is halved during meiosis

A
  1. Homologous chromosomes (pair);
  2. One of each (pair) goes to each (daughter)
    cell / to opposite poles;
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11
Q

crossing over increases genetic diveristy explain how

A
  1. Homologous pairs of chromosomes associate
    / form a bivalent;
  2. Chiasma(ta) form;
  3. (Equal) lengths of (non-sister) chromatids /
    alleles are exchanged;
  4. Producing new combinations of alleles;
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12
Q

Explain the meaning of
Degenerate
Non overlapping

A

Degenerate : more than one base triplet can code for the same amino acid
Non overlapping: each base is part of only one triplet

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13
Q

mRNA is used during translation to form polypeptides.
Describe how mRNA is produced in the nucleus of a cell.

A
  1. Helicase;
  2. Breaks hydrogen bonds;
  3. Only one DNA strand acts as template;
  4. RNA nucleotides attracted to exposed bases;
  5. (Attraction) according to base pairing rule;
  6. RNA polymerase joins (RNA) nucleotides together;
  7. Pre-mRNA spliced to remove introns.
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14
Q

Contrast the structures of mRNA and DNA

A
  1. DNA double
    stranded/double helix and mRNA single-stranded;
    Contrast requires both parts of the statement
  2. DNA (very) long and RNA short;
    Accept ‛RNA shorter’ or ‛DNA bigger/longer’
  3. Thymine/T in DNA and uracil/U in RNA;
  4. Deoxyribose in DNA and ribose in RNA;
    R Deoxyribonucleic/ ribonucleic acid
    Ignore ref. to histones
    Ignore ref. to helix and straight chain alone
  5. DNA has base pairing and mRNA doesn’t/ DNA has hydrogen
    bonding and mRNA doesn’t;
  6. DNA has introns/non-coding sequences and mRNA doesn’t;
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15
Q

Single base deletion can lead to a non func protein
Why

A

Mutation) changes triplets / codons after that point / causes frame shift;
Accept changes splicing site
Ignore changes in sequence of nucleotides / bases
2. Changes amino acid sequence (after this) / codes for different amino
acids (after this);
Accept changes primary structure
Reject changes amino acid formed / one amino acid changed
3. Affects hydrogen / ionic / sulfur bond (not peptide bond);
4. Changes tertiary structure of protein (so non-functional);

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16
Q

Mutation in intron causes whag

A

Intron non- coding (DNA) / only exons coding;
Context is the intron
Do not mix and match from alternatives
Neutral references to introns removed during splicing
1. and 2. Ignore ref. to code degenerate and get same / different
amino acid in sequence
2. (So) not translated / no change in mRNA produced / no effect (on protein)
/ no effect on amino acid sequence;
Accept does not code for amino acids
OR
3. Prevents / changes splicing;
4. (So) faulty mRNA formed;
Accept exons not joined together / introns not removed
5. Get different amino acid sequence;

17
Q

Explain how the structure of DNA is related to its function

A

Sugar-phosphate (backbone) / double stranded / helix so provides strength / stability
/ protects bases / protects hydrogen bonds;
Must be a direct link / obvious to get the mark
Neutral: reference to histones
2. Long / large molecule so can store lots of information;
3. Helix / coiled so compact;
Accept: can store in a small amount of space for ‘compact’
4. Base sequence allows information to be stored / base sequence codes for
amino acids / protein;
Accept: base sequence allows transcription
5. Double stranded so replication can occur semi-conservatively / strands can act
as templates / complementary base pairing / A-T and G-C so accurate
replication / identical copies can be made;
6. (Weak) hydrogen bonds for replication / unzipping / strand separation / many
hydrogen bonds so stable / strong;
Accept: ‘H-bonds’ for ‘hydrogen bonds’

18
Q

differences in primary structure in haemoglobin molecules can provide evidence of phylogenic (evolutionary relationships between species
explain how (5)

A
  1. Mutations change base / nucleotide (sequence);
    Reject if mutation in amino acid
  2. (Causing) change in amino acid sequence;
  3. Mutations build up over time;
  4. More mutations / more differences (in amino acid / base / nucleotide sequence / primary structure) between distantly related species;
    OR
    Few(er) mutations / differences (in amino acid / base / nucleotide sequence / primary structure) in closely related species;
  5. Distantly related species have earlier common ancestor;
    OR
    Closely related species have recent common ancestor;
    Accept “order” for “sequence”
19
Q

compare and contrast DNA structure (5)

A

Comparisons
1. Nucleotide structure is identical;
Accept labelled diagram or description of nucleotide as phosphate, deoxyribose and base
2. Nucleotides joined by phosphodiester bond;
OR
Deoxyribose joined to phosphate (in sugar, phosphate backbone);
3. DNA in mitochondria / chloroplasts same / similar (structure) to DNA in prokaryotes;
Accept shorter than nuclear DNA/is circular not linear/is not associated with protein/histones unlike nuclear DNA;
Contrasts
4. Eukaryotic DNA is longer;
5. Eukaryotic DNA contain introns, prokaryotic DNA does not;
6. Eukaryotic DNA is linear, prokaryotic DNA is circular;
7. Eukaryotic DNA is associated with / bound to protein / histones, prokaryotic DNA is not;

20
Q

describe the role of a ribosome in the production of polypeptide

A
  1. mRNA binds to ribosome;
  2. Idea of two codons / binding sites;
  3. (Allows) tRNA with anticodons to bind / associate;
  4. (Catalyses) formation of peptide bond between amino acids (held by tRNA molecules);
  5. Moves along (mRNA to the next codon)
21
Q
A